MixedJEE Physics · Original learning card10 original chapter questions

Constant-Acceleration Kinematics in a Plane

For constant vector acceleration a, v(t) = v_0 + at and r(t) = r_0 + v_0 t + one-half at squared; eliminating time or applying components gives the required geometry.

Why this shows up in the exam

Vehicle motion with independent horizontal and vertical acceleration · Locating particles under constant force · Reconstructing a trajectory from component equations

Learn the idea

With constant acceleration, each Cartesian component follows the familiar one-dimensional equations independently. A planar path may curve even though the acceleration is constant, because the horizontal and vertical velocity components evolve separately and then recombine.

🧠 Memory hook: Constant acceleration means two independent quadratic component stories.

Get this one clearly and it pays off every single time it shows up in the paper. 🎯

Formulas & facts to keep ready

  • v_vector = v₀_vector + a_vector t — velocity under constant acceleration
  • r_vector = r₀_vector + v₀_vector t + (1/2)a_vector t² — position under constant acceleration
  • v² = v₀² + 2 a dot (r-r₀) — scalar relation only when applied consistently along the displacement

How to approach it

  1. 1Choose axes that simplify acceleration
  2. 2Write one equation per component
  3. 3Use the common time to reconnect the components

Common slip-ups that cost marks

  • •Applying a scalar equation to vector magnitudes blindly
  • •Omitting initial position
  • •Mixing components from different times

🌟 That's the whole idea — you've got this. Try the practice set below; every question you attempt makes it stick a little harder.

Original chapter practice

Original questions for this chapter, not past-paper questions or an exact mapping to this individual concept.

Question 1 of 10

A particle has initial speed 2 m/s and constant acceleration 3 m/s^2 for 4 s. What distance does it cover?

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