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The questions your board exam loves to ask

800 most-asked Class 11 & 12 (+1 / +2) questions across Physics, Chemistry, Maths and Biology — each with a model answer and the exact marking-scheme points examiners reward. Revise smart, walk in calm.

800 board questions•Model answers•Marking-scheme points•Every chapter•CBSE · ISC · State boards

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MathsClass 122 marksmedium

Differential Equations

Find the order and degree of the differential equation (d2y/dx2)^3 + (dy/dx) + y = 0.

Reveal model answer + marking points▾

The highest order derivative present in the equation is d2y/dx2 (the second derivative), so the order of the differential equation is 2. The power (exponent) of this highest order derivative is 3, and the equation is a polynomial in the derivatives, so the degree is 3. Hence the order is 2 and the degree is 3.

Marking-scheme points

  • ✓Highest derivative is d2y/dx2 -> order 2
  • ✓Its power is 3 -> degree 3
  • ✓Order = 2, degree = 3
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MathsClass 122 markseasy

Differential Equations

Distinguish between the general solution and a particular solution of a differential equation.

Reveal model answer + marking points▾

The general solution of a differential equation is the solution that contains as many arbitrary constants as the order of the differential equation; it represents a whole family of curves. A particular solution is obtained from the general solution by giving definite values to these arbitrary constants using given initial or boundary conditions; it represents one specific member of the family.

Marking-scheme points

  • ✓General solution: contains arbitrary constants (= order of the equation)
  • ✓Represents a family of curves
  • ✓Particular solution: constants fixed using given conditions
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MathsClass 122 marksmedium

Differential Equations

What is a homogeneous differential equation? What substitution is used to solve it?

Reveal model answer + marking points▾

A differential equation of the form dy/dx = f(x, y) is called homogeneous if the function f(x, y) can be written as a function of the ratio y/x only (that is, f depends on x and y only through y/x). To solve it, we use the substitution y = v x (so v = y/x), which gives dy/dx = v + x (dv/dx). This substitution reduces the equation to a variable separable form in v and x, which can then be integrated.

y = v x, dy/dx = v + x(dv/dx)

Marking-scheme points

  • ✓Homogeneous: dy/dx can be written as a function of y/x
  • ✓Substitute y = v x, so dy/dx = v + x(dv/dx)
  • ✓Reduces to a variable separable equation
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