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800 most-asked Class 11 & 12 (+1 / +2) questions across Physics, Chemistry, Maths and Biology — each with a model answer and the exact marking-scheme points examiners reward. Revise smart, walk in calm.

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PhysicsClass 123 marksmedium

Electromagnetic Induction

Derive the expression for the motional emf induced in a conducting rod moving in a uniform magnetic field.

Reveal model answer + marking points

Consider a conducting rod of length l moving with velocity v perpendicular to a uniform magnetic field B. In time dt the rod sweeps an area dA = l (v dt), so the change in flux is d(flux) = B dA = B l v dt. By Faraday's law, the induced emf e = d(flux)/dt = B l v. Alternatively, the free electrons in the rod experience a force qvB that pushes them to one end, setting up an emf e = B v l across the rod.

e = B l v

Marking-scheme points

  • Area swept in dt = l v dt, so d(flux) = B l v dt
  • e = d(flux)/dt = B l v
  • Also from force on electrons qvB
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PhysicsClass 122 marksmedium

Electromagnetic Induction

Define self-inductance of a coil. State its SI unit.

Reveal model answer + marking points

Self-inductance is the property of a coil by virtue of which it opposes any change in the current flowing through it, by inducing an opposing emf (back emf). It is defined as the flux linkage per unit current (N flux = L I) or from the induced emf e = -L (dI/dt), where L is the self-inductance. Its SI unit is the henry (H).

e = -L dI/dt

Marking-scheme points

  • Coil opposes change in its own current (back emf)
  • N flux = L I, or e = -L dI/dt
  • SI unit: henry (H)
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PhysicsClass 122 marksmedium

Electromagnetic Induction

Define mutual inductance between two coils. On what factors does it depend?

Reveal model answer + marking points

Mutual inductance is the property by which a change of current in one coil (primary) induces an emf in a neighbouring coil (secondary) due to the change in flux linkage. It is defined by e2 = -M (dI1/dt), where M is the mutual inductance, whose SI unit is the henry. It depends on the number of turns of the coils, their geometry (area and length), the distance and orientation between them, and the permeability of the core material.

e2 = -M dI1/dt

Marking-scheme points

  • Change of current in one coil induces emf in another
  • e2 = -M dI1/dt (SI unit henry)
  • Depends on turns, geometry, separation and core material
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PhysicsClass 123 marksmedium

Electromagnetic Induction

A coil of 500 turns has the magnetic flux through it changing from 0.01 Wb to 0.05 Wb in 0.1 s. Calculate the induced emf.

Reveal model answer + marking points

Given N = 500, initial flux = 0.01 Wb, final flux = 0.05 Wb, so change in flux = 0.05 - 0.01 = 0.04 Wb, and time = 0.1 s. The induced emf (magnitude) = N (change in flux)/time = 500 x 0.04/0.1 = 500 x 0.4 = 200 V.

e = N (change in flux)/time

Marking-scheme points

  • Change in flux = 0.05 - 0.01 = 0.04 Wb
  • e = N (change in flux)/time = 500 x 0.04/0.1
  • e = 200 V
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PhysicsClass 122 marksmedium

Electromagnetic Induction

What are eddy currents? State two applications.

Reveal model answer + marking points

Eddy currents are the circulating induced currents produced in the body of a conductor when the magnetic flux linked with it changes. They flow in closed loops within the conductor and generally cause heating and energy loss. Applications: they are used in induction furnaces (to melt metals by the heat produced), in electromagnetic braking of trains, in electric (induction) meters, and in induction cooktops. Laminating the cores of transformers reduces energy loss due to eddy currents.

Marking-scheme points

  • Circulating induced currents in a conductor due to changing flux
  • Cause heating and energy loss
  • Applications: induction furnace, electromagnetic braking, induction cooktop
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PhysicsClass 122 markseasy

Alternating Current

Define the root mean square (RMS) value of alternating current. Write its relation with the peak value.

