MixedJEE Physics · Original learning card5 original chapter questions

Speed of Sound in an Ideal Gas

For small adiabatic disturbances in an ideal gas, c = sqrt(gamma P/rho) = sqrt(gamma RT/M), with equilibrium properties evaluated locally.

Why this shows up in the exam

Comparing sound in helium and nitrogen · Gas-mixture sound speed · Linking sound speed with molecular rms speed

Learn the idea

Sound speed depends on adiabatic stiffness divided by density, giving a square-root dependence on gamma T/M. A pressure disturbance moves faster when the gas is harder to compress and slower when each mole carries more mass.

🧠 Memory hook: Sound follows square root of gamma T over M.

Get this one clearly and it pays off every single time it shows up in the paper. 🎯

Formulas & facts to keep ready

  • c = sqrt(gamma P/rho) — sound speed from adiabatic bulk response
  • c = sqrt(gamma RT/M) — ideal-gas form using SI molar mass
  • c2/c1 = sqrt((gamma2 T2 M1)/(gamma1 T1 M2)) — comparison between ideal gases

How to approach it

  1. 1Find gamma and effective molar mass
  2. 2Use absolute temperature
  3. 3Form a ratio to cancel common constants

Common slip-ups that cost marks

  • •Using isothermal compressibility
  • •Dropping gamma
  • •Using an unweighted molar mass for a mixture

🌟 That's the whole idea — you've got this. Try the practice set below; every question you attempt makes it stick a little harder.

Original chapter practice

Original questions for this chapter, not past-paper questions or an exact mapping to this individual concept.

Question 1 of 5

A gas has rms molecular speed 300 m/s at 300 K. What is its rms speed at 1200 K, assuming ideal behavior?

Take a timed JEE Physics sectional mock