Board Boosters
The questions your board exam loves to ask
800 most-asked Class 11 & 12 (+1 / +2) questions across Physics, Chemistry, Maths and Biology — each with a model answer and the exact marking-scheme points examiners reward. Revise smart, walk in calm.
PhysicsClass 122 markseasy
Ray Optics and Optical Instruments
State the laws of refraction of light (Snell's law).
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The laws of refraction are: (1) The incident ray, the refracted ray and the normal at the point of incidence all lie in the same plane. (2) For a given pair of media and a given colour of light, the ratio of the sine of the angle of incidence to the sine of the angle of refraction is a constant, called the refractive index: sin i/sin r = n (Snell's law). Refraction occurs because light travels at different speeds in different media.
sin i/sin r = n
Marking-scheme points
- ✓Incident ray, refracted ray and normal lie in one plane
- ✓Snell's law: sin i/sin r = n (constant)
- ✓Caused by change of speed of light between media
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Ray Optics and Optical Instruments
Define the power of a lens. State its SI unit and the formula for the power of two thin lenses in contact.
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The power of a lens is a measure of its ability to converge or diverge light and is defined as the reciprocal of its focal length in metres: P = 1/f (f in metres). Its SI unit is the dioptre (D). A converging (convex) lens has positive power and a diverging (concave) lens has negative power. For two thin lenses in contact, the total power is the sum: P = P1 + P2.
P = 1/f; P = P1 + P2
Marking-scheme points
- ✓P = 1/f (f in metres); SI unit dioptre (D)
- ✓Convex lens: positive power; concave lens: negative power
- ✓Lenses in contact: P = P1 + P2
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Wave Optics
State Huygens' principle of secondary wavelets.
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Huygens' principle states that: (1) every point on a given wavefront acts as a source of new disturbance called secondary wavelets, which spread out in all directions with the speed of the wave; and (2) the new wavefront at a later instant is the forward envelope (tangential surface) of all these secondary wavelets. This principle is used to explain the laws of reflection and refraction and the propagation of light as a wave.
Marking-scheme points
- ✓Every point on a wavefront is a source of secondary wavelets
- ✓Wavelets travel with the speed of the wave
- ✓New wavefront = forward envelope of the secondary wavelets
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Wave Optics
State the conditions for constructive and destructive interference in terms of path difference.
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For constructive interference (bright fringe), the path difference between the two interfering waves must be an integral multiple of the wavelength: path difference = n lambda, where n = 0, 1, 2, ... For destructive interference (dark fringe), the path difference must be an odd multiple of half the wavelength: path difference = (2n - 1) lambda/2. Equivalently, the phase difference is 2n pi for constructive and (2n - 1) pi for destructive interference.
constructive: n lambda; destructive: (2n-1) lambda/2
Marking-scheme points
- ✓Constructive: path difference = n lambda
- ✓Destructive: path difference = (2n - 1) lambda/2
- ✓Phase difference 2n pi (bright) or (2n-1) pi (dark)
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Wave Optics
What are coherent sources? State the conditions for obtaining sustained interference of light.
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Coherent sources are two sources of light that emit waves of the same frequency (or wavelength) and have a constant phase difference between them. Conditions for sustained (steady) interference: (1) the two sources must be coherent; (2) they must have the same frequency and nearly equal amplitudes; and (3) they must be narrow and close together, and the light should preferably be monochromatic. In practice, coherent sources are obtained from a single source (for example, using two slits).
Marking-scheme points
- ✓Coherent sources: same frequency and constant phase difference
- ✓Need equal frequency and nearly equal amplitude
- ✓Obtained from a single source (e.g. two slits)
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Wave Optics
State two differences between interference and diffraction of light.
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(1) Interference is due to the superposition of waves from two (or more) different coherent sources, whereas diffraction is due to the superposition of secondary wavelets coming from different parts of the same wavefront. (2) In interference all bright fringes are of equal intensity and equal width, whereas in diffraction the central maximum is the brightest and the intensity of the secondary maxima decreases rapidly on either side.
Marking-scheme points
- ✓Interference: two coherent sources; diffraction: parts of the same wavefront
- ✓Interference fringes: equal width and intensity
- ✓Diffraction: central maximum brightest, others decrease
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Wave Optics
What is polarisation of light? State Brewster's law.