Reveal model answer + marking points

The RMS (root mean square) value of an alternating current is that value of steady direct current which produces the same heating effect in a given resistance in the same time as the alternating current does. For a sinusoidal current of peak value I0, the RMS value is Irms = I0/sqrt(2) = 0.707 I0. Similarly Vrms = V0/sqrt(2). AC meters read RMS values.

Irms = I0/sqrt(2)

Marking-scheme points

  • RMS = equivalent DC giving the same heating effect
  • Irms = I0/sqrt(2) = 0.707 I0
  • Vrms = V0/sqrt(2); AC meters read RMS
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PhysicsClass 122 marksmedium

Alternating Current

Define inductive reactance and capacitive reactance. Write their expressions.

Reveal model answer + marking points

Inductive reactance is the opposition offered by an inductor to the flow of alternating current, given by XL = omega L = 2 pi f L; it increases with frequency. Capacitive reactance is the opposition offered by a capacitor to alternating current, given by XC = 1/(omega C) = 1/(2 pi f C); it decreases with frequency. Both are measured in ohm. For direct current (f = 0), XL = 0 and XC is infinite.

XL = omega L; XC = 1/(omega C)

Marking-scheme points

  • Inductive reactance XL = omega L = 2 pi f L (increases with f)
  • Capacitive reactance XC = 1/(omega C) (decreases with f)
  • Both measured in ohm
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PhysicsClass 123 marksmedium

Alternating Current

Write the expression for the impedance of a series LCR circuit and the phase angle between voltage and current.

Reveal model answer + marking points

In a series LCR circuit connected to an AC source, the total opposition to current is called impedance Z, given by Z = sqrt(R^2 + (XL - XC)^2), where XL is the inductive reactance and XC is the capacitive reactance. The phase angle phi between the applied voltage and the current is given by tan(phi) = (XL - XC)/R. The current is I = V/Z.

Z = sqrt(R^2 + (XL - XC)^2)

Marking-scheme points

  • Z = sqrt(R^2 + (XL - XC)^2)
  • Phase angle: tan(phi) = (XL - XC)/R
  • Current I = V/Z
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PhysicsClass 123 marksmedium

Alternating Current

What is resonance in a series LCR circuit? Derive the expression for the resonant frequency.

Reveal model answer + marking points

Resonance in a series LCR circuit occurs when the inductive reactance equals the capacitive reactance (XL = XC). At resonance the impedance is minimum (Z = R), the current is maximum, and the circuit behaves as purely resistive. The condition XL = XC gives omega L = 1/(omega C), so omega^2 = 1/(LC), and the resonant frequency f = 1/(2 pi sqrt(LC)). Such a circuit is used for tuning radios and televisions.

f = 1/(2 pi sqrt(LC))

Marking-scheme points

  • Resonance when XL = XC (impedance minimum = R, current maximum)
  • omega L = 1/(omega C) -> omega = 1/sqrt(LC)
  • Resonant frequency f = 1/(2 pi sqrt(LC))
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PhysicsClass 122 marksmedium

Alternating Current

Define power factor of an AC circuit. What is wattless current?

Reveal model answer + marking points

The average power in an AC circuit is P = Vrms Irms cos(phi), where cos(phi) is called the power factor and phi is the phase difference between voltage and current. Thus the power factor is the ratio of true power to apparent power (cos phi = R/Z). Wattless current is the component of the AC current (Irms sin phi) that is 90 degrees out of phase with the voltage; it consumes no average power, so it is called the idle or wattless current.

P = Vrms Irms cos(phi)

Marking-scheme points

  • Power P = Vrms Irms cos(phi); cos(phi) = power factor = R/Z
  • Ratio of true power to apparent power
  • Wattless current (Irms sin phi) consumes no average power
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PhysicsClass 123 marksmedium

Alternating Current

State the principle of a transformer and write the transformer equation. Distinguish step-up and step-down transformers.

Reveal model answer + marking points

A transformer works on the principle of mutual induction: an alternating current in the primary coil produces a changing flux that induces an emf in the secondary coil. For an ideal transformer, Vs/Vp = Ns/Np = Ip/Is, where V is voltage, N is number of turns and I is current. A step-up transformer has more turns in the secondary (Ns > Np) and increases the voltage; a step-down transformer has fewer turns in the secondary (Ns < Np) and decreases the voltage.

Vs/Vp = Ns/Np = Ip/Is

Marking-scheme points

  • Works on mutual induction (needs AC)
  • Vs/Vp = Ns/Np = Ip/Is (ideal transformer)
  • Step-up: Ns > Np raises voltage; step-down: Ns < Np lowers it
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PhysicsClass 123 marksmedium

Alternating Current

A step-down transformer converts 2200 V to 220 V. If the primary has 5000 turns, find the number of turns in the secondary.

Reveal model answer + marking points

For an ideal transformer, Ns/Np = Vs/Vp. Given Vp = 2200 V, Vs = 220 V, Np = 5000. So Ns = Np x (Vs/Vp) = 5000 x (220/2200) = 5000 x 0.1 = 500 turns. Since the secondary has fewer turns than the primary, it is a step-down transformer, as expected.

Ns/Np = Vs/Vp

Marking-scheme points

  • Ns/Np = Vs/Vp
  • Ns = 5000 x (220/2200) = 5000 x 0.1
  • Ns = 500 turns
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PhysicsClass 122 marksmedium

Electromagnetic Waves

What is displacement current? How did it complete Ampere's law?

Reveal model answer + marking points

Displacement current is the current that arises due to a changing electric field (or changing electric flux) between the plates of a capacitor, even though no charge actually flows across the gap. It is given by Id = epsilon0 (d(electric flux)/dt). Maxwell introduced it to make Ampere's law consistent while charging a capacitor: the total current (conduction current plus displacement current) is continuous, so the modified Ampere-Maxwell law is the integral of B.dl = mu0 (I + Id).

Id = epsilon0 d(electric flux)/dt

Marking-scheme points

  • Current due to a changing electric field/flux (no charge flows)
  • Id = epsilon0 d(electric flux)/dt
  • Makes conduction + displacement current continuous (Ampere-Maxwell law)
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PhysicsClass 122 markseasy

Electromagnetic Waves

State any four properties of electromagnetic waves.

Reveal model answer + marking points

(1) Electromagnetic waves are transverse in nature, with the electric field E and magnetic field B oscillating perpendicular to each other and to the direction of propagation. (2) They do not require a material medium and can travel through vacuum. (3) They travel through vacuum with the speed of light, c = 3 x 10^8 m/s. (4) They carry energy and momentum, and the ratio of the amplitudes of E and B equals c (E0/B0 = c).

c = E0/B0

Marking-scheme points

  • Transverse; E and B perpendicular to each other and to propagation
  • Do not need a medium; travel through vacuum
  • Speed c = 3 x 10^8 m/s; E0/B0 = c
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PhysicsClass 123 marksmedium

Electromagnetic Waves

Name the parts of the electromagnetic spectrum in order of increasing frequency and give one use of each.

Reveal model answer + marking points

In order of increasing frequency (decreasing wavelength): (1) Radio waves - used in radio and television communication. (2) Microwaves - used in radar and microwave ovens. (3) Infrared - used in remote controls and thermal imaging. (4) Visible light - used for vision and photography. (5) Ultraviolet - used to sterilise water and in detecting forgery. (6) X-rays - used in medical imaging and detecting fractures. (7) Gamma rays - used in cancer treatment (radiotherapy).

Marking-scheme points

  • Order of increasing frequency: radio, microwave, infrared, visible, UV, X-ray, gamma
  • Radio: communication; microwave: radar/oven; infrared: remote control
  • X-ray: medical imaging; gamma ray: cancer treatment
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PhysicsClass 122 marksmedium

Electromagnetic Waves

Write the expression for the speed of electromagnetic waves in vacuum in terms of mu0 and epsilon0.

Reveal model answer + marking points

The speed of electromagnetic waves in vacuum is given by c = 1/sqrt(mu0 epsilon0), where mu0 is the permeability and epsilon0 the permittivity of free space. Substituting mu0 = 4 pi x 10^-7 and epsilon0 = 8.85 x 10^-12 gives c = 3 x 10^8 m/s, which equals the measured speed of light, showing that light is an electromagnetic wave. In a medium the speed is v = 1/sqrt(mu epsilon).

c = 1/sqrt(mu0 epsilon0)

Marking-scheme points

  • c = 1/sqrt(mu0 epsilon0)
  • Gives 3 x 10^8 m/s (speed of light)
  • Shows light is an electromagnetic wave
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PhysicsClass 122 markseasy

Ray Optics and Optical Instruments

Write the mirror formula and the expression for linear magnification produced by a spherical mirror.

Reveal model answer + marking points

The mirror formula relates the object distance u, image distance v and focal length f of a spherical mirror: 1/v + 1/u = 1/f. The linear magnification is m = -v/u = height of image/height of object. The focal length f = R/2, where R is the radius of curvature. The New Cartesian sign convention is used for the distances.

1/v + 1/u = 1/f

Marking-scheme points

  • Mirror formula: 1/v + 1/u = 1/f
  • Magnification m = -v/u = h(image)/h(object)
  • f = R/2; use sign convention
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PhysicsClass 123 marksmedium

Ray Optics and Optical Instruments

An object is placed 20 cm in front of a concave mirror of focal length 15 cm. Find the position and nature of the image.

Reveal model answer + marking points

Using the sign convention, u = -20 cm and f = -15 cm. From the mirror formula 1/v = 1/f - 1/u = 1/(-15) - 1/(-20) = -1/15 + 1/20 = (-4 + 3)/60 = -1/60, so v = -60 cm. The magnification m = -v/u = -(-60)/(-20) = -3. The image is real (v negative), inverted (m negative) and magnified three times, formed 60 cm in front of the mirror.

1/v + 1/u = 1/f

Marking-scheme points

  • u = -20 cm, f = -15 cm; 1/v = 1/f - 1/u
  • v = -60 cm; m = -v/u = -3
  • Image is real, inverted and magnified 3 times
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PhysicsClass 122 markseasy

Ray Optics and Optical Instruments

State the laws of refraction of light (Snell's law).

Reveal model answer + marking points

The laws of refraction are: (1) The incident ray, the refracted ray and the normal at the point of incidence all lie in the same plane. (2) For a given pair of media and a given colour of light, the ratio of the sine of the angle of incidence to the sine of the angle of refraction is a constant, called the refractive index: sin i/sin r = n (Snell's law). Refraction occurs because light travels at different speeds in different media.

sin i/sin r = n

Marking-scheme points

  • Incident ray, refracted ray and normal lie in one plane
  • Snell's law: sin i/sin r = n (constant)
  • Caused by change of speed of light between media
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PhysicsClass 123 marksmedium

Ray Optics and Optical Instruments

What is total internal reflection? State the conditions required for it and one application.

Reveal model answer + marking points

Total internal reflection is the phenomenon in which a ray of light travelling from a denser to a rarer medium is completely reflected back into the denser medium when the angle of incidence exceeds a certain angle called the critical angle. Conditions: (1) light must travel from a denser to a rarer medium; (2) the angle of incidence must be greater than the critical angle C, where sin C = 1/n. Applications: optical fibres, sparkling of diamonds, and mirages.

sin C = 1/n

Marking-scheme points

  • Complete reflection back into the denser medium
  • Conditions: denser to rarer medium and angle of incidence > critical angle
  • sin C = 1/n; application: optical fibres
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