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ChemistryClass 112 markshard

Classification of Elements and Periodicity

Why is the electron gain enthalpy of chlorine more negative than that of fluorine?

Reveal model answer + marking points

Although fluorine is smaller, its 2p subshell is very compact, so the incoming electron experiences strong inter-electronic repulsion from the already crowded 2p electrons. In chlorine, the larger 3p subshell accommodates the incoming electron with less repulsion, so more energy is released. Hence chlorine has a more negative (more exothermic) electron gain enthalpy than fluorine.

Marking-scheme points

  • F is small, compact 2p -> high electron-electron repulsion
  • Cl larger 3p -> less repulsion for incoming electron
  • So electron gain enthalpy of Cl is more negative
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ChemistryClass 112 markseasy

Classification of Elements and Periodicity

Define electronegativity. How does it vary across a period and down a group?

Reveal model answer + marking points

Electronegativity is the tendency of an atom in a molecule to attract the shared pair of electrons in a covalent bond towards itself. It increases across a period (as size decreases and nuclear charge increases) and decreases down a group (as size increases). Fluorine is the most electronegative element. The Pauling scale is commonly used.

Marking-scheme points

  • Tendency to attract bonded (shared) electrons
  • Increases across a period, decreases down a group
  • F is most electronegative; Pauling scale
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ChemistryClass 112 marksmedium

Classification of Elements and Periodicity

Arrange the isoelectronic species O2-, F-, Na+ and Mg2+ in increasing order of ionic radius. Justify.

Reveal model answer + marking points

All four species have 10 electrons (isoelectronic). For isoelectronic species, the greater the nuclear charge (number of protons), the smaller the radius. Nuclear charges: O2- (8), F- (9), Na+ (11), Mg2+ (12). Increasing order of radius: Mg2+ < Na+ < F- < O2-.

Marking-scheme points

  • All are isoelectronic (10 electrons)
  • More protons -> smaller radius
  • Order: Mg2+ < Na+ < F- < O2-
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ChemistryClass 112 markseasy

Chemical Bonding and Molecular Structure

Distinguish between an ionic bond and a covalent bond with one example each.

Reveal model answer + marking points

An ionic (electrovalent) bond is formed by the complete transfer of one or more electrons from one atom to another, producing oppositely charged ions held by electrostatic attraction (e.g. NaCl). A covalent bond is formed by the mutual sharing of electron pairs between atoms (e.g. H2 or Cl2). Ionic bonds form between metals and non-metals; covalent bonds form between non-metals.

Marking-scheme points

  • Ionic: complete transfer of electrons, e.g. NaCl
  • Covalent: sharing of electron pairs, e.g. H2
  • Ionic = metal + non-metal; covalent = non-metals
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ChemistryClass 112 marksmedium

Chemical Bonding and Molecular Structure

Why is the bond angle of H2O (104.5 deg) less than that of NH3 (107 deg)?

Reveal model answer + marking points

Both molecules are based on sp3 hybridisation with an ideal angle of 109.5 deg. NH3 has one lone pair, while H2O has two lone pairs. Lone pair-lone pair repulsion is stronger than lone pair-bond pair repulsion, and water has an extra lone pair, so its bond pairs are pushed closer together. Hence the bond angle of H2O (104.5 deg) is smaller than that of NH3 (107 deg).

Marking-scheme points

  • Both sp3, ideal 109.5 deg
  • NH3 has 1 lone pair; H2O has 2 lone pairs
  • More lone pairs -> greater repulsion -> smaller angle
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ChemistryClass 112 marksmedium

Chemical Bonding and Molecular Structure

Calculate the bond order of the nitrogen molecule (N2) using molecular orbital theory.

Reveal model answer + marking points

N2 has 14 electrons. Number of bonding electrons Nb = 10 and antibonding electrons Na = 4. Bond order = (Nb - Na)/2 = (10 - 4)/2 = 3. This corresponds to a nitrogen-nitrogen triple bond, which explains the very high stability and bond dissociation energy of N2.

Bond order = (Nb - Na)/2

Marking-scheme points

  • N2 has 14 electrons; Nb = 10, Na = 4
  • Bond order = (10 - 4)/2 = 3
  • Triple bond -> very stable molecule
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ChemistryClass 112 markseasy

Chemical Bonding and Molecular Structure

What is a coordinate (dative) bond? Explain with the example of the ammonium ion.