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Polarisation is the phenomenon of restricting the vibrations of the electric field of a light wave to a single plane perpendicular to the direction of propagation; it shows that light is a transverse wave. Brewster's law states that when unpolarised light is incident on a transparent surface at a particular angle called the polarising angle (theta_p), the reflected light is completely plane-polarised, and the refractive index of the medium is n = tan(theta_p).
n = tan(theta_p)
Marking-scheme points
- ✓Polarisation restricts vibrations to one plane (light is transverse)
- ✓At the polarising angle, reflected light is fully plane-polarised
- ✓Brewster's law: n = tan(theta_p)
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Dual Nature of Radiation and Matter
What is the photoelectric effect?
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The photoelectric effect is the phenomenon of emission of electrons (called photoelectrons) from the surface of a metal when light of suitable frequency (usually ultraviolet or visible for some metals) falls on it. The emitted electrons carry kinetic energy. The effect occurs only when the frequency of the incident light is greater than a certain minimum value called the threshold frequency, and it provided evidence for the particle (photon) nature of light.
Marking-scheme points
- ✓Emission of electrons from a metal when light falls on it
- ✓Occurs only above the threshold frequency
- ✓Evidence for the particle (photon) nature of light
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Dual Nature of Radiation and Matter
Define work function and threshold frequency.
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The work function (W0) of a metal is the minimum energy required to just remove an electron from the surface of the metal without giving it any kinetic energy. The threshold frequency (f0) is the minimum frequency of the incident light below which no photoelectric emission takes place, however intense the light may be. They are related by W0 = h f0, where h is Planck's constant.
W0 = h f0
Marking-scheme points
- ✓Work function W0 = minimum energy to free an electron
- ✓Threshold frequency f0 = minimum frequency for emission
- ✓Relation: W0 = h f0
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Dual Nature of Radiation and Matter
State any two laws of the photoelectric effect.
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(1) For a given metal, photoelectric emission occurs only if the frequency of the incident light is greater than a certain minimum value (threshold frequency), whatever the intensity. (2) The maximum kinetic energy of the emitted photoelectrons depends on the frequency of the incident light and the nature of the metal, but is independent of the intensity of the light. (3) The number of photoelectrons emitted per second (photoelectric current) is directly proportional to the intensity of the incident light. (4) The emission is instantaneous, with no measurable time lag.
Marking-scheme points
- ✓Emission only above the threshold frequency
- ✓Max KE depends on frequency, not on intensity
- ✓Number of photoelectrons is proportional to intensity; emission is instantaneous
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Dual Nature of Radiation and Matter
What is the de Broglie hypothesis? Write the expression for the de Broglie wavelength.
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The de Broglie hypothesis states that every moving particle has a wave associated with it, called a matter wave. The de Broglie wavelength is lambda = h/p = h/(m v), where h is Planck's constant, p is the momentum, m is the mass and v the velocity of the particle. In terms of kinetic energy, lambda = h/sqrt(2 m KE). This shows the dual (wave-particle) nature of matter; the wavelength is significant only for very small particles like electrons.
lambda = h/(m v)
Marking-scheme points
- ✓Every moving particle has an associated matter wave
- ✓lambda = h/p = h/(m v)
- ✓In terms of KE: lambda = h/sqrt(2 m KE)
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Atoms
State the main conclusions of Rutherford's alpha-particle scattering experiment.
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From the scattering of alpha particles by a thin gold foil, Rutherford concluded that: (1) most of the atom is empty space, since most alpha particles passed straight through; (2) the entire positive charge and almost all the mass of the atom are concentrated in a very small central region called the nucleus, since a few alpha particles were deflected through large angles; and (3) the electrons revolve around the nucleus, and the size of the nucleus is very small compared with the size of the atom.
Marking-scheme points
- ✓Most of the atom is empty space
- ✓Positive charge and mass concentrated in a tiny nucleus
- ✓Electrons revolve around the nucleus
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Atoms
The energy of an electron in the ground state of hydrogen is -13.6 eV. Calculate the energy of the electron in the second orbit (n = 2).
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The energy of the electron in the nth orbit of hydrogen is En = -13.6/n^2 eV. For n = 2, E2 = -13.6/2^2 = -13.6/4 = -3.4 eV. The negative sign shows that the electron is bound to the nucleus, and the energy increases (becomes less negative) as n increases.
