MixedJEE Physics · Original learning card5 original chapter questions

Appliance Ratings and Bulb Circuits

For a resistive appliance at rating, R_rated = V_rated squared/P_rated and I_rated = P_rated/V_rated. Actual power follows the actual circuit voltage or current; incandescent cold resistance can differ greatly.

Why this shows up in the exam

Bulbs in series and parallel · Choosing a series dropping resistor · Comparing illumination qualitatively

Learn the idea

A rated voltage and power specify an appliance's hot operating resistance, not its power at every connection. A 100 W, 220 V bulb draws 100 W only at 220 V. In series or at another voltage, first infer its operating resistance under the usual constant-resistance exam model.

🧠 Memory hook: Ratings define the designed operating point.

Get this one clearly and it pays off every single time it shows up in the paper. 🎯

Formulas & facts to keep ready

  • R_rated = V_rated²/P_rated — effective resistance at rated operation
  • I_rated = P_rated/V_rated — current drawn at the rated operating point
  • P_actual = V_actual²/R_model — actual power under the stated constant-R model

How to approach it

  1. 1Convert every rating to R or I
  2. 2Solve the actual connection
  3. 3Compute actual power and compare

Common slip-ups that cost marks

  • •Treating wattage as resistance
  • •Keeping rated power after changing voltage
  • •Ignoring hot-versus-cold filament resistance

🌟 That's the whole idea — you've got this. Try the practice set below; every question you attempt makes it stick a little harder.

Original chapter practice

Original questions for this chapter, not past-paper questions or an exact mapping to this individual concept.

Question 1 of 5

A cell of emf 6 V and internal resistance 1 ohm is connected to a 2 ohm resistor. Find the circuit current.

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