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The questions your board exam loves to ask
800 most-asked Class 11 & 12 (+1 / +2) questions across Physics, Chemistry, Maths and Biology — each with a model answer and the exact marking-scheme points examiners reward. Revise smart, walk in calm.
PhysicsClass 112 markseasy
Mechanical Properties of Solids
Name the three moduli of elasticity and state what each measures.
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Young's modulus (Y) measures resistance to change in length (longitudinal stress/strain). Bulk modulus (B) measures resistance to change in volume (volume stress/strain) under uniform pressure. Shear (rigidity) modulus (G) measures resistance to change in shape (shearing stress/strain).
Marking-scheme points
- ✓Young's Y: change in length
- ✓Bulk B: change in volume
- ✓Shear/rigidity G: change in shape
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Thermal Properties of Matter
State Stefan's law and Wien's displacement law of black-body radiation.
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Stefan's (Stefan-Boltzmann) law: the total energy radiated per unit area per unit time by a black body is proportional to the fourth power of its absolute temperature, E = sigma T^4. Wien's displacement law: the wavelength at which the emission is maximum is inversely proportional to the absolute temperature, lambda_max * T = constant (= 2.9 x 10^-3 m K).
E = sigma T^4 ; lambda_max T = b
Marking-scheme points
- ✓Stefan: E = sigma T^4
- ✓Wien: lambda_max T = constant
- ✓Hotter body -> shorter peak wavelength
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Kinetic Theory
Define mean free path of a gas molecule. State two factors it depends on.
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The mean free path is the average distance a gas molecule travels between two successive collisions. It increases when the number density of molecules is low and when the molecular diameter is small; that is, it is inversely proportional to the number density and to the square of the molecular diameter.
lambda = 1 / (sqrt(2) pi d^2 n)
Marking-scheme points
- ✓Average distance between collisions
- ✓Inversely proportional to number density
- ✓Inversely proportional to (diameter)^2
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System of Particles and Rotational Motion
Define the centre of mass of a system of particles. Write its position for a two-particle system.
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The centre of mass is the point at which the entire mass of the system can be considered to be concentrated, and where an applied external force produces the same acceleration as on the whole system. For two particles of masses m1 and m2 at positions x1 and x2, x_cm = (m1 x1 + m2 x2) / (m1 + m2).
x_cm = (m1 x1 + m2 x2) / (m1 + m2)
Marking-scheme points
- ✓Point where total mass seems concentrated
- ✓Moves as if all mass and external force act there
- ✓x_cm = (m1 x1 + m2 x2)/(m1 + m2)
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Gravitation
How does the acceleration due to gravity vary with depth below the Earth's surface? What is its value at the centre?
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With depth d, g decreases as g' = g (1 - d/R), assuming uniform density, because only the mass within the smaller inner sphere attracts the body. At the centre (d = R) the value becomes zero, since the mass is symmetrically distributed all around.
g' = g (1 - d/R)
Marking-scheme points
- ✓g' = g (1 - d/R)
- ✓g decreases with depth
- ✓g = 0 at the centre
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Motion in a Plane
What is meant by resolution of a vector? Write the rectangular components of a vector A making angle theta with the x-axis.
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Resolution of a vector is the process of splitting it into two or more components, usually along mutually perpendicular directions. For a vector A at angle theta to the x-axis, the rectangular components are Ax = A cos(theta) along the x-axis and Ay = A sin(theta) along the y-axis, with A = sqrt(Ax^2 + Ay^2).
Ax = A cos(theta) ; Ay = A sin(theta)
Marking-scheme points
- ✓Splitting a vector into components
- ✓Ax = A cos(theta), Ay = A sin(theta)
- ✓A = sqrt(Ax^2 + Ay^2)
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Thermodynamics
What is a quasi-static process? Why is it important?
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A quasi-static process is one carried out infinitely slowly so that the system stays in thermal and mechanical equilibrium with its surroundings at every stage. It is important because only for such (reversible) processes can the state variables (P, V, T) be defined throughout, and the work done can be represented as an area on a P-V diagram.