En = -13.6/n^2 eV
Marking-scheme points
- ✓En = -13.6/n^2 eV
- ✓E2 = -13.6/4
- ✓E2 = -3.4 eV
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Atoms
State two limitations of Bohr's model of the atom.
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(1) Bohr's model applies successfully only to hydrogen and hydrogen-like single-electron atoms; it fails to explain the spectra of atoms having more than one electron. (2) It could not explain the fine structure of spectral lines or the relative intensities of the lines, and it does not account for the splitting of spectral lines in electric and magnetic fields (the Stark and Zeeman effects). Also, it arbitrarily assumes quantisation without explaining it (later explained by de Broglie).
Marking-scheme points
- ✓Works only for hydrogen/single-electron atoms
- ✓Cannot explain fine structure or relative intensities of lines
- ✓Cannot explain Zeeman/Stark effects; quantisation assumed arbitrarily
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Nuclei
State Einstein's mass-energy relation. What is the energy equivalent of 1 atomic mass unit (u)?
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Einstein's mass-energy relation is E = m c^2, which states that mass and energy are interconvertible, where c is the speed of light. Using this relation, the energy equivalent of 1 atomic mass unit (1 u = 1.66 x 10^-27 kg) is about 931 MeV (mega electron volt). This relation explains the large amount of energy released in nuclear reactions such as fission and fusion.
E = m c^2; 1 u = 931 MeV
Marking-scheme points
- ✓E = m c^2 (mass and energy are interconvertible)
- ✓1 u is equivalent to about 931 MeV
- ✓Explains energy released in nuclear reactions
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Nuclei
Define mass defect and binding energy of a nucleus.
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The mass defect is the difference between the sum of the masses of the individual protons and neutrons (nucleons) and the actual mass of the nucleus; the actual nuclear mass is always less than the sum. This missing mass (delta m) is converted into energy that binds the nucleons together. The binding energy is the energy equivalent of the mass defect, BE = (delta m) c^2; it is the energy required to break the nucleus into its constituent nucleons.
BE = (delta m) c^2
Marking-scheme points
- ✓Mass defect = (sum of nucleon masses) - (actual nuclear mass)
- ✓This mass is converted into binding energy
- ✓Binding energy = (delta m) c^2
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Nuclei
Name the three types of radioactive radiations and state their nature.
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The three types of radioactive radiations are: (1) alpha rays, which are helium nuclei (2 protons + 2 neutrons), positively charged and with low penetrating power; (2) beta rays, which are fast-moving electrons, negatively charged and with greater penetrating power than alpha rays; and (3) gamma rays, which are high-energy electromagnetic waves (photons), electrically neutral and with very high penetrating power. In a magnetic field, alpha and beta rays are deflected in opposite directions while gamma rays are undeflected.
Marking-scheme points
- ✓Alpha: helium nuclei, positive, low penetration
- ✓Beta: fast electrons, negative, moderate penetration
- ✓Gamma: high-energy EM waves, neutral, high penetration
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Nuclei
What is nuclear fission? Give one example.
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Nuclear fission is the process in which a heavy nucleus (such as uranium-235) splits into two lighter nuclei of comparable masses, with the release of a few neutrons and a large amount of energy. For example, when a uranium-235 nucleus captures a slow neutron, it splits into barium and krypton nuclei plus three neutrons and energy. The released neutrons can cause further fissions, leading to a chain reaction, which is used in nuclear reactors and atom bombs.
Marking-scheme points
- ✓Heavy nucleus splits into two lighter nuclei with energy release
- ✓Example: U-235 + neutron -> lighter nuclei + neutrons + energy
- ✓Released neutrons can cause a chain reaction
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Nuclei
What is nuclear fusion? Why does it require very high temperature?
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Nuclear fusion is the process in which two light nuclei (such as isotopes of hydrogen) combine to form a heavier nucleus, with the release of an enormous amount of energy. It is the source of energy of the sun and stars, where hydrogen nuclei fuse to form helium. It requires very high temperature (millions of degrees) because the positively charged nuclei must overcome their strong electrostatic repulsion to come close enough to fuse.
Marking-scheme points
- ✓Two light nuclei combine into a heavier nucleus with energy release
- ✓Source of energy of the sun and stars (hydrogen to helium)
- ✓Needs very high temperature to overcome electrostatic repulsion
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Semiconductor Electronics
Distinguish between intrinsic and extrinsic semiconductors.