MixedJEE Physics · Original learning card5 original chapter questions

Drift Speed and Carrier Density

For one carrier species in a uniform conductor, current magnitude equals number density times carrier charge magnitude, cross-sectional area, and drift-speed magnitude.

Why this shows up in the exam

Estimating electron drift speed · Finding carrier density · Comparing wires carrying the same current

Learn the idea

A small average drift of many carriers produces an ordinary macroscopic current. Electrons move randomly even without a battery, but their random velocities cancel. An electric field adds a tiny directed drift whose collective charge transport is measurable.

🧠 Memory hook: Many carriers times tiny drift makes the current.

Get this one clearly and it pays off every single time it shows up in the paper. 🎯

Formulas & facts to keep ready

  • I = n |q| A v_d — magnitude for uniform n, A, and average drift speed
  • v_d = I/(n |q| A) — drift speed inferred from a steady current

How to approach it

  1. 1Write I = n|q|Av_d
  2. 2Convert mm squared to m squared
  3. 3State direction separately from magnitude

Common slip-ups that cost marks

  • •Using electron random thermal speed as drift speed
  • •Forgetting cross-sectional area conversion
  • •Assigning electron drift the conventional-current direction

🌟 That's the whole idea — you've got this. Try the practice set below; every question you attempt makes it stick a little harder.

Original chapter practice

Original questions for this chapter, not past-paper questions or an exact mapping to this individual concept.

Question 1 of 5

A cell of emf 6 V and internal resistance 1 ohm is connected to a 2 ohm resistor. Find the circuit current.

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