Marking-scheme points
- ✓Infinitely slow, equilibrium at every step
- ✓System properties well-defined throughout
- ✓Basis of reversible processes / P-V work
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Gravitation
State Newton's universal law of gravitation and write its mathematical form.
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Every particle of matter attracts every other particle with a force that is directly proportional to the product of their masses and inversely proportional to the square of the distance between them, directed along the line joining them: F = G m1 m2 / r^2, where G is the universal gravitational constant (6.67 x 10^-11 N m^2 / kg^2).
F = G m1 m2 / r^2
Marking-scheme points
- ✓F proportional to m1 m2
- ✓F inversely proportional to r^2
- ✓F = G m1 m2 / r^2
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Electric Charges and Fields
State Coulomb's law of electrostatics and write its mathematical form.
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Coulomb's law states that the force of attraction or repulsion between two point charges is directly proportional to the product of the magnitudes of the charges and inversely proportional to the square of the distance between them, acting along the line joining them. Mathematically, F = k q1 q2 / r^2, where k = 1/(4 pi epsilon0) = 9 x 10^9 N m^2 C^-2 in free space.
F = k q1 q2 / r^2
Marking-scheme points
- ✓F is proportional to product of charges and to 1/r^2
- ✓F = k q1 q2 / r^2 along the line joining them
- ✓k = 1/(4 pi epsilon0) = 9 x 10^9 N m^2 C^-2
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Electric Charges and Fields
Define electric field intensity at a point. State its SI unit.
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The electric field intensity at a point is the force experienced by a unit positive test charge placed at that point. It is a vector quantity given by E = F/q0, where q0 is the small positive test charge. Its SI unit is newton per coulomb (N/C) or equivalently volt per metre (V/m).
E = F/q0
Marking-scheme points
- ✓E = force per unit positive test charge = F/q0
- ✓Vector quantity, directed along the force on a positive charge
- ✓SI unit: N/C or V/m
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Electric Charges and Fields
Derive the expression for the torque acting on an electric dipole placed in a uniform electric field.
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When a dipole of moment p is placed in a uniform electric field E at an angle theta, the two charges experience equal and opposite forces qE, forming a couple. The magnitude of the torque = force x perpendicular distance = qE x (2a sin theta) = (q x 2a) E sin theta = pE sin theta. In vector form, torque = p x E. The torque tends to align the dipole with the field.
torque = pE sin theta = p x E
Marking-scheme points
- ✓Equal and opposite forces qE form a couple
- ✓Torque = pE sin theta (magnitude)
- ✓Vector form: torque = p x E; aligns dipole with field
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Electrostatic Potential and Capacitance
Define electric potential at a point. State its SI unit and write the expression for the potential due to a point charge.
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The electric potential at a point is the work done in bringing a unit positive charge from infinity to that point against the electric field. It is a scalar quantity and its SI unit is the volt (V), where 1 volt = 1 joule per coulomb. The potential due to a point charge Q at distance r is V = kQ/r = Q/(4 pi epsilon0 r).
V = kQ/r
Marking-scheme points
- ✓Work done per unit positive charge from infinity to the point
- ✓Scalar quantity; SI unit volt (1 V = 1 J/C)
- ✓V = kQ/r for a point charge
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Electrostatic Potential and Capacitance
Write the relation between electric field and electric potential. What does the negative sign indicate?
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The electric field is the negative gradient of the electric potential: E = -dV/dr. This means the field points in the direction in which the potential decreases most rapidly. The negative sign indicates that the electric field is directed from a region of higher potential to a region of lower potential, that is, potential decreases along the direction of the field.
E = -dV/dr
Marking-scheme points
- ✓E = -dV/dr (field = negative potential gradient)
- ✓Field points towards decreasing potential
- ✓Negative sign: E directed from high to low potential
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Electrostatic Potential and Capacitance
Define capacitance of a conductor. State its SI unit.
