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The questions your board exam loves to ask

800 most-asked Class 11 & 12 (+1 / +2) questions across Physics, Chemistry, Maths and Biology — each with a model answer and the exact marking-scheme points examiners reward. Revise smart, walk in calm.

800 board questions•Model answers•Marking-scheme points•Every chapter•CBSE · ISC · State boards

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PhysicsClass 123 marksmedium

Nuclei

State the radioactive decay law. What fraction of a radioactive sample remains after 3 half-lives?

Reveal model answer + marking points▾

The radioactive decay law states that the rate of decay of a radioactive sample is directly proportional to the number of undecayed nuclei present at that instant: N = N0 e^(-lambda t), where lambda is the decay constant. The half-life T is related to it by T = 0.693/lambda. After each half-life, half of the sample remains, so after 3 half-lives the fraction remaining = (1/2)^3 = 1/8 of the original sample.

N = N0 (1/2)^(t/T)

Marking-scheme points

  • ✓Decay law: N = N0 e^(-lambda t); half-life T = 0.693/lambda
  • ✓Fraction after n half-lives = (1/2)^n
  • ✓After 3 half-lives: (1/2)^3 = 1/8 remains
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PhysicsClass 123 marksmedium

Semiconductor Electronics

Explain how a p-n junction diode works as a half-wave rectifier.

Reveal model answer + marking points▾

A rectifier converts alternating current (AC) into direct current (DC). In a half-wave rectifier, a single diode is connected in series with the AC source and a load resistor. During the positive half-cycle of the AC input, the diode is forward biased and conducts, so current flows through the load. During the negative half-cycle, the diode is reverse biased and does not conduct, so no current flows. As a result, output is obtained only during one half of each cycle, giving a pulsating DC. Its efficiency is low because half the input is wasted.

Marking-scheme points

  • ✓Rectifier converts AC into DC; uses one diode
  • ✓Positive half-cycle: diode forward biased -> conducts
  • ✓Negative half-cycle: diode reverse biased -> no output (pulsating DC)
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PhysicsClass 123 marksmedium

Semiconductor Electronics

Explain the working of a full-wave rectifier using two diodes.

Reveal model answer + marking points▾

A full-wave rectifier converts both halves of the AC input into DC. It uses two diodes with a centre-tapped transformer and a load resistor. During the positive half-cycle, one diode is forward biased and conducts while the other is reverse biased; during the negative half-cycle, the second diode conducts while the first does not. In both half-cycles, the current through the load flows in the same direction, so output is obtained during the whole cycle. This gives a smoother, more efficient pulsating DC than a half-wave rectifier.

Marking-scheme points

  • ✓Uses two diodes and a centre-tapped transformer
  • ✓Each diode conducts during one half-cycle
  • ✓Current through load is in the same direction for both halves (full-wave DC)
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