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The questions your board exam loves to ask

800 most-asked Class 11 & 12 (+1 / +2) questions across Physics, Chemistry, Maths and Biology — each with a model answer and the exact marking-scheme points examiners reward. Revise smart, walk in calm.

800 board questionsModel answersMarking-scheme pointsEvery chapterCBSE · ISC · State boards

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PhysicsClass 122 markseasy

Electric Charges and Fields

State Coulomb's law of electrostatics and write its mathematical form.

Reveal model answer + marking points

Coulomb's law states that the force of attraction or repulsion between two point charges is directly proportional to the product of the magnitudes of the charges and inversely proportional to the square of the distance between them, acting along the line joining them. Mathematically, F = k q1 q2 / r^2, where k = 1/(4 pi epsilon0) = 9 x 10^9 N m^2 C^-2 in free space.

F = k q1 q2 / r^2

Marking-scheme points

  • F is proportional to product of charges and to 1/r^2
  • F = k q1 q2 / r^2 along the line joining them
  • k = 1/(4 pi epsilon0) = 9 x 10^9 N m^2 C^-2
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PhysicsClass 122 markseasy

Electric Charges and Fields

Define electric field intensity at a point. State its SI unit.

Reveal model answer + marking points

The electric field intensity at a point is the force experienced by a unit positive test charge placed at that point. It is a vector quantity given by E = F/q0, where q0 is the small positive test charge. Its SI unit is newton per coulomb (N/C) or equivalently volt per metre (V/m).

E = F/q0

Marking-scheme points

  • E = force per unit positive test charge = F/q0
  • Vector quantity, directed along the force on a positive charge
  • SI unit: N/C or V/m
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PhysicsClass 122 marksmedium

Electric Charges and Fields

Derive the expression for the torque acting on an electric dipole placed in a uniform electric field.

Reveal model answer + marking points

When a dipole of moment p is placed in a uniform electric field E at an angle theta, the two charges experience equal and opposite forces qE, forming a couple. The magnitude of the torque = force x perpendicular distance = qE x (2a sin theta) = (q x 2a) E sin theta = pE sin theta. In vector form, torque = p x E. The torque tends to align the dipole with the field.

torque = pE sin theta = p x E

Marking-scheme points

  • Equal and opposite forces qE form a couple
  • Torque = pE sin theta (magnitude)
  • Vector form: torque = p x E; aligns dipole with field
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PhysicsClass 122 markseasy

Electrostatic Potential and Capacitance

Define electric potential at a point. State its SI unit and write the expression for the potential due to a point charge.

Reveal model answer + marking points

The electric potential at a point is the work done in bringing a unit positive charge from infinity to that point against the electric field. It is a scalar quantity and its SI unit is the volt (V), where 1 volt = 1 joule per coulomb. The potential due to a point charge Q at distance r is V = kQ/r = Q/(4 pi epsilon0 r).

V = kQ/r

Marking-scheme points

  • Work done per unit positive charge from infinity to the point
  • Scalar quantity; SI unit volt (1 V = 1 J/C)
  • V = kQ/r for a point charge
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PhysicsClass 122 marksmedium

Electrostatic Potential and Capacitance

Write the relation between electric field and electric potential. What does the negative sign indicate?

Reveal model answer + marking points

The electric field is the negative gradient of the electric potential: E = -dV/dr. This means the field points in the direction in which the potential decreases most rapidly. The negative sign indicates that the electric field is directed from a region of higher potential to a region of lower potential, that is, potential decreases along the direction of the field.

E = -dV/dr

Marking-scheme points

  • E = -dV/dr (field = negative potential gradient)
  • Field points towards decreasing potential
  • Negative sign: E directed from high to low potential
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PhysicsClass 122 markseasy

Electrostatic Potential and Capacitance

Define capacitance of a conductor. State its SI unit.

Reveal model answer + marking points

The capacitance of a conductor is the ratio of the charge given to it to the resulting rise in its potential: C = Q/V. It is a measure of the ability of the conductor to store charge. Its SI unit is the farad (F), where 1 farad = 1 coulomb per volt. Capacitance depends on the size and shape of the conductor and the surrounding medium.

C = Q/V

Marking-scheme points

  • C = Q/V (charge stored per unit potential)
  • SI unit: farad (1 F = 1 C/V)
  • Depends on size, shape and surrounding medium
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PhysicsClass 122 marksmedium

Electrostatic Potential and Capacitance

Write the expression for the energy stored in a charged capacitor in three equivalent forms.

Reveal model answer + marking points

The energy stored in a charged capacitor is the work done in charging it. It can be written in three equivalent forms: U = (1/2) C V^2 = (1/2) Q V = Q^2/(2C), where C is the capacitance, Q the charge and V the potential difference. This energy is stored in the electric field between the plates.

