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ChemistryClass 112 markseasy

Some Basic Concepts of Chemistry

State the law of conservation of mass and the law of definite proportions.

Reveal model answer + marking points

Law of conservation of mass: matter can neither be created nor destroyed in a chemical reaction; the total mass of reactants equals the total mass of products. Law of definite proportions: a given chemical compound always contains the same elements combined in the same fixed proportion by mass, irrespective of its source or method of preparation.

Marking-scheme points

  • Conservation of mass: mass of reactants = mass of products
  • Definite proportions: fixed ratio of elements by mass
  • Example: water always 1:8 H:O by mass
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ChemistryClass 112 markseasy

Some Basic Concepts of Chemistry

Calculate the number of moles present in 11 g of carbon dioxide (CO2).

Reveal model answer + marking points

Molar mass of CO2 = 12 + 2(16) = 44 g/mol. Number of moles = given mass / molar mass = 11 / 44 = 0.25 mol.

n = m / M

Marking-scheme points

  • Molar mass of CO2 = 44 g/mol
  • moles = mass / molar mass
  • n = 11/44 = 0.25 mol
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ChemistryClass 112 markseasy

Some Basic Concepts of Chemistry

Define one mole and state the value of Avogadro's number.

Reveal model answer + marking points

One mole is the amount of a substance that contains as many elementary entities (atoms, molecules, ions) as there are atoms in exactly 12 g of carbon-12. This number of entities is Avogadro's number, N_A = 6.022 x 10^23 mol^-1.

1 mol = 6.022 x 10^23 particles

Marking-scheme points

  • Mole = amount containing N_A entities
  • Reference: atoms in 12 g of C-12
  • N_A = 6.022 x 10^23 per mole
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ChemistryClass 112 markseasy

Some Basic Concepts of Chemistry

Define molarity and molality. State their units.

Reveal model answer + marking points

Molarity (M) is the number of moles of solute dissolved per litre of solution; unit mol/L (or M). Molality (m) is the number of moles of solute dissolved per kilogram of solvent; unit mol/kg (or m). Molality is independent of temperature since it uses mass, whereas molarity changes with temperature because volume changes.

M = n_solute / V(L); m = n_solute / mass_solvent(kg)

Marking-scheme points

  • Molarity = moles of solute / litre of solution (mol/L)
  • Molality = moles of solute / kg of solvent (mol/kg)
  • Molality is temperature independent
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ChemistryClass 112 marksmedium

Some Basic Concepts of Chemistry

Define mole fraction and mass percent of a component in a solution.

Reveal model answer + marking points

Mole fraction of a component = number of moles of that component / total number of moles of all components in the solution; it is dimensionless and the sum of mole fractions equals 1. Mass percent of a component = (mass of the component / total mass of solution) x 100.

x_A = n_A / n_total; mass% = (mass component / total mass) x 100

Marking-scheme points

  • Mole fraction x_A = n_A / (n_A + n_B); sum = 1
  • Dimensionless quantity
  • Mass percent = (mass of component / total mass) x 100
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ChemistryClass 112 marksmedium

Structure of Atom

Calculate the energy of a photon of light of wavelength 4000 Angstrom. (h = 6.626 x 10^-34 J s, c = 3 x 10^8 m/s)

Reveal model answer + marking points

Wavelength = 4000 Angstrom = 4000 x 10^-10 m = 4 x 10^-7 m. Energy E = hc/lambda = (6.626 x 10^-34 x 3 x 10^8) / (4 x 10^-7) = 1.988 x 10^-25 / 4 x 10^-7 = 4.97 x 10^-19 J.

E = hc / lambda

Marking-scheme points

  • Convert 4000 Angstrom = 4 x 10^-7 m
  • E = hc/lambda
  • E = 4.97 x 10^-19 J
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ChemistryClass 112 markseasy

Structure of Atom

State Heisenberg's uncertainty principle and give its mathematical form.

