MixedJEE Physics · Original learning card5 original chapter questions

Mobility, Relaxation Time, and Drude Conductivity

In the classical Drude model with field-independent relaxation time, mobility is drift speed per field and conductivity is nq times mobility; the electron form is ne squared tau over m.

Why this shows up in the exam

Estimating mobility from drift data · Relating mean free time to resistivity · Explaining material conductivity

Learn the idea

Carrier response links microscopic collisions to mobility, conductivity, and resistivity. An electric field accelerates a carrier between collisions. Frequent collisions limit the average drift, so longer relaxation time or more carriers makes the material more conductive.

🧠 Memory hook: More carriers or longer free time means easier conduction.

Get this one clearly and it pays off every single time it shows up in the paper. 🎯

Formulas & facts to keep ready

  • mu = |v_d|/E = |q| tau/m — mobility in the low-field Drude model
  • sigma = n |q| mu = n q² tau/m — conductivity for one carrier species
  • rho = 1/sigma — resistivity of an isotropic ohmic material

How to approach it

  1. 1List n, q, tau, and m
  2. 2Choose mu, sigma, or rho relation
  3. 3Check SI units before substitution

Common slip-ups that cost marks

  • •Dropping one factor of charge in sigma
  • •Using the Drude formula for a strongly non-ohmic regime
  • •Confusing mobility with drift speed

🌟 That's the whole idea — you've got this. Try the practice set below; every question you attempt makes it stick a little harder.

Original chapter practice

Original questions for this chapter, not past-paper questions or an exact mapping to this individual concept.

Question 1 of 5

A cell of emf 6 V and internal resistance 1 ohm is connected to a 2 ohm resistor. Find the circuit current.

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