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The questions your board exam loves to ask

800 most-asked Class 11 & 12 (+1 / +2) questions across Physics, Chemistry, Maths and Biology — each with a model answer and the exact marking-scheme points examiners reward. Revise smart, walk in calm.

800 board questions•Model answers•Marking-scheme points•Every chapter•CBSE · ISC · State boards

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ChemistryClass 113 marksmedium

States of Matter

A gas occupies 300 mL at 27 deg C. What volume will it occupy at 127 deg C if the pressure is kept constant?

Reveal model answer + marking points▾

Convert temperatures to Kelvin: T1 = 27 + 273 = 300 K, T2 = 127 + 273 = 400 K. By Charles's law V1/T1 = V2/T2, so V2 = V1 x T2/T1 = 300 x 400/300 = 400 mL.

V1/T1 = V2/T2

Marking-scheme points

  • ✓Convert to Kelvin: 300 K and 400 K
  • ✓V1/T1 = V2/T2 at constant pressure
  • ✓V2 = 300 x 400/300 = 400 mL
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ChemistryClass 112 markseasy

States of Matter

Write the ideal gas equation and give the value of the gas constant R in two units.

Reveal model answer + marking points▾

The ideal gas equation is PV = nRT, where P = pressure, V = volume, n = number of moles, T = absolute temperature and R = universal gas constant. R = 0.0821 L atm K^-1 mol^-1 = 8.314 J K^-1 mol^-1.

PV = nRT

Marking-scheme points

  • ✓PV = nRT
  • ✓R = 0.0821 L atm K^-1 mol^-1
  • ✓R = 8.314 J K^-1 mol^-1
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ChemistryClass 113 marksmedium

States of Matter

Calculate the volume occupied by 2 moles of an ideal gas at 300 K and a pressure of 2 atm. (R = 0.0821 L atm K^-1 mol^-1)

Reveal model answer + marking points▾

Using PV = nRT, V = nRT/P = (2 x 0.0821 x 300) / 2 = 49.26/2 = 24.63 L.

V = nRT / P

Marking-scheme points

  • ✓Use V = nRT/P
  • ✓Substitute n=2, R=0.0821, T=300, P=2
  • ✓V = 24.63 L
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