MixedJEE Physics · Original learning card5 original chapter questions

Radiation Pressure on Reflecting Surfaces

For normal incidence on a perfect reflector, momentum transfer is 2U/c and radiation pressure is 2I/c. The factor of two applies only to complete reflection with reversal of the normal momentum component.

Why this shows up in the exam

Calculating force on mirrors · Explaining solar-sail thrust · Comparing absorbing and reflecting radiation forces

Learn the idea

Normal reflection reverses photon momentum, doubling pressure compared with complete absorption. A reflected wave arrives with momentum toward the surface and leaves with momentum away from it. That reversal changes momentum by twice the incoming amount.

🧠 Memory hook: Reflection reverses momentum, so the transfer doubles.

Get this one clearly and it pays off every single time it shows up in the paper. 🎯

Formulas & facts to keep ready

  • P_rad = 2I/c — pressure on a perfect reflector at normal incidence
  • F = 2IA/c — force on a perfectly reflecting area
  • Delta p = 2U/c — momentum transfer for complete normal reflection

How to approach it

  1. 1Confirm complete reflection and normal incidence
  2. 2Find incident intensity or power at the surface
  3. 3Apply the factor of two only to the normal momentum transfer

Common slip-ups that cost marks

  • •Using the reflection factor of two for absorption
  • •Applying normal-incidence formulas to an unspecified oblique case
  • •Using source power instead of power actually incident on the surface

🌟 That's the whole idea — you've got this. Try the practice set below; every question you attempt makes it stick a little harder.

Original chapter practice

Original questions for this chapter, not past-paper questions or an exact mapping to this individual concept.

Question 1 of 5

An electromagnetic wave in vacuum has wavelength 1 m. Take c = 3 x 10^8 m/s. Find its frequency in units of 10^8 Hz.

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