MixedJEE Physics · Original learning card10 original chapter questions

Vector Addition, Subtraction, and Resultants

For vectors A and B separated by angle theta, the resultant is R = A + B and its squared magnitude follows the cosine rule; A - B is obtained by reversing B.

Why this shows up in the exam

Combining concurrent forces · Adding successive displacements · Finding relative separations and polygon resultants

Learn the idea

Vector sums depend on both magnitudes and the angle between directions. Joining arrows head to tail shows why aligned vectors reinforce, opposite vectors cancel, and oblique vectors produce a diagonal resultant. Subtraction means adding the reversed arrow.

🧠 Memory hook: Add arrows head to tail; subtract by turning the second arrow around.

Get this one clearly and it pays off every single time it shows up in the paper. 🎯

Formulas & facts to keep ready

  • |A+B|² = A² + B² + 2AB cos(theta) — magnitude of a two-vector sum
  • |A-B|² = A² + B² - 2AB cos(theta) — magnitude of a vector difference
  • R_vector = sum A_i_vector — component-wise superposition of any number of vectors

How to approach it

  1. 1Translate the wording into a vector equation
  2. 2Choose components or the cosine rule
  3. 3Check limiting cases theta = 0 and theta = 180 degrees

Common slip-ups that cost marks

  • •Adding magnitudes regardless of direction
  • •Using the sum formula for a difference
  • •Solving only for magnitude when direction is asked

🌟 That's the whole idea — you've got this. Try the practice set below; every question you attempt makes it stick a little harder.

Original chapter practice

Original questions for this chapter, not past-paper questions or an exact mapping to this individual concept.

Question 1 of 10

A particle has initial speed 2 m/s and constant acceleration 3 m/s^2 for 4 s. What distance does it cover?

Take a timed JEE Physics sectional mock