Board Boosters

The questions your board exam loves to ask

800 most-asked Class 11 & 12 (+1 / +2) questions across Physics, Chemistry, Maths and Biology — each with a model answer and the exact marking-scheme points examiners reward. Revise smart, walk in calm.

800 board questions•Model answers•Marking-scheme points•Every chapter•CBSE · ISC · State boards

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PhysicsClass 113 marksmedium

Gravitation

A satellite revolves in a circular orbit very close to the Earth's surface. Find its orbital speed. Take g = 9.8 m/s^2 and R = 6.4 x 10^6 m.

Reveal model answer + marking points▾

For an orbit close to the surface the required centripetal force is provided by gravity, so v_o = sqrt(g R) = sqrt(9.8 * 6.4 x 10^6) = sqrt(6.272 x 10^7) = 7.92 x 10^3 m/s = 7.92 km/s (approximately 8 km/s).

v_o = sqrt(g R)

Marking-scheme points

  • ✓v_o = sqrt(g R) for a near-surface orbit
  • ✓Substitute g and R
  • ✓v_o ~ 7.9 km/s
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PhysicsClass 113 marksmedium

Gravitation

Show that the escape velocity from the Earth's surface is sqrt(2) times the orbital velocity of a satellite orbiting close to the surface.

Reveal model answer + marking points▾

Orbital velocity near the surface: v_o = sqrt(g R). Escape velocity: v_e = sqrt(2 g R). Dividing, v_e / v_o = sqrt(2 g R) / sqrt(g R) = sqrt(2). Hence v_e = sqrt(2) * v_o (about 1.41 times).

v_e = sqrt(2) * v_o

Marking-scheme points

  • ✓v_o = sqrt(gR), v_e = sqrt(2gR)
  • ✓Ratio v_e/v_o = sqrt(2)
  • ✓v_e = 1.41 v_o
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PhysicsClass 113 marksmedium

Mechanical Properties of Solids

A wire of length 2 m and cross-sectional area 1 mm^2 stretches by 1 mm when a load of 10 N is applied. Calculate Young's modulus of the material.

Reveal model answer + marking points▾

Y = (F L) / (A * delta L). Here F = 10 N, L = 2 m, A = 1 mm^2 = 1 x 10^-6 m^2, delta L = 1 mm = 1 x 10^-3 m. Y = (10 * 2) / (1 x 10^-6 * 1 x 10^-3) = 20 / (1 x 10^-9) = 2 x 10^10 N/m^2.

Y = (F L) / (A * delta L)

Marking-scheme points

  • ✓Y = F L / (A delta L)
  • ✓Convert mm^2 and mm to SI
  • ✓Y = 2 x 10^10 N/m^2
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