Board Boosters
The questions your board exam loves to ask
800 most-asked Class 11 & 12 (+1 / +2) questions across Physics, Chemistry, Maths and Biology — each with a model answer and the exact marking-scheme points examiners reward. Revise smart, walk in calm.
PhysicsClass 112 markseasy
System of Particles and Rotational Motion
Find the moment of inertia of a ring of mass 2 kg and radius 0.5 m about an axis passing through its centre and perpendicular to its plane.
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For a ring about its central axis, I = M R^2 = 2 * (0.5)^2 = 2 * 0.25 = 0.5 kg m^2.
I = M R^2
Marking-scheme points
- ✓Ring: I = M R^2
- ✓= 2 * 0.25
- ✓I = 0.5 kg m^2
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Gravitation
What is a geostationary satellite? State any two conditions for a satellite to be geostationary.
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A geostationary satellite appears stationary relative to the Earth because it revolves in step with the Earth's rotation. Conditions: (i) its orbital period must equal 24 hours (equal to Earth's rotation period); (ii) it must orbit in the equatorial plane, in the same (west-to-east) sense as the Earth, at a height of about 36000 km.
Marking-scheme points
- ✓Period = 24 h (matches Earth)
- ✓Equatorial plane, west to east
- ✓Height ~ 36000 km
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Mechanical Properties of Solids
State Hooke's law and define the elastic limit.
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Hooke's law: within the elastic limit, the stress developed in a body is directly proportional to the strain produced, i.e. stress / strain = a constant (the modulus of elasticity). The elastic limit is the maximum stress up to which a body returns to its original shape and size on removing the deforming force; beyond it, permanent (plastic) deformation occurs.
stress = E * strain
Marking-scheme points
- ✓Stress proportional to strain (within elastic limit)
- ✓stress/strain = modulus of elasticity
- ✓Elastic limit: max stress for full recovery
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Mechanical Properties of Fluids
State Pascal's law and give one application of it.
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Pascal's law: a pressure applied to an enclosed incompressible fluid is transmitted equally and undiminished to every part of the fluid and to the walls of the container. Application: the hydraulic lift/brake, where a small force on a small piston produces a large force on a large piston because pressure is the same throughout.
F1 / A1 = F2 / A2
Marking-scheme points
- ✓Pressure transmitted equally in an enclosed fluid
- ✓Application: hydraulic lift / brakes
- ✓Small force -> large force via area ratio
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Mechanical Properties of Fluids
State the equation of continuity for fluid flow and what it represents.
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For the steady flow of an incompressible fluid, the product of area of cross-section and speed is constant along the tube: A1 v1 = A2 v2 (A v = constant). It is a statement of conservation of mass - where a pipe is narrow the fluid flows faster, and where it is wide it flows slower.
A1 v1 = A2 v2
Marking-scheme points
- ✓A v = constant
- ✓Based on conservation of mass
- ✓Narrow pipe -> higher speed
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Mechanical Properties of Fluids
Define surface tension. Give one everyday example that demonstrates it.
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Surface tension is the property by which the free surface of a liquid behaves like a stretched elastic membrane; it is the force per unit length acting along the surface (SI unit: N/m). Example: small water droplets and mercury beads become spherical (minimum surface area), and some insects can walk on water.
T = F / L
Marking-scheme points
- ✓Force per unit length on liquid surface
- ✓Unit N/m
- ✓Example: spherical droplets, insects on water
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Thermal Properties of Matter
Define the coefficient of linear expansion. Write the relation for the increase in length of a rod on heating.
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The coefficient of linear expansion (alpha) is the fractional increase in length per degree rise in temperature: alpha = (delta L) / (L * delta T). The increase in length is delta L = L alpha (delta T), and the new length is L' = L (1 + alpha delta T). SI unit of alpha: per kelvin (K^-1).
delta L = L alpha delta T
Marking-scheme points
- ✓alpha = delta L / (L delta T)
- ✓delta L = L alpha delta T
- ✓Unit K^-1
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Thermal Properties of Matter
Distinguish between specific heat capacity and latent heat.
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Specific heat capacity is the heat required to raise the temperature of 1 kg of a substance by 1 K (Q = m c delta T; unit J/kg/K) - the temperature changes. Latent heat is the heat required to change the state of 1 kg of a substance at constant temperature (Q = m L; unit J/kg) - the temperature stays constant during the phase change.
Q = m c delta T ; Q = m L
Marking-scheme points
- ✓Specific heat: Q = m c delta T, temperature changes
- ✓Latent heat: Q = m L, temperature constant (phase change)
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Thermal Properties of Matter
State Newton's law of cooling.
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Newton's law of cooling states that the rate of loss of heat of a body is directly proportional to the difference in temperature between the body and its surroundings, provided this difference is small: (- dQ/dt) is proportional to (T - T_surroundings).
dQ/dt = -k (T - T0)
Marking-scheme points
- ✓Rate of cooling proportional to temperature difference
- ✓Valid for small differences
- ✓- dQ/dt proportional to (T - T0)
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Thermodynamics
State the zeroth law of thermodynamics. What does it define?
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The zeroth law states that if two systems are each in thermal equilibrium with a third system, then they are in thermal equilibrium with each other. It leads to the concept of temperature - a property that is the same for all bodies in thermal equilibrium.
Marking-scheme points
- ✓A eq C and B eq C => A eq B
- ✓Defines temperature
- ✓Basis of thermometry
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Thermodynamics
State the second law of thermodynamics (any one statement).
