Board Boosters

The questions your board exam loves to ask

800 most-asked Class 11 & 12 (+1 / +2) questions across Physics, Chemistry, Maths and Biology — each with a model answer and the exact marking-scheme points examiners reward. Revise smart, walk in calm.

800 board questions•Model answers•Marking-scheme points•Every chapter•CBSE · ISC · State boards

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MathsClass 122 markseasy

Determinants

What is a singular and a non-singular matrix? State the condition for a matrix to be invertible.

Reveal model answer + marking points▾

A square matrix A is called singular if its determinant is zero (|A| = 0), and non-singular if its determinant is non-zero (|A| is not equal to 0). The condition for a square matrix to be invertible (to have an inverse) is that it must be non-singular, that is, |A| must not be zero, because the inverse A inverse = (1/|A|) adj A is defined only when |A| is not zero.

A inverse exists if and only if |A| is not 0

Marking-scheme points

  • ✓Singular: |A| = 0; non-singular: |A| not equal to 0
  • ✓A matrix is invertible only if it is non-singular
  • ✓Because A inverse = (1/|A|) adj A needs |A| not zero
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MathsClass 122 marksmedium

Determinants

If A is a 3 x 3 matrix with |A| = 5, find the values of |adj A| and |2A|.

Reveal model answer + marking points▾

For an n x n matrix, |adj A| = |A|^(n - 1). Here n = 3, so |adj A| = |A|^2 = 5^2 = 25. Also, for a scalar k, |kA| = k^n |A|. Here |2A| = 2^3 x |A| = 8 x 5 = 40. So |adj A| = 25 and |2A| = 40.

|adj A| = |A|^(n-1); |kA| = k^n |A|

Marking-scheme points

  • ✓|adj A| = |A|^(n-1) = 5^2 = 25
  • ✓|kA| = k^n |A|
  • ✓|2A| = 2^3 x 5 = 40
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MathsClass 122 markseasy

Continuity and Differentiability

State the conditions for a function f(x) to be continuous at a point x = a.

Reveal model answer + marking points▾

A function f(x) is continuous at a point x = a if the following three conditions are all satisfied: (1) f(a) is defined (the function has a value at a); (2) the limit of f(x) as x approaches a exists (that is, the left-hand limit equals the right-hand limit); and (3) this limit is equal to the value of the function, that is, limit of f(x) as x approaches a = f(a).

limit(x->a) f(x) = f(a)

Marking-scheme points

  • ✓f(a) must be defined
  • ✓The limit as x approaches a must exist (LHL = RHL)
  • ✓The limit must equal f(a)
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