MixedJEE Physics · Original learning card5 original chapter questions

Electric and Magnetic Energy Density

The instantaneous electromagnetic energy density is the sum of electric and magnetic terms. For a plane wave, the field-amplitude relation makes these terms equal, and sinusoidal time averaging contributes the usual factor of one-half.

Why this shows up in the exam

Finding energy stored in an illuminated volume · Comparing electric and magnetic energy shares · Converting field amplitude to average energy density

Learn the idea

A plane wave stores equal average energy in its electric and magnetic fields. Energy moves back and forth through two field forms. In a plane wave, the electric and magnetic contributions are equal at each point in a simple linear medium, so either contribution is half the total.

🧠 Memory hook: Plane waves split field energy equally.

Get this one clearly and it pays off every single time it shows up in the paper. 🎯

Formulas & facts to keep ready

  • u_E = (1/2) epsilon E² — instantaneous electric energy density
  • u_B = B²/(2 mu) — instantaneous magnetic energy density
  • u_E = u_B, u_total = epsilon E² = B²/mu — plane-wave equality and instantaneous total
  • <u_total> = (1/2) epsilon E₀² — cycle-averaged total energy density for a sinusoid

How to approach it

  1. 1Decide whether the question asks instantaneous or average energy
  2. 2Calculate one field contribution with the matching field value
  3. 3Double one contribution for the plane-wave total

Common slip-ups that cost marks

  • •Calling either field contribution the total energy
  • •Mixing peak and instantaneous field values
  • •Forgetting the time-average factor for a sinusoidal squared field

🌟 That's the whole idea — you've got this. Try the practice set below; every question you attempt makes it stick a little harder.

Original chapter practice

Original questions for this chapter, not past-paper questions or an exact mapping to this individual concept.

Question 1 of 5

An electromagnetic wave in vacuum has wavelength 1 m. Take c = 3 x 10^8 m/s. Find its frequency in units of 10^8 Hz.

Take a timed JEE Physics sectional mock

More from Electromagnetic Waves