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Kelvin-Planck statement: it is impossible to construct an engine that, working in a cycle, converts all the heat absorbed from a source completely into work with no other effect. (Equivalently, Clausius statement: heat cannot flow of its own accord from a colder body to a hotter body.)
Marking-scheme points
- ✓Kelvin-Planck: no 100% heat-to-work engine
- ✓Clausius: heat won't flow cold -> hot on its own
- ✓Sets a direction for natural processes
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Kinetic Theory
State the law of equipartition of energy and give the degrees of freedom of a monatomic and a diatomic gas molecule.
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Law of equipartition: in thermal equilibrium, the total energy is shared equally among all degrees of freedom, each contributing (1/2) k T of energy per molecule. A monatomic molecule has 3 degrees of freedom (translational only); a diatomic molecule at ordinary temperatures has 5 (3 translational + 2 rotational).
Energy per degree of freedom = (1/2) k T
Marking-scheme points
- ✓Each degree of freedom gets (1/2) kT
- ✓Monatomic: 3 (translational)
- ✓Diatomic: 5 (3 trans + 2 rot)
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Oscillations
Define simple harmonic motion (SHM) and write its defining equation.
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Simple harmonic motion is an oscillation in which the restoring force (or acceleration) is directly proportional to the displacement from the mean position and is always directed towards it. Defining equation: a = - omega^2 x, where omega is the angular frequency and x the displacement.
a = - omega^2 x
Marking-scheme points
- ✓Restoring force proportional to -x
- ✓Directed towards mean position
- ✓a = - omega^2 x
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Oscillations
Write the expression for the time period of a mass m attached to a spring of force constant k, and state how it changes if the mass is quadrupled.
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T = 2 pi sqrt(m / k). Since T is proportional to sqrt(m), quadrupling the mass (m -> 4m) makes sqrt(4m) = 2 sqrt(m), so the time period doubles.
T = 2 pi sqrt(m / k)
Marking-scheme points
- ✓T = 2 pi sqrt(m/k)
- ✓T proportional to sqrt(m)
- ✓4x mass => 2x period
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Oscillations
What are forced oscillations and resonance?
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Forced oscillations occur when a body is made to oscillate under an external periodic force with the frequency of that force. Resonance is the special case when the driving frequency equals the body's natural frequency; the amplitude of oscillation then becomes maximum. Example: a child's swing pushed at its natural frequency.
Marking-scheme points
- ✓Forced: oscillation at the driving frequency
- ✓Resonance: driving frequency = natural frequency
- ✓Amplitude becomes maximum
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Waves
Derive the relation between wave speed, frequency and wavelength.
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In one time period T, a wave advances by one wavelength lambda. So wave speed v = distance / time = lambda / T. Since frequency f = 1/T, we get v = f lambda. This holds for all progressive waves.
v = f lambda
Marking-scheme points
- ✓In time T, wave moves one wavelength
- ✓v = lambda / T
- ✓f = 1/T => v = f lambda
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Waves
Distinguish between progressive (travelling) and stationary (standing) waves.
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A progressive wave transfers energy continuously in one direction, and every particle has the same amplitude but oscillates with a phase lag. A stationary wave is formed by two identical waves travelling in opposite directions; it does not transfer net energy, has fixed nodes (zero amplitude) and antinodes (maximum amplitude), and the amplitude varies from point to point.
Marking-scheme points
- ✓Progressive: transfers energy, same amplitude, phase lag
- ✓Stationary: no net energy transfer, fixed nodes and antinodes
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Motion in a Straight Line
Define relative velocity. Two trains move in the same direction at 60 km/h and 40 km/h - what is the velocity of the first relative to the second?
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Relative velocity of a body A with respect to B is the velocity of A as seen from B: v_AB = v_A - v_B. For the trains, v = 60 - 40 = 20 km/h, so the faster train appears to move ahead at 20 km/h relative to the slower one.
v_AB = v_A - v_B
Marking-scheme points
- ✓v_AB = v_A - v_B
- ✓Same direction: subtract speeds
- ✓= 20 km/h
Still unsure? Ask the AI tutor →PhysicsClass 112 marksmedium
Gravitation
Write the expression for the gravitational potential energy of a mass m at a distance r from the centre of the Earth (mass M), and explain why it is negative.
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U = - G M m / r. It is negative because the gravitational force is attractive: zero potential energy is taken at infinity, and as the mass is brought closer, work is done by gravity, lowering the energy below zero. The negative sign shows the mass is in a bound state.
U = - G M m / r
Marking-scheme points
- ✓U = - G M m / r
- ✓Reference: U = 0 at infinity
- ✓Negative => attractive, bound system
Still unsure? Ask the AI tutor →PhysicsClass 112 marksmedium
Work, Energy and Power
Define the coefficient of restitution. What are its values for a perfectly elastic and a perfectly inelastic collision?
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The coefficient of restitution (e) is the ratio of the relative velocity of separation after collision to the relative velocity of approach before collision: e = (velocity of separation) / (velocity of approach). For a perfectly elastic collision e = 1; for a perfectly inelastic collision e = 0.
e = (v2 - v1) / (u1 - u2)
Marking-scheme points
- ✓e = separation velocity / approach velocity
- ✓Perfectly elastic: e = 1
- ✓Perfectly inelastic: e = 0
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