Reveal model answer + marking points

A coordinate bond is a covalent bond in which the shared pair of electrons is contributed by only one of the two bonded atoms (the donor). In the ammonium ion (NH4+), nitrogen in NH3 has a lone pair which it donates to a proton (H+) that has no electrons, forming the fourth N-H bond as a coordinate bond. Once formed, all four N-H bonds are identical.

NH3 + H+ -> NH4+

Marking-scheme points

  • Both shared electrons come from one atom (donor)
  • NH3 nitrogen lone pair donated to H+
  • All four N-H bonds become equivalent in NH4+
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ChemistryClass 112 marksmedium

Chemical Bonding and Molecular Structure

What is a hydrogen bond? State the conditions for its formation and its two types.

Reveal model answer + marking points

A hydrogen bond is a weak electrostatic attraction between a hydrogen atom covalently bonded to a highly electronegative atom (F, O or N) and the lone pair of another electronegative atom. Conditions: hydrogen must be attached to a small, highly electronegative atom. Types: intermolecular hydrogen bonding (between different molecules, e.g. in water and HF) and intramolecular hydrogen bonding (within the same molecule, e.g. o-nitrophenol).

Marking-scheme points

  • Attraction of H (bonded to F/O/N) with lone pair on another electronegative atom
  • Needs H on small, highly electronegative atom
  • Types: intermolecular and intramolecular
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ChemistryClass 112 marksmedium

Chemical Bonding and Molecular Structure

Why does water (H2O) have a much higher boiling point than hydrogen sulphide (H2S)?

Reveal model answer + marking points

Oxygen is much more electronegative and smaller than sulphur, so water molecules form strong intermolecular hydrogen bonds, whereas H2S molecules are held only by weak van der Waals (dipole) forces. Extra energy is needed to break the hydrogen bonds in water, so water has a much higher boiling point than H2S even though H2S has a higher molar mass.

Marking-scheme points

  • Water forms strong intermolecular H-bonds (O is small, electronegative)
  • H2S has only weak van der Waals forces
  • Breaking H-bonds needs more energy -> higher boiling point
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ChemistryClass 112 marksmedium

Chemical Bonding and Molecular Structure

Distinguish between a sigma bond and a pi bond. Which is stronger and why?

Reveal model answer + marking points

A sigma bond is formed by the head-on (axial) overlap of orbitals along the internuclear axis, while a pi bond is formed by the sidewise (lateral) overlap of parallel p orbitals. A sigma bond is stronger because axial overlap is more effective and greater, giving a larger region of electron density between the nuclei; pi bonds have smaller lateral overlap and are weaker and more reactive.

Marking-scheme points

  • Sigma: head-on/axial overlap; pi: sidewise overlap of p orbitals
  • Sigma has greater, more effective overlap
  • Sigma bond is stronger than pi bond
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ChemistryClass 112 markseasy

States of Matter

State Boyle's law and Charles's law with their mathematical expressions.

Reveal model answer + marking points

Boyle's law: at constant temperature, the volume of a fixed mass of gas is inversely proportional to its pressure, i.e. V is proportional to 1/P, so PV = constant. Charles's law: at constant pressure, the volume of a fixed mass of gas is directly proportional to its absolute (Kelvin) temperature, i.e. V is proportional to T, so V/T = constant.

PV = constant (Boyle); V/T = constant (Charles)

Marking-scheme points

  • Boyle: V proportional to 1/P at constant T -> PV = constant
  • Charles: V proportional to T at constant P -> V/T = constant
  • Temperature must be in Kelvin
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ChemistryClass 112 markseasy

States of Matter

Write the ideal gas equation and give the value of the gas constant R in two units.

Reveal model answer + marking points

The ideal gas equation is PV = nRT, where P = pressure, V = volume, n = number of moles, T = absolute temperature and R = universal gas constant. R = 0.0821 L atm K^-1 mol^-1 = 8.314 J K^-1 mol^-1.

PV = nRT

Marking-scheme points

  • PV = nRT
  • R = 0.0821 L atm K^-1 mol^-1
  • R = 8.314 J K^-1 mol^-1
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ChemistryClass 112 marksmedium

States of Matter

Write the van der Waals equation for n moles of a real gas and explain the significance of the constants a and b.

Reveal model answer + marking points

The van der Waals equation is (P + a n^2/V^2)(V - nb) = nRT. The constant 'a' corrects for the intermolecular forces of attraction (it accounts for the pressure being lower than ideal), and the constant 'b' corrects for the finite volume actually occupied by the gas molecules (excluded volume). Real gases deviate from ideal behaviour at high pressure and low temperature.

