MixedJEE Physics · Original learning card5 original chapter questions

Screw-Gauge Pitch and Least Count

The pitch is the axial distance moved by the spindle per complete rotation, and the screw-gauge least count is the pitch divided by the number of equal divisions on the circular scale.

Why this shows up in the exam

Wire diameter measurement · Sheet thickness measurement · Small-sphere diameter measurement

Learn the idea

A screw gauge converts one rotation into a small axial advance and divides that advance on its circular scale. The screw thread acts like a very shallow ramp wrapped around a cylinder: one turn advances by the pitch, while the circular divisions split that advance into much smaller readable steps.

🧠 Memory hook: One turn gives pitch; one division gives pitch divided by divisions.

Get this one clearly and it pays off every single time it shows up in the paper. 🎯

Formulas & facts to keep ready

  • pitch = axial advance / number of rotations — calibration from a measured multi-turn displacement
  • LC = pitch / N — resolution for N circular-scale divisions per turn

How to approach it

  1. 1Find one-turn advance
  2. 2Divide by circular-scale divisions
  3. 3Keep pitch and LC in the same length unit

Common slip-ups that cost marks

  • •Treating total multi-turn travel as the pitch
  • •Multiplying pitch by circular divisions
  • •Changing pitch or division count without recomputing LC

🌟 That's the whole idea — you've got this. Try the practice set below; every question you attempt makes it stick a little harder.

Original chapter practice

Original questions for this chapter, not past-paper questions or an exact mapping to this individual concept.

Question 1 of 5

In a meter bridge, resistance 2 ohm is in the left gap and balance occurs at 40 cm from the left end. Find the right-gap resistance.

Take a timed JEE Physics sectional mock

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