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The capacitance of a conductor is the ratio of the charge given to it to the resulting rise in its potential: C = Q/V. It is a measure of the ability of the conductor to store charge. Its SI unit is the farad (F), where 1 farad = 1 coulomb per volt. Capacitance depends on the size and shape of the conductor and the surrounding medium.
C = Q/V
Marking-scheme points
- ✓C = Q/V (charge stored per unit potential)
- ✓SI unit: farad (1 F = 1 C/V)
- ✓Depends on size, shape and surrounding medium
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Electrostatic Potential and Capacitance
Write the expression for the energy stored in a charged capacitor in three equivalent forms.
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The energy stored in a charged capacitor is the work done in charging it. It can be written in three equivalent forms: U = (1/2) C V^2 = (1/2) Q V = Q^2/(2C), where C is the capacitance, Q the charge and V the potential difference. This energy is stored in the electric field between the plates.
U = (1/2) C V^2 = (1/2) QV = Q^2/(2C)
Marking-scheme points
- ✓U = (1/2) C V^2
- ✓U = (1/2) Q V = Q^2/(2C)
- ✓Energy stored in the electric field between plates
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Electrostatic Potential and Capacitance
How does the introduction of a dielectric slab between the plates of a capacitor affect its capacitance? Explain.
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When a dielectric of dielectric constant K is fully inserted between the plates, the capacitance increases K times: C = K C0, where C0 is the capacitance with air. This is because the dielectric gets polarised and sets up an internal field opposite to the applied field, reducing the net field and hence the potential difference for the same charge; since C = Q/V, a smaller V means a larger C.
C = K C0
Marking-scheme points
- ✓Dielectric increases capacitance: C = K C0
- ✓Dielectric polarises and reduces the net field
- ✓Lower V for same Q -> higher C
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Current Electricity
State Ohm's law. Define resistance and give its SI unit.
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Ohm's law states that, at constant temperature, the current flowing through a conductor is directly proportional to the potential difference across its ends, so V = IR, where R is a constant called the resistance. Resistance is the opposition offered by a conductor to the flow of current and is defined as R = V/I. Its SI unit is the ohm.
V = IR
Marking-scheme points
- ✓At constant temperature, V is proportional to I (V = IR)
- ✓Resistance R = V/I = opposition to current
- ✓SI unit: ohm
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Current Electricity
Define resistivity of a material. How does the resistance of a wire depend on its length and area of cross-section?
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Resistivity (specific resistance) is the resistance of a conductor of unit length and unit area of cross-section; it depends on the material and temperature but not on its dimensions. The resistance of a wire is R = rho L/A, so it is directly proportional to its length L and inversely proportional to its area of cross-section A. The SI unit of resistivity is the ohm metre.
R = rho L/A
Marking-scheme points
- ✓Resistivity = resistance of unit length and unit area
- ✓R = rho L/A
- ✓R is proportional to L and inversely proportional to A
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Current Electricity
State Kirchhoff's two laws for electrical circuits.
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Kirchhoff's junction (current) law states that the algebraic sum of currents meeting at a junction is zero, that is, the total current entering a junction equals the total current leaving it; it is based on conservation of charge. Kirchhoff's loop (voltage) law states that the algebraic sum of the changes in potential around any closed loop of a circuit is zero; it is based on conservation of energy.
sum(I) at junction = 0; sum(V) around loop = 0
Marking-scheme points
- ✓Junction law: sum of currents at a junction = 0 (charge conservation)
- ✓Loop law: sum of potential changes around a loop = 0 (energy conservation)
- ✓Used to analyse complex circuits
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Current Electricity
Write the effective emf and internal resistance when n identical cells are connected in series.
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When n identical cells, each of emf E and internal resistance r, are connected in series (all in the same direction), the effective emf is n E and the total internal resistance is n r. The current through an external resistance R is I = n E/(R + n r). Series grouping is advantageous when the external resistance is much larger than the internal resistance.
I = nE/(R + nr)
Marking-scheme points
- ✓Series: effective emf = nE, internal resistance = nr
- ✓Current I = nE/(R + nr)
- ✓Useful when external R is much greater than internal r
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