Board Boosters

The questions your board exam loves to ask

800 most-asked Class 11 & 12 (+1 / +2) questions across Physics, Chemistry, Maths and Biology — each with a model answer and the exact marking-scheme points examiners reward. Revise smart, walk in calm.

800 board questions•Model answers•Marking-scheme points•Every chapter•CBSE · ISC · State boards

56 questions · clear filters

MathsClass 122 markseasy

Relations and Functions

Define reflexive, symmetric and transitive relations. When is a relation called an equivalence relation?

Reveal model answer + marking points▾

A relation R on a set A is reflexive if (a, a) belongs to R for every a in A. It is symmetric if (a, b) in R implies (b, a) in R. It is transitive if (a, b) in R and (b, c) in R together imply (a, c) in R. A relation that is reflexive, symmetric and transitive at the same time is called an equivalence relation.

Marking-scheme points

  • ✓Reflexive: (a, a) in R for all a
  • ✓Symmetric: (a, b) in R => (b, a) in R
  • ✓Transitive: (a, b), (b, c) in R => (a, c) in R; all three => equivalence
Still unsure? Ask the AI tutor →
MathsClass 122 markseasy

Relations and Functions

Define one-one (injective), onto (surjective) and bijective functions.

Reveal model answer + marking points▾

A function f from A to B is one-one (injective) if distinct elements of A have distinct images, that is, f(x1) = f(x2) implies x1 = x2. It is onto (surjective) if every element of B has at least one pre-image in A, that is, the range of f equals the codomain B. A function that is both one-one and onto is called bijective (a one-to-one correspondence).

Marking-scheme points

  • ✓One-one: f(x1) = f(x2) => x1 = x2
  • ✓Onto: range = codomain (every element of B has a pre-image)
  • ✓Bijective: both one-one and onto
Still unsure? Ask the AI tutor →
MathsClass 122 marksmedium

Relations and Functions

If f(x) = x + 1 and g(x) = 2x, find (g o f)(x) and (f o g)(x).

Reveal model answer + marking points▾

(g o f)(x) means g(f(x)). So (g o f)(x) = g(f(x)) = g(x + 1) = 2(x + 1) = 2x + 2. (f o g)(x) means f(g(x)). So (f o g)(x) = f(g(x)) = f(2x) = 2x + 1. Note that (g o f)(x) is not equal to (f o g)(x), so composition of functions is not commutative in general.

(g o f)(x) = g(f(x))

Marking-scheme points

  • ✓(g o f)(x) = g(f(x)) = 2(x + 1) = 2x + 2
  • ✓(f o g)(x) = f(g(x)) = 2x + 1
  • ✓Composition is not commutative in general
Still unsure? Ask the AI tutor →
Page 1 of 3Next →

You are more ready than you feel.

One question at a time is how every topper started. Bookmark this, revise a few each day, and watch the fear shrink. And if a friend is stressing about boards — send this their way. You both win.