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800 most-asked Class 11 & 12 (+1 / +2) questions across Physics, Chemistry, Maths and Biology — each with a model answer and the exact marking-scheme points examiners reward. Revise smart, walk in calm.

800 board questions•Model answers•Marking-scheme points•Every chapter•CBSE · ISC · State boards

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ChemistryClass 113 marksmedium

Hydrogen

What is hard water? Distinguish between temporary and permanent hardness and give one method to remove each.

Reveal model answer + marking points▾

Hard water is water that does not give lather easily with soap because it contains dissolved calcium and magnesium salts. Temporary hardness is due to bicarbonates of Ca and Mg (Ca(HCO3)2, Mg(HCO3)2) and can be removed by boiling or by Clark's method (adding calculated slaked lime). Permanent hardness is due to chlorides and sulphates of Ca and Mg and is removed by adding washing soda (Na2CO3) or by the ion-exchange (permutit/resin) method.

Marking-scheme points

  • ✓Hard water: contains Ca2+ and Mg2+ salts, no lather with soap
  • ✓Temporary: bicarbonates -> removed by boiling / Clark's method
  • ✓Permanent: chlorides and sulphates -> removed by washing soda / ion exchange
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ChemistryClass 113 marksmedium

The s-Block Elements

Describe the trend in solubility of the hydroxides and sulphates of alkaline earth metals down the group. Give the flame colours of Ca, Sr and Ba.

Reveal model answer + marking points▾

Solubility of hydroxides increases down the group (Mg(OH)2 is sparingly soluble while Ba(OH)2 is fairly soluble) because lattice energy decreases faster than hydration energy. Solubility of sulphates decreases down the group (MgSO4 is soluble but BaSO4 is almost insoluble) because hydration energy decreases faster for the larger ions. Flame colours: calcium gives brick-red, strontium gives crimson-red and barium gives apple-green.

Marking-scheme points

  • ✓Hydroxide solubility increases down group (lattice energy falls faster)
  • ✓Sulphate solubility decreases down group (hydration energy falls faster)
  • ✓Flame: Ca brick-red, Sr crimson, Ba apple-green
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ChemistryClass 113 markshard

The p-Block Elements

Describe the structure and bonding in diborane (B2H6).

Reveal model answer + marking points▾

Diborane (B2H6) has two boron atoms and six hydrogen atoms. Four hydrogen atoms (two on each boron) are terminal and are bonded by normal two-centre two-electron (2c-2e) B-H bonds. The remaining two hydrogen atoms are bridging: each forms a three-centre two-electron (3c-2e) B-H-B bond, often called a banana bond. Each boron is sp3 hybridised. The molecule is electron-deficient because it does not have enough valence electrons for normal two-electron bonds throughout.

B2H6 (2 bridging + 4 terminal H)

Marking-scheme points

  • ✓4 terminal B-H bonds (normal 2c-2e bonds)
  • ✓2 bridging B-H-B bonds are 3c-2e (banana) bonds
  • ✓Boron is sp3; molecule is electron-deficient
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