Reveal model answer + marking points

It is impossible to determine simultaneously and with absolute accuracy both the position and the momentum (or velocity) of a microscopic particle such as an electron. The product of the uncertainties in position (delta x) and momentum (delta p) is at least of the order of h/4pi.

delta x . delta p >= h / 4pi

Marking-scheme points

  • Cannot measure position and momentum exactly at once
  • Applies to microscopic particles like electrons
  • delta x . delta p >= h/4pi
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ChemistryClass 112 marksmedium

Structure of Atom

Calculate the wave number of the spectral line when an electron in a hydrogen atom jumps from n = 3 to n = 2. (Rydberg constant R = 1.097 x 10^7 m^-1)

Reveal model answer + marking points

Wave number (nu bar) = R (1/n1^2 - 1/n2^2) = 1.097 x 10^7 (1/2^2 - 1/3^2) = 1.097 x 10^7 (1/4 - 1/9) = 1.097 x 10^7 x (5/36) = 1.523 x 10^6 m^-1. This is the H-alpha line of the Balmer series.

nu bar = R (1/n1^2 - 1/n2^2)

Marking-scheme points

  • nu bar = R(1/n1^2 - 1/n2^2), n1=2, n2=3
  • 1/4 - 1/9 = 5/36
  • nu bar = 1.523 x 10^6 m^-1 (Balmer series)
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ChemistryClass 112 markseasy

Structure of Atom

State Pauli's exclusion principle and Hund's rule of maximum multiplicity.

Reveal model answer + marking points

Pauli's exclusion principle: no two electrons in an atom can have the same set of all four quantum numbers; an orbital can hold at most two electrons with opposite spins. Hund's rule of maximum multiplicity: electron pairing in orbitals of the same subshell (degenerate orbitals) does not occur until each orbital is singly occupied, and all singly filled orbitals have parallel spin.

Marking-scheme points

  • Pauli: no two electrons share all four quantum numbers
  • Max 2 electrons per orbital, opposite spins
  • Hund: singly fill degenerate orbitals first, parallel spins
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ChemistryClass 112 markseasy

Structure of Atom

State the Aufbau principle and the (n + l) rule for filling of orbitals.

Reveal model answer + marking points

Aufbau principle: in the ground state of an atom, electrons are filled into orbitals in order of increasing energy, i.e. the lowest energy orbital is filled first. (n + l) rule: the orbital with the lower (n + l) value has lower energy and is filled first; if two orbitals have the same (n + l) value, the one with the lower n is filled first (e.g. 4s (n+l=4) is filled before 3d (n+l=5)).

energy order by increasing (n + l)

Marking-scheme points

  • Fill lowest energy orbitals first
  • Lower (n + l) = lower energy = filled first
  • Equal (n+l): lower n filled first (4s before 3d)
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ChemistryClass 112 markseasy

Classification of Elements and Periodicity

State the modern periodic law. How does it differ from Mendeleev's periodic law?

Reveal model answer + marking points

Modern periodic law: the physical and chemical properties of elements are a periodic function of their atomic numbers. Mendeleev's law was based on atomic mass, whereas the modern law is based on atomic number (number of protons), which removed anomalies such as the position of argon and potassium.

Marking-scheme points

  • Properties are periodic function of atomic number
  • Mendeleev: based on atomic mass
  • Atomic number basis removes mass-order anomalies
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ChemistryClass 112 marksmedium

Classification of Elements and Periodicity

Why is the first ionization enthalpy of nitrogen greater than that of oxygen?

Reveal model answer + marking points

Nitrogen has the configuration 1s2 2s2 2p3 with a half-filled 2p subshell, which is extra stable due to symmetry and exchange energy, so removing an electron requires more energy. Oxygen (1s2 2s2 2p4) has one paired electron in 2p; removing it relieves electron-electron repulsion and gives a stable half-filled configuration, so less energy is needed. Hence IE1 of nitrogen > oxygen.

Marking-scheme points

  • N has stable half-filled 2p3 configuration
  • O 2p4 has electron-pair repulsion, easier to remove
  • So IE1(N) > IE1(O)
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ChemistryClass 112 markshard

Classification of Elements and Periodicity

Why is the electron gain enthalpy of chlorine more negative than that of fluorine?

Reveal model answer + marking points

Although fluorine is smaller, its 2p subshell is very compact, so the incoming electron experiences strong inter-electronic repulsion from the already crowded 2p electrons. In chlorine, the larger 3p subshell accommodates the incoming electron with less repulsion, so more energy is released. Hence chlorine has a more negative (more exothermic) electron gain enthalpy than fluorine.

Marking-scheme points

  • F is small, compact 2p -> high electron-electron repulsion
  • Cl larger 3p -> less repulsion for incoming electron
  • So electron gain enthalpy of Cl is more negative
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ChemistryClass 112 markseasy

Classification of Elements and Periodicity

Define electronegativity. How does it vary across a period and down a group?

Reveal model answer + marking points

Electronegativity is the tendency of an atom in a molecule to attract the shared pair of electrons in a covalent bond towards itself. It increases across a period (as size decreases and nuclear charge increases) and decreases down a group (as size increases). Fluorine is the most electronegative element. The Pauling scale is commonly used.

