Board Boosters

The questions your board exam loves to ask

800 most-asked Class 11 & 12 (+1 / +2) questions across Physics, Chemistry, Maths and Biology — each with a model answer and the exact marking-scheme points examiners reward. Revise smart, walk in calm.

800 board questions•Model answers•Marking-scheme points•Every chapter•CBSE · ISC · State boards

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PhysicsClass 123 marksmedium

Alternating Current

Write the expression for the impedance of a series LCR circuit and the phase angle between voltage and current.

Reveal model answer + marking points▾

In a series LCR circuit connected to an AC source, the total opposition to current is called impedance Z, given by Z = sqrt(R^2 + (XL - XC)^2), where XL is the inductive reactance and XC is the capacitive reactance. The phase angle phi between the applied voltage and the current is given by tan(phi) = (XL - XC)/R. The current is I = V/Z.

Z = sqrt(R^2 + (XL - XC)^2)

Marking-scheme points

  • ✓Z = sqrt(R^2 + (XL - XC)^2)
  • ✓Phase angle: tan(phi) = (XL - XC)/R
  • ✓Current I = V/Z
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PhysicsClass 123 marksmedium

Alternating Current

What is resonance in a series LCR circuit? Derive the expression for the resonant frequency.

Reveal model answer + marking points▾

Resonance in a series LCR circuit occurs when the inductive reactance equals the capacitive reactance (XL = XC). At resonance the impedance is minimum (Z = R), the current is maximum, and the circuit behaves as purely resistive. The condition XL = XC gives omega L = 1/(omega C), so omega^2 = 1/(LC), and the resonant frequency f = 1/(2 pi sqrt(LC)). Such a circuit is used for tuning radios and televisions.

f = 1/(2 pi sqrt(LC))

Marking-scheme points

  • ✓Resonance when XL = XC (impedance minimum = R, current maximum)
  • ✓omega L = 1/(omega C) -> omega = 1/sqrt(LC)
  • ✓Resonant frequency f = 1/(2 pi sqrt(LC))
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PhysicsClass 123 marksmedium

Alternating Current

State the principle of a transformer and write the transformer equation. Distinguish step-up and step-down transformers.

Reveal model answer + marking points▾

A transformer works on the principle of mutual induction: an alternating current in the primary coil produces a changing flux that induces an emf in the secondary coil. For an ideal transformer, Vs/Vp = Ns/Np = Ip/Is, where V is voltage, N is number of turns and I is current. A step-up transformer has more turns in the secondary (Ns > Np) and increases the voltage; a step-down transformer has fewer turns in the secondary (Ns < Np) and decreases the voltage.

Vs/Vp = Ns/Np = Ip/Is

Marking-scheme points

  • ✓Works on mutual induction (needs AC)
  • ✓Vs/Vp = Ns/Np = Ip/Is (ideal transformer)
  • ✓Step-up: Ns > Np raises voltage; step-down: Ns < Np lowers it
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