Board Boosters

The questions your board exam loves to ask

800 most-asked Class 11 & 12 (+1 / +2) questions across Physics, Chemistry, Maths and Biology — each with a model answer and the exact marking-scheme points examiners reward. Revise smart, walk in calm.

800 board questions•Model answers•Marking-scheme points•Every chapter•CBSE · ISC · State boards

180 questions · clear filters

MathsClass 113 marksmedium

Straight Lines

Find the equation of the line passing through the points (1, 2) and (3, 6).

Reveal model answer + marking points▾

Slope m = (6 - 2)/(3 - 1) = 4/2 = 2. Using point-slope form with point (1, 2): y - 2 = 2(x - 1), so y - 2 = 2x - 2, giving y = 2x, or 2x - y = 0.

y - y1 = m(x - x1)

Marking-scheme points

  • ✓Slope = (6 - 2)/(3 - 1) = 2
  • ✓y - 2 = 2(x - 1)
  • ✓Equation: 2x - y = 0
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MathsClass 113 marksmedium

Straight Lines

Find the acute angle between the lines x + sqrt(3) y = 1 and sqrt(3) x + y = 1.

Reveal model answer + marking points▾

Slope of first line m1 = -1/sqrt3; slope of second line m2 = -sqrt3. The angle between them satisfies tan(theta) = |(m1 - m2)/(1 + m1 m2)| = |(-1/sqrt3 + sqrt3)/(1 + (-1/sqrt3)(-sqrt3))| = |((-1 + 3)/sqrt3)/(1 + 1)| = |(2/sqrt3)/2| = 1/sqrt3. So theta = 30 degrees.

tan theta = |(m1 - m2)/(1 + m1 m2)|

Marking-scheme points

  • ✓m1 = -1/sqrt3, m2 = -sqrt3
  • ✓tan theta = |(m1 - m2)/(1 + m1 m2)| = 1/sqrt3
  • ✓theta = 30 degrees
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MathsClass 113 marksmedium

Straight Lines

Find the distance of the point (3, -5) from the line 3x - 4y - 26 = 0.

Reveal model answer + marking points▾

The distance of point (x1, y1) from line Ax + By + C = 0 is d = |A x1 + B y1 + C|/sqrt(A^2 + B^2). Here A = 3, B = -4, C = -26 and (x1, y1) = (3, -5). d = |3(3) - 4(-5) - 26|/sqrt(9 + 16) = |9 + 20 - 26|/sqrt25 = |3|/5 = 3/5.

d = |A x1 + B y1 + C|/sqrt(A^2 + B^2)

Marking-scheme points

  • ✓d = |A x1 + B y1 + C|/sqrt(A^2 + B^2)
  • ✓Numerator = |9 + 20 - 26| = 3; denominator = 5
  • ✓d = 3/5 units
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