U = (1/2) C V^2 = (1/2) QV = Q^2/(2C)

Marking-scheme points

  • U = (1/2) C V^2
  • U = (1/2) Q V = Q^2/(2C)
  • Energy stored in the electric field between plates
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PhysicsClass 122 marksmedium

Electrostatic Potential and Capacitance

How does the introduction of a dielectric slab between the plates of a capacitor affect its capacitance? Explain.

Reveal model answer + marking points

When a dielectric of dielectric constant K is fully inserted between the plates, the capacitance increases K times: C = K C0, where C0 is the capacitance with air. This is because the dielectric gets polarised and sets up an internal field opposite to the applied field, reducing the net field and hence the potential difference for the same charge; since C = Q/V, a smaller V means a larger C.

C = K C0

Marking-scheme points

  • Dielectric increases capacitance: C = K C0
  • Dielectric polarises and reduces the net field
  • Lower V for same Q -> higher C
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PhysicsClass 122 markseasy

Current Electricity

State Ohm's law. Define resistance and give its SI unit.

Reveal model answer + marking points

Ohm's law states that, at constant temperature, the current flowing through a conductor is directly proportional to the potential difference across its ends, so V = IR, where R is a constant called the resistance. Resistance is the opposition offered by a conductor to the flow of current and is defined as R = V/I. Its SI unit is the ohm.

V = IR

Marking-scheme points

  • At constant temperature, V is proportional to I (V = IR)
  • Resistance R = V/I = opposition to current
  • SI unit: ohm
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PhysicsClass 122 marksmedium

Current Electricity

Define resistivity of a material. How does the resistance of a wire depend on its length and area of cross-section?

Reveal model answer + marking points

Resistivity (specific resistance) is the resistance of a conductor of unit length and unit area of cross-section; it depends on the material and temperature but not on its dimensions. The resistance of a wire is R = rho L/A, so it is directly proportional to its length L and inversely proportional to its area of cross-section A. The SI unit of resistivity is the ohm metre.

R = rho L/A

Marking-scheme points

  • Resistivity = resistance of unit length and unit area
  • R = rho L/A
  • R is proportional to L and inversely proportional to A
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PhysicsClass 122 marksmedium

Current Electricity

State Kirchhoff's two laws for electrical circuits.

Reveal model answer + marking points

Kirchhoff's junction (current) law states that the algebraic sum of currents meeting at a junction is zero, that is, the total current entering a junction equals the total current leaving it; it is based on conservation of charge. Kirchhoff's loop (voltage) law states that the algebraic sum of the changes in potential around any closed loop of a circuit is zero; it is based on conservation of energy.

sum(I) at junction = 0; sum(V) around loop = 0

Marking-scheme points

  • Junction law: sum of currents at a junction = 0 (charge conservation)
  • Loop law: sum of potential changes around a loop = 0 (energy conservation)
  • Used to analyse complex circuits
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PhysicsClass 122 marksmedium

Current Electricity

Write the effective emf and internal resistance when n identical cells are connected in series.

Reveal model answer + marking points

When n identical cells, each of emf E and internal resistance r, are connected in series (all in the same direction), the effective emf is n E and the total internal resistance is n r. The current through an external resistance R is I = n E/(R + n r). Series grouping is advantageous when the external resistance is much larger than the internal resistance.

I = nE/(R + nr)

Marking-scheme points

  • Series: effective emf = nE, internal resistance = nr
  • Current I = nE/(R + nr)
  • Useful when external R is much greater than internal r
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PhysicsClass 122 marksmedium

Current Electricity

How does the resistance of a metallic conductor vary with temperature? Write the relevant relation.

Reveal model answer + marking points

The resistance of a metallic conductor increases with a rise in temperature, because increased thermal motion of the atoms causes more frequent collisions of electrons, increasing the resistance. The relation is R(t) = R0 (1 + alpha (delta T)), where R0 is the resistance at the reference temperature, alpha is the temperature coefficient of resistance and delta T is the rise in temperature.

R = R0 (1 + alpha delta T)

Marking-scheme points

  • Resistance of a metal increases with temperature
  • More atomic vibration -> more electron collisions
  • R = R0 (1 + alpha delta T)
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PhysicsClass 122 markseasy

Moving Charges and Magnetism

Write the expression for the magnetic Lorentz force on a charge moving in a magnetic field. When is it maximum and when zero?

Reveal model answer + marking points

A charge q moving with velocity v in a magnetic field B experiences a magnetic force F = q v B sin theta, where theta is the angle between v and B; in vector form F = q(v x B). The force is maximum (F = qvB) when the charge moves perpendicular to the field (theta = 90 deg), and it is zero when the charge moves parallel or antiparallel to the field (theta = 0 or 180 deg). The force is always perpendicular to the velocity, so it does no work.

