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The questions your board exam loves to ask

800 most-asked Class 11 & 12 (+1 / +2) questions across Physics, Chemistry, Maths and Biology — each with a model answer and the exact marking-scheme points examiners reward. Revise smart, walk in calm.

800 board questions•Model answers•Marking-scheme points•Every chapter•CBSE · ISC · State boards

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ChemistryClass 113 marksmedium

Classification of Elements and Periodicity

What are s-, p-, d- and f-block elements? Why are d-block elements called transition elements?

Reveal model answer + marking points▾

Elements are classified by the subshell into which the last (differentiating) electron enters: s-block (last electron in s), p-block (in p), d-block (in d) and f-block (in f). d-block elements are called transition elements because they lie between the s-block (metals) and p-block (non-metals) and show a gradual transition in properties; their atoms or common ions have partially filled d orbitals.

Marking-scheme points

  • ✓Block = subshell receiving the last electron (s, p, d, f)
  • ✓d-block lies between s- and p-blocks
  • ✓Transition: atoms/ions have partially filled d orbitals
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ChemistryClass 113 marksmedium

Chemical Bonding and Molecular Structure

Using VSEPR theory, predict the shapes and bond angles of BF3, NH3 and H2O.

Reveal model answer + marking points▾

BF3: central B has 3 bond pairs and no lone pair -> trigonal planar, bond angle 120 deg. NH3: central N has 3 bond pairs and 1 lone pair -> pyramidal (trigonal pyramidal), bond angle about 107 deg. H2O: central O has 2 bond pairs and 2 lone pairs -> bent/angular, bond angle about 104.5 deg. Lone pairs repel more than bond pairs, reducing the angle from the ideal 109.5 deg in NH3 and H2O.

Marking-scheme points

  • ✓BF3: 3 bp, 0 lp -> trigonal planar, 120 deg
  • ✓NH3: 3 bp, 1 lp -> pyramidal, 107 deg
  • ✓H2O: 2 bp, 2 lp -> bent, 104.5 deg
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ChemistryClass 113 marksmedium

Chemical Bonding and Molecular Structure

Describe the hybridization, shape and bonding in an ethyne (C2H2) molecule.

Reveal model answer + marking points▾

In ethyne each carbon is sp hybridised. The two sp hybrid orbitals on each carbon form sigma bonds: one C-C sigma bond and one C-H sigma bond, giving a linear molecule with a bond angle of 180 deg. The remaining two unhybridised p orbitals on each carbon overlap sideways to form two pi bonds, so there is a triple bond (1 sigma + 2 pi) between the carbon atoms.

H-C(triple bond)C-H

Marking-scheme points

  • ✓Each C is sp hybridised, molecule linear (180 deg)
  • ✓sp orbitals form C-C and C-H sigma bonds
  • ✓Two unhybridised p orbitals form 2 pi bonds (triple bond = 1 sigma + 2 pi)
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