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800 most-asked Class 11 & 12 (+1 / +2) questions across Physics, Chemistry, Maths and Biology — each with a model answer and the exact marking-scheme points examiners reward. Revise smart, walk in calm.

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ChemistryClass 123 marksmedium

Aldehydes, Ketones and Carboxylic Acids

Why are carboxylic acids more acidic than phenols? How do electron-withdrawing groups affect their acidity?

Reveal model answer + marking points▾

Carboxylic acids are more acidic than phenols because the carboxylate ion formed after the loss of the proton is stabilised by resonance in which the negative charge is spread equally over two electronegative oxygen atoms, making it very stable. In the phenoxide ion the negative charge is mainly on one oxygen and partly on less electronegative ring carbons, so it is less stabilised. Electron-withdrawing groups (like -Cl or -NO2) increase acidity because they further disperse and stabilise the negative charge of the carboxylate ion (for example, chloroacetic acid is stronger than acetic acid), while electron-releasing groups decrease acidity.

Marking-scheme points

  • ✓Carboxylate ion: charge spread equally over two oxygen atoms (very stable)
  • ✓Phenoxide ion is less stabilised
  • ✓Electron-withdrawing groups increase acidity; electron-releasing groups decrease it
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ChemistryClass 122 marksmedium

Aldehydes, Ketones and Carboxylic Acids

Write the esterification reaction of a carboxylic acid and the decarboxylation reaction.

Reveal model answer + marking points▾

(1) Esterification: a carboxylic acid reacts with an alcohol in the presence of a little concentrated sulphuric acid (as catalyst) to form an ester and water, R-COOH + R'-OH -> R-COO-R' + H2O; this reaction is reversible and gives esters that have fruity smells. (2) Decarboxylation: the sodium salt of a carboxylic acid, when heated with soda lime (NaOH + CaO), loses carbon dioxide to give a hydrocarbon (alkane) with one carbon less, R-COONa + NaOH -> R-H + Na2CO3.

R-COOH + R'-OH -> R-COO-R' + H2O

Marking-scheme points

  • ✓Esterification: R-COOH + R'-OH -> ester + water (conc. H2SO4 catalyst)
  • ✓Decarboxylation: R-COONa + NaOH (soda lime) -> R-H + Na2CO3
  • ✓Decarboxylation removes CO2 and gives an alkane with one less carbon
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ChemistryClass 122 marksmedium

Aldehydes, Ketones and Carboxylic Acids

What is the iodoform test? Which compounds give a positive result?

Reveal model answer + marking points▾

The iodoform test is used to detect the presence of a methyl ketone group (CH3-CO-) or a group that can be oxidised to it, such as CH3-CH(OH)-. When such a compound is warmed with iodine and sodium hydroxide (or sodium hypoiodite), it gives a yellow precipitate of iodoform (CHI3) with a characteristic smell. Compounds like acetaldehyde, acetone, ethanol and isopropanol give a positive iodoform test.

Marking-scheme points

  • ✓Detects a methyl ketone (CH3-CO-) or CH3-CH(OH)- group
  • ✓Warm with I2 and NaOH -> yellow precipitate of iodoform (CHI3)
  • ✓Positive for ethanol, acetaldehyde, acetone, isopropanol
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