F = q v B sin theta

Marking-scheme points

  • F = q v B sin theta = q(v x B)
  • Maximum (qvB) when v perpendicular to B
  • Zero when v parallel to B; force does no work
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PhysicsClass 122 marksmedium

Moving Charges and Magnetism

State the Biot-Savart law for the magnetic field due to a current element.

Reveal model answer + marking points

The Biot-Savart law states that the magnetic field dB due to a small current element I dl at a point P at distance r is directly proportional to the current I, the length dl and the sine of the angle theta between the element and the line joining it to P, and inversely proportional to the square of the distance r. Mathematically, dB = (mu0/4 pi) (I dl sin theta)/r^2, and its direction is perpendicular to the plane containing dl and r.

dB = (mu0/4 pi)(I dl sin theta)/r^2

Marking-scheme points

  • dB proportional to I dl sin theta and to 1/r^2
  • dB = (mu0/4 pi)(I dl sin theta)/r^2
  • Direction perpendicular to plane of dl and r
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PhysicsClass 122 marksmedium

Moving Charges and Magnetism

Write the expression for the force per unit length between two long parallel current-carrying wires and use it to define the ampere.

Reveal model answer + marking points

Two long parallel wires separated by distance d carrying currents I1 and I2 experience a force per unit length F/L = (mu0 I1 I2)/(2 pi d); the force is attractive if the currents are in the same direction and repulsive if opposite. The ampere is defined as that steady current which, when maintained in two infinitely long parallel wires of negligible cross-section placed 1 metre apart in vacuum, produces a force of 2 x 10^-7 newton per metre of length between them.

F/L = mu0 I1 I2/(2 pi d)

Marking-scheme points

  • F/L = mu0 I1 I2/(2 pi d)
  • Same direction currents attract, opposite repel
  • 1 ampere gives 2 x 10^-7 N/m between wires 1 m apart
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PhysicsClass 122 markseasy

Magnetism and Matter

Write the expression for the magnetic dipole moment of a current-carrying loop. State its SI unit.

Reveal model answer + marking points

A current loop behaves as a magnetic dipole. The magnetic dipole moment of a coil of N turns each of area A carrying current I is m = N I A, and it is directed perpendicular to the plane of the loop (given by the right-hand rule). Its SI unit is ampere metre squared (A m^2). The torque on it in a field B is m x B.

m = N I A

Marking-scheme points

  • Magnetic moment m = N I A
  • Directed perpendicular to the plane of the loop
  • SI unit: ampere metre squared (A m^2)
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PhysicsClass 122 marksmedium

Magnetism and Matter

Distinguish between diamagnetic, paramagnetic and ferromagnetic substances with one example each.

Reveal model answer + marking points

Diamagnetic substances are weakly repelled by a magnetic field and move from stronger to weaker regions; they have a small negative susceptibility (e.g. bismuth, copper). Paramagnetic substances are weakly attracted by a magnetic field and have a small positive susceptibility (e.g. aluminium, sodium). Ferromagnetic substances are strongly attracted and can be permanently magnetised; they have a large positive susceptibility (e.g. iron, cobalt, nickel).

Marking-scheme points

  • Diamagnetic: weakly repelled, small negative susceptibility (bismuth)
  • Paramagnetic: weakly attracted, small positive susceptibility (aluminium)
  • Ferromagnetic: strongly attracted, large positive susceptibility (iron)
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PhysicsClass 122 markseasy

Magnetism and Matter

State any four properties of magnetic field lines.

Reveal model answer + marking points

(1) Magnetic field lines are continuous closed curves that pass from the south to the north pole inside the magnet and from the north to the south pole outside it. (2) The tangent drawn at any point on a field line gives the direction of the magnetic field at that point. (3) Two field lines never intersect each other (as the field can have only one direction at a point). (4) The lines are crowded where the field is strong and spread apart where it is weak.

Marking-scheme points

  • Continuous closed loops (S to N inside, N to S outside)
  • Tangent gives field direction; no two lines intersect
  • Crowded where field is strong
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PhysicsClass 122 marksmedium

Magnetism and Matter

Define magnetic susceptibility and relative permeability. Write the relation between them.

Reveal model answer + marking points

Magnetic susceptibility (chi) is the ratio of the intensity of magnetisation (M) produced in a material to the magnetising field (H): chi = M/H; it measures how easily a material can be magnetised. Relative permeability (mu_r) is the ratio of the permeability of the material to that of free space. The relation between them is mu_r = 1 + chi.

mu_r = 1 + chi

Marking-scheme points

  • Susceptibility chi = M/H (ease of magnetisation)
  • Relative permeability mu_r = mu/mu0
  • Relation: mu_r = 1 + chi
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