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The questions your board exam loves to ask
800 most-asked Class 11 & 12 (+1 / +2) questions across Physics, Chemistry, Maths and Biology — each with a model answer and the exact marking-scheme points examiners reward. Revise smart, walk in calm.
ChemistryClass 122 marksmedium
Amines
Why is aniline less basic than ethylamine (or ammonia)?
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Aniline is less basic than ethylamine (and than ammonia) because in aniline the lone pair of electrons on the nitrogen atom is delocalised (drawn) into the benzene ring by resonance. As a result the lone pair is less available for donation to a proton, so aniline accepts a proton less readily and is a weaker base. In ethylamine, the alkyl group has an electron-releasing (+I) effect that increases the electron density on nitrogen and makes the lone pair more available, so it is more basic.
Marking-scheme points
- ✓In aniline the N lone pair is delocalised into the ring (resonance)
- ✓Lone pair is less available for protonation -> weaker base
- ✓In ethylamine, +I effect of the alkyl group makes N more basic
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Amines
What is the coupling reaction of diazonium salts? Give one example.
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The coupling reaction is a reaction in which a diazonium salt reacts with an electron-rich aromatic compound such as phenol or an aromatic amine to form a brightly coloured azo compound (containing the -N=N- linkage). For example, benzenediazonium chloride reacts with phenol in a mildly alkaline medium to give p-hydroxyazobenzene (an orange dye). These coupling reactions are used to prepare a large number of azo dyes.
Marking-scheme points
- ✓Diazonium salt + phenol/aromatic amine -> coloured azo compound (-N=N-)
- ✓Example: benzenediazonium chloride + phenol -> p-hydroxyazobenzene
- ✓Used to make azo dyes
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Biomolecules
Classify carbohydrates into three types based on hydrolysis, with one example of each.
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Based on their behaviour on hydrolysis, carbohydrates are classified as: (1) monosaccharides - simple sugars that cannot be hydrolysed further into smaller units (e.g. glucose, fructose); (2) oligosaccharides - which give 2 to 10 monosaccharide units on hydrolysis, the most common being disaccharides (e.g. sucrose, which gives glucose and fructose, and maltose); and (3) polysaccharides - which give a large number of monosaccharide units on hydrolysis (e.g. starch, cellulose and glycogen).
Marking-scheme points
- ✓Monosaccharides: cannot be hydrolysed further (glucose, fructose)
- ✓Oligosaccharides (disaccharides): give 2-10 units (sucrose, maltose)
- ✓Polysaccharides: give many units (starch, cellulose)
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Biomolecules
Distinguish between reducing and non-reducing sugars with examples.
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Biomolecules
State two evidences that show the presence of an aldehyde group and an alcohol group in glucose.
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Biomolecules
State two differences between starch and cellulose.
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Biomolecules
Name and briefly describe the four levels of protein structure.
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Biomolecules
What are enzymes? State two of their characteristics.
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Biomolecules
How are vitamins classified? Name one deficiency disease caused by a lack of vitamin C and vitamin D.
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Biomolecules
State three differences between DNA and RNA.
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Relations and Functions
Define reflexive, symmetric and transitive relations. When is a relation called an equivalence relation?
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Relations and Functions
Define one-one (injective), onto (surjective) and bijective functions.
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Relations and Functions
If f(x) = x + 1 and g(x) = 2x, find (g o f)(x) and (f o g)(x).
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Inverse Trigonometric Functions
Find the principal values of sin inverse (1/2) and cos inverse (-1/2).
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Inverse Trigonometric Functions
Evaluate tan inverse (1) + cos inverse (1/2) + sin inverse (1/2).
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Inverse Trigonometric Functions
Prove that sin inverse (x) + cos inverse (x) = pi/2 for all x in [-1, 1].
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Inverse Trigonometric Functions
Find the value of cos inverse (cos(7pi/6)).
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Inverse Trigonometric Functions
Write the domain and principal value range of sin inverse (x) and tan inverse (x).
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Matrices
Define a diagonal matrix, a scalar matrix and an identity matrix.
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Matrices
Find the values of x and y if the matrix [[x + y, 2],[5, x - y]] equals [[6, 2],[5, 2]].
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