MixedJEE Physics · Original learning card5 original chapter questions

Vernier Least Count and Direct Reading

For a direct vernier, the least count is one main-scale division minus one vernier-scale division, and the observed reading is the main-scale reading plus the coinciding vernier division multiplied by that least count.

Why this shows up in the exam

Tube diameter measurement · Depth and internal-diameter measurement · Travelling-microscope scale reading

Learn the idea

A vernier resolves the small mismatch between a main-scale division and a vernier-scale division. The two scales almost agree, so the coinciding vernier mark reveals the fraction left beyond the main-scale reading; the instrument turns a small accumulated mismatch into a readable length.

🧠 Memory hook: Main scale gives the whole part; coincidence gives the fraction.

Get this one clearly and it pays off every single time it shows up in the paper. 🎯

Formulas & facts to keep ready

  • LC = 1 MSD - 1 VSD — direct-vernier least count; use the actual stated scale relation
  • observed reading = MSR + n(LC) — reading when the nth vernier mark coincides, before zero correction

How to approach it

  1. 1Convert the stated VSD-MSD relation first
  2. 2Record MSR immediately left of vernier zero
  3. 3Add coincidence contribution, then apply correction

Common slip-ups that cost marks

  • •Multiplying one MSD by the number of vernier divisions
  • •Using the coinciding mark as a length without multiplying by LC
  • •Applying zero correction before determining its sign

🌟 That's the whole idea — you've got this. Try the practice set below; every question you attempt makes it stick a little harder.

Original chapter practice

Original questions for this chapter, not past-paper questions or an exact mapping to this individual concept.

Question 1 of 5

In a meter bridge, resistance 2 ohm is in the left gap and balance occurs at 40 cm from the left end. Find the right-gap resistance.

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