(P + a n^2/V^2)(V - nb) = nRT

Marking-scheme points

  • (P + a n^2/V^2)(V - nb) = nRT
  • a: correction for intermolecular attraction
  • b: correction for finite molecular volume
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ChemistryClass 112 markseasy

Thermodynamics

Define system and surroundings. Name the three types of thermodynamic systems.

Reveal model answer + marking points

A system is the specified part of the universe under study; the surroundings are the rest of the universe outside the system that can interact with it. The three types are: open system (exchanges both matter and energy with surroundings), closed system (exchanges only energy, not matter) and isolated system (exchanges neither matter nor energy).

Marking-scheme points

  • System = part under study; surroundings = rest of universe
  • Open: exchanges matter and energy
  • Closed: only energy; Isolated: neither
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ChemistryClass 112 markseasy

Thermodynamics

State the first law of thermodynamics and give its mathematical expression with sign convention.

Reveal model answer + marking points

The first law of thermodynamics states that energy can neither be created nor destroyed, only transformed from one form to another; the total energy of an isolated system remains constant. Mathematically, delta U = q + w, where delta U is the change in internal energy, q is the heat added to the system (positive when absorbed) and w is the work done on the system (positive when done on the system).

delta U = q + w

Marking-scheme points

  • Energy is conserved (cannot be created or destroyed)
  • delta U = q + w
  • q positive if heat absorbed; w positive if work done on system
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ChemistryClass 112 marksmedium

Thermodynamics

Define enthalpy. Derive the relation between delta H and delta U for a reaction involving gases.

Reveal model answer + marking points

Enthalpy (H) is the total heat content of a system at constant pressure, defined as H = U + PV. For a reaction at constant pressure and temperature, delta H = delta U + P delta V. For ideal gases, P delta V = delta ng RT, where delta ng is the change in the number of moles of gaseous species. Hence delta H = delta U + delta ng RT.

delta H = delta U + delta ng RT

Marking-scheme points

  • H = U + PV (heat content at constant pressure)
  • delta H = delta U + P delta V
  • For gases: delta H = delta U + delta ng RT
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ChemistryClass 112 markseasy

Thermodynamics

State Hess's law of constant heat summation and mention one of its applications.

Reveal model answer + marking points

Hess's law states that the total enthalpy change of a reaction is the same whether the reaction takes place in one step or in several steps, provided the initial and final conditions are the same. It follows from the fact that enthalpy is a state function. Applications: it is used to calculate enthalpies of formation, bond enthalpies and reaction enthalpies that cannot be measured directly.

Marking-scheme points

  • Total enthalpy change is path independent
  • Consequence of enthalpy being a state function
  • Used to find delta H that cannot be measured directly
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ChemistryClass 112 marksmedium

Thermodynamics

What is entropy? Predict the sign of delta S when ice melts into water.

Reveal model answer + marking points

Entropy (S) is a thermodynamic state function that measures the degree of randomness or disorder of a system. When ice (a highly ordered solid) melts into water (a more disordered liquid), disorder increases, so the entropy increases and delta S is positive.

delta S = q(rev) / T

Marking-scheme points

  • Entropy = measure of randomness/disorder
  • Melting increases disorder (solid -> liquid)
  • delta S is positive for melting of ice
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ChemistryClass 112 marksmedium

Thermodynamics

Define standard enthalpy of formation and standard enthalpy of combustion.

Reveal model answer + marking points

Standard enthalpy of formation is the enthalpy change when one mole of a compound is formed from its constituent elements in their standard states (at 298 K and 1 bar); e.g. for CO2 it is -393.5 kJ/mol. Standard enthalpy of combustion is the enthalpy change when one mole of a substance is completely burnt in excess oxygen under standard conditions; it is always negative (exothermic).

Marking-scheme points

  • Formation: 1 mol compound from elements in standard states
  • Combustion: 1 mol substance completely burnt in oxygen
  • Enthalpy of combustion is always negative
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ChemistryClass 112 markseasy

Equilibrium

What is a reversible reaction? State two characteristics of chemical equilibrium.

Reveal model answer + marking points

A reversible reaction is one that proceeds in both forward and backward directions under the same conditions. Characteristics of chemical equilibrium: (1) it is dynamic in nature, i.e. the forward and backward reactions continue at equal rates; (2) the observable properties (concentration, pressure, colour) remain constant with time; (3) it can be attained from either direction and is disturbed by changing conditions.

rate(forward) = rate(backward)

Marking-scheme points

  • Reversible: proceeds in both directions
  • Equilibrium is dynamic: forward rate = backward rate
  • Measurable properties stay constant with time
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