Marking-scheme points

  • Tendency to attract bonded (shared) electrons
  • Increases across a period, decreases down a group
  • F is most electronegative; Pauling scale
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ChemistryClass 112 marksmedium

Classification of Elements and Periodicity

Arrange the isoelectronic species O2-, F-, Na+ and Mg2+ in increasing order of ionic radius. Justify.

Reveal model answer + marking points

All four species have 10 electrons (isoelectronic). For isoelectronic species, the greater the nuclear charge (number of protons), the smaller the radius. Nuclear charges: O2- (8), F- (9), Na+ (11), Mg2+ (12). Increasing order of radius: Mg2+ < Na+ < F- < O2-.

Marking-scheme points

  • All are isoelectronic (10 electrons)
  • More protons -> smaller radius
  • Order: Mg2+ < Na+ < F- < O2-
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ChemistryClass 112 markseasy

Chemical Bonding and Molecular Structure

Distinguish between an ionic bond and a covalent bond with one example each.

Reveal model answer + marking points

An ionic (electrovalent) bond is formed by the complete transfer of one or more electrons from one atom to another, producing oppositely charged ions held by electrostatic attraction (e.g. NaCl). A covalent bond is formed by the mutual sharing of electron pairs between atoms (e.g. H2 or Cl2). Ionic bonds form between metals and non-metals; covalent bonds form between non-metals.

Marking-scheme points

  • Ionic: complete transfer of electrons, e.g. NaCl
  • Covalent: sharing of electron pairs, e.g. H2
  • Ionic = metal + non-metal; covalent = non-metals
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ChemistryClass 112 marksmedium

Chemical Bonding and Molecular Structure

Why is the bond angle of H2O (104.5 deg) less than that of NH3 (107 deg)?

Reveal model answer + marking points

Both molecules are based on sp3 hybridisation with an ideal angle of 109.5 deg. NH3 has one lone pair, while H2O has two lone pairs. Lone pair-lone pair repulsion is stronger than lone pair-bond pair repulsion, and water has an extra lone pair, so its bond pairs are pushed closer together. Hence the bond angle of H2O (104.5 deg) is smaller than that of NH3 (107 deg).

Marking-scheme points

  • Both sp3, ideal 109.5 deg
  • NH3 has 1 lone pair; H2O has 2 lone pairs
  • More lone pairs -> greater repulsion -> smaller angle
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ChemistryClass 112 marksmedium

Chemical Bonding and Molecular Structure

Calculate the bond order of the nitrogen molecule (N2) using molecular orbital theory.

Reveal model answer + marking points

N2 has 14 electrons. Number of bonding electrons Nb = 10 and antibonding electrons Na = 4. Bond order = (Nb - Na)/2 = (10 - 4)/2 = 3. This corresponds to a nitrogen-nitrogen triple bond, which explains the very high stability and bond dissociation energy of N2.

Bond order = (Nb - Na)/2

Marking-scheme points

  • N2 has 14 electrons; Nb = 10, Na = 4
  • Bond order = (10 - 4)/2 = 3
  • Triple bond -> very stable molecule
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ChemistryClass 112 markseasy

Chemical Bonding and Molecular Structure

What is a coordinate (dative) bond? Explain with the example of the ammonium ion.

Reveal model answer + marking points

A coordinate bond is a covalent bond in which the shared pair of electrons is contributed by only one of the two bonded atoms (the donor). In the ammonium ion (NH4+), nitrogen in NH3 has a lone pair which it donates to a proton (H+) that has no electrons, forming the fourth N-H bond as a coordinate bond. Once formed, all four N-H bonds are identical.

NH3 + H+ -> NH4+

Marking-scheme points

  • Both shared electrons come from one atom (donor)
  • NH3 nitrogen lone pair donated to H+
  • All four N-H bonds become equivalent in NH4+
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ChemistryClass 112 marksmedium

Chemical Bonding and Molecular Structure

What is a hydrogen bond? State the conditions for its formation and its two types.

Reveal model answer + marking points

A hydrogen bond is a weak electrostatic attraction between a hydrogen atom covalently bonded to a highly electronegative atom (F, O or N) and the lone pair of another electronegative atom. Conditions: hydrogen must be attached to a small, highly electronegative atom. Types: intermolecular hydrogen bonding (between different molecules, e.g. in water and HF) and intramolecular hydrogen bonding (within the same molecule, e.g. o-nitrophenol).

Marking-scheme points

  • Attraction of H (bonded to F/O/N) with lone pair on another electronegative atom
  • Needs H on small, highly electronegative atom
  • Types: intermolecular and intramolecular
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