MixedJEE Physics · Original learning card5 original chapter questions

Series Resistors and Voltage Division

For resistors connected end-to-end with no branching node, equivalent resistance is their sum. With an unloaded divider, each voltage drop is proportional to its resistance.

Why this shows up in the exam

Voltage-divider design · Series heater or lamp circuits · Combining wire segments

Learn the idea

Series elements carry the same current and their voltage drops add. A single stream of charge passes through every series resistor. A larger resistance therefore claims a larger share of the total voltage.

🧠 Memory hook: Same current in series; voltage divides by resistance.

Get this one clearly and it pays off every single time it shows up in the paper. 🎯

Formulas & facts to keep ready

  • R_eq = sum R_i — series equivalent resistance
  • V_i = V R_i/(sum R) — unloaded voltage divider across series resistors

How to approach it

  1. 1Confirm there is no branch at the shared node
  2. 2Add series resistance
  3. 3Use the common current or voltage ratio

Common slip-ups that cost marks

  • •Using voltage division when a load creates a branch
  • •Adding conductances in series
  • •Assuming equal drops across unequal resistors

🌟 That's the whole idea — you've got this. Try the practice set below; every question you attempt makes it stick a little harder.

Original chapter practice

Original questions for this chapter, not past-paper questions or an exact mapping to this individual concept.

Question 1 of 5

A cell of emf 6 V and internal resistance 1 ohm is connected to a 2 ohm resistor. Find the circuit current.

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