MixedJEE Physics · Original learning card10 original chapter questions

River Crossing and Swimmer-Boat Problems

The bank-frame velocity is v_ground = v_relative_water + v_river. For heading normal to the bank, crossing time is width divided by the cross-stream component; for zero drift, the along-stream components cancel.

Why this shows up in the exam

Planning ferry headings · Estimating drift in currents · Comparing fastest and shortest river routes

Learn the idea

Ground velocity across a river is the vector sum of velocity through water and river flow. The swimmer or boat controls velocity relative to water, while the river carries both downstream. Fastest crossing and shortest path are different optimizations.

🧠 Memory hook: Across sets the time; along sets the drift.

Get this one clearly and it pays off every single time it shows up in the paper. 🎯

Formulas & facts to keep ready

  • v_ground = v_swimmer/water + v_water/ground — velocity addition between water and bank frames
  • t_cross = W/|v_cross| — crossing time from cross-stream component
  • v_swimmer,along + v_river = 0 — condition for reaching the directly opposite point

How to approach it

  1. 1Draw flow, across-river, and heading arrows
  2. 2Resolve the controlled velocity
  3. 3Use cross component for time and stream component for drift

Common slip-ups that cost marks

  • •Using swimmer speed as ground speed
  • •Confusing minimum time with minimum distance
  • •Cancelling the wrong component for straight crossing

🌟 That's the whole idea — you've got this. Try the practice set below; every question you attempt makes it stick a little harder.

Original chapter practice

Original questions for this chapter, not past-paper questions or an exact mapping to this individual concept.

Question 1 of 10

A particle has initial speed 2 m/s and constant acceleration 3 m/s^2 for 4 s. What distance does it cover?

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