MixedJEE Physics · Original learning card5 original chapter questions

RMS-Speed Scaling with Temperature and Molar Mass

For an ideal gas, v_rms = sqrt(3RT/M); hence speed ratios depend on sqrt(T/M) and do not directly depend on gas pressure.

Why this shows up in the exam

Identifying a gas from rms speed · Comparing hydrogen, oxygen, and noble gases · Dissociation and temperature-change questions

Learn the idea

Molecular thermal speed grows as square root of absolute temperature and falls as square root of molar mass. Heating makes every species faster, while at the same temperature a lighter species must move faster to carry the same average translational energy.

🧠 Memory hook: Speed follows the square root of T over M.

Get this one clearly and it pays off every single time it shows up in the paper. 🎯

Formulas & facts to keep ready

  • v_rms = sqrt(3RT/M) — rms speed using SI molar mass M for an ideal gas
  • v2/v1 = sqrt((T2 M1)/(T1 M2)) — ratio rule for two gas states or species

How to approach it

  1. 1Write the ratio before inserting values
  2. 2Convert every temperature to kelvin
  3. 3Square only after isolating the desired ratio

Common slip-ups that cost marks

  • •Using Celsius temperature
  • •Making rms speed proportional to pressure
  • •Forgetting molecular mass changes after dissociation

🌟 That's the whole idea — you've got this. Try the practice set below; every question you attempt makes it stick a little harder.

Original chapter practice

Original questions for this chapter, not past-paper questions or an exact mapping to this individual concept.

Question 1 of 5

A gas has rms molecular speed 300 m/s at 300 K. What is its rms speed at 1200 K, assuming ideal behavior?

Take a timed JEE Physics sectional mock