MixedJEE Physics · Original learning card5 original chapter questions

Electrical Work and Energy

For charge Q crossing a constant potential difference V, work is QV. For time-varying conditions, energy is the integral of VI over time; kilowatt-hour is an energy unit.

Why this shows up in the exam

Battery work · Electricity consumption · Energy supplied to mixed systems

Learn the idea

Moving charge through a potential difference transfers electrical energy. A source gives each coulomb E joules of energy, while circuit elements convert that energy to heat, light, motion, or stored energy.

🧠 Memory hook: Volts are joules per coulomb.

Get this one clearly and it pays off every single time it shows up in the paper. 🎯

Formulas & facts to keep ready

  • W = Q V — energy transfer for charge Q across constant V
  • W = integral V(t) I(t) dt — general electrical energy transfer
  • 1 kWh = 3.6 x 10⁶ J — commercial energy conversion

How to approach it

  1. 1Identify charge, current-time, or power-time data
  2. 2Choose QV or integrate VI
  3. 3Report joules or convert energy units

Common slip-ups that cost marks

  • •Calling kWh a unit of power
  • •Using W = QV when V varies without integration
  • •Ignoring energy leaving as useful work

🌟 That's the whole idea — you've got this. Try the practice set below; every question you attempt makes it stick a little harder.

Original chapter practice

Original questions for this chapter, not past-paper questions or an exact mapping to this individual concept.

Question 1 of 5

A cell of emf 6 V and internal resistance 1 ohm is connected to a 2 ohm resistor. Find the circuit current.

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