MixedJEE Physics · Original learning card5 original chapter questions

Heat Capacities, Degrees of Freedom, and Mayer Relation

For a calorically perfect ideal gas with f active quadratic degrees of freedom, C_V = fR/2, C_P = C_V + R, and γ = C_P/C_V; vibrational modes are included only when thermally active as stated.

Why this shows up in the exam

Identifying monatomic or rigid-diatomic gases · Finding heat in constant-pressure or constant-volume heating · Deducing γ or molecular degrees of freedom

Learn the idea

Molecular degrees of freedom determine C_V, while ideal-gas expansion makes C_P exceed C_V by R. Heating at constant volume only raises microscopic energy; heating at constant pressure must also supply expansion work.

🧠 Memory hook: At constant pressure, add one R for expansion.

Get this one clearly and it pays off every single time it shows up in the paper. 🎯

Formulas & facts to keep ready

  • C_V = fR/2; C_P = (f+2)R/2 — molar heat capacities for an ideal gas with f active quadratic degrees of freedom
  • C_P - C_V = R — Mayer relation for one mole of an ideal gas
  • γ = C_P/C_V = 1 + 2/f — heat-capacity ratio under the same active-mode assumption

How to approach it

  1. 1Determine active degrees of freedom
  2. 2Choose C_V or C_P from the constraint
  3. 3Keep molar, specific, and total heat capacities distinct

Common slip-ups that cost marks

  • •Using Celsius temperature in absolute ratios
  • •Always assigning five degrees of freedom to every diatomic gas
  • •Confusing total heat capacity nC with molar heat capacity C

🌟 That's the whole idea — you've got this. Try the practice set below; every question you attempt makes it stick a little harder.

Original chapter practice

Original questions for this chapter, not past-paper questions or an exact mapping to this individual concept.

Question 1 of 5

A gas absorbs 500 J of heat and does 200 J of work. What is the change in its internal energy?

Take a timed JEE Physics sectional mock