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800 most-asked Class 11 & 12 (+1 / +2) questions across Physics, Chemistry, Maths and Biology — each with a model answer and the exact marking-scheme points examiners reward. Revise smart, walk in calm.

800 board questions•Model answers•Marking-scheme points•Every chapter•CBSE · ISC · State boards

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ChemistryClass 112 marksmedium

Equilibrium

State Le Chatelier's principle. What is the effect of increasing pressure on the equilibrium N2(g) + 3H2(g) <=> 2NH3(g)?

Reveal model answer + marking points▾

Le Chatelier's principle states that if a system at equilibrium is subjected to a change in concentration, pressure or temperature, the equilibrium shifts in the direction that tends to counteract (reduce) the effect of that change. Increasing the pressure shifts this equilibrium in the forward direction (towards NH3), because the forward reaction reduces the number of gas moles from 4 (1 + 3) to 2, thereby lowering the pressure.

Marking-scheme points

  • ✓System shifts to oppose the imposed change
  • ✓Higher pressure favours the side with fewer gas moles
  • ✓Here forward reaction (4 -> 2 moles) is favoured -> more NH3
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ChemistryClass 112 markseasy

Equilibrium

Define an acid and a base according to the Bronsted-Lowry concept. What is a conjugate acid-base pair?

Reveal model answer + marking points▾

According to the Bronsted-Lowry concept, an acid is a substance that donates a proton (H+) and a base is a substance that accepts a proton. A conjugate acid-base pair is a pair of species that differ by a single proton; for example, in HCl + H2O -> H3O+ + Cl-, HCl/Cl- and H2O/H3O+ are conjugate acid-base pairs.

acid <=> base + H+

Marking-scheme points

  • ✓Bronsted acid = proton donor; base = proton acceptor
  • ✓Conjugate pair differs by one proton (H+)
  • ✓Example: HCl/Cl- and H2O/H3O+
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ChemistryClass 112 markseasy

Equilibrium

Calculate the pH of a 0.001 M HCl solution.

Reveal model answer + marking points▾

HCl is a strong acid and dissociates completely, so [H+] = 0.001 M = 1 x 10^-3 M. pH = -log[H+] = -log(10^-3) = 3. The solution is acidic (pH < 7).

pH = -log[H+]

Marking-scheme points

  • ✓Strong acid: [H+] = 10^-3 M
  • ✓pH = -log[H+]
  • ✓pH = 3 (acidic)
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