MixedJEE Physics · Original learning card5 original chapter questions

Internal Energy of an Ideal Gas

For a fixed amount of ideal gas with temperature-independent molar heat capacity, internal energy is a state function satisfying ΔU = nC_VΔT; therefore any isothermal ideal-gas process has ΔU = 0.

Why this shows up in the exam

Comparing two paths between the same states · Heating gas in a rigid vessel · Computing temperature change from adiabatic work

Learn the idea

For an ideal gas, internal energy depends only on temperature, not directly on pressure or volume. Ideal-gas molecules store microscopic kinetic energy, so equal temperature changes give equal internal-energy changes even along different paths.

🧠 Memory hook: Ideal-gas U follows T, whatever path P and V take.

Get this one clearly and it pays off every single time it shows up in the paper. 🎯

Formulas & facts to keep ready

  • ΔU = n C_V (T_f - T_i) — ideal-gas internal-energy change when C_V is constant over the interval
  • dU = n C_V dT — differential form for a calorically perfect ideal gas

How to approach it

  1. 1Find endpoint temperatures
  2. 2Use C_V for internal energy
  3. 3Check that a complete cycle has net ΔU equal to zero

Common slip-ups that cost marks

  • •Setting ΔU equal to zero for every cycle leg
  • •Using C_P instead of C_V in the state-function relation
  • •Inferring ΔU from work alone without the first law

🌟 That's the whole idea — you've got this. Try the practice set below; every question you attempt makes it stick a little harder.

Original chapter practice

Original questions for this chapter, not past-paper questions or an exact mapping to this individual concept.

Question 1 of 5

A gas absorbs 500 J of heat and does 200 J of work. What is the change in its internal energy?

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