MixedJEE Physics · Original learning card5 original chapter questions

Equipartition and Internal Energy

For an ideal gas with f active quadratic degrees of freedom, U = (f/2)nRT and Delta U = nC_V Delta T, assuming f remains unchanged across the temperature interval.

Why this shows up in the exam

Internal energy of monoatomic and diatomic gases · Thermalization after a moving container stops · Energy of gas mixtures

Learn the idea

Each active quadratic degree contributes equal mean energy, making ideal-gas internal energy a temperature function. A molecule's thermal energy is shared equally among all active quadratic storage modes; multiplying per-particle energy by particle count gives the sample energy.

🧠 Memory hook: Half kT per quadratic degree; then multiply by particles.

Get this one clearly and it pays off every single time it shows up in the paper. 🎯

Formulas & facts to keep ready

  • U = (f/2) nRT — internal energy of an ideal gas with fixed active degree count f
  • Delta U = n C_V Delta T — internal-energy change when molar C_V is valid over the interval
  • U = N(f/2)k_B T — particle-count form of equipartition energy

How to approach it

  1. 1Determine active f
  2. 2Choose per molecule or per mole
  3. 3Apply energy conservation and check signs

Common slip-ups that cost marks

  • •Using total mass instead of moles
  • •Adding an arbitrary constant when only changes matter
  • •Keeping f fixed across a mode-activation transition without justification

🌟 That's the whole idea — you've got this. Try the practice set below; every question you attempt makes it stick a little harder.

Original chapter practice

Original questions for this chapter, not past-paper questions or an exact mapping to this individual concept.

Question 1 of 5

A gas has rms molecular speed 300 m/s at 300 K. What is its rms speed at 1200 K, assuming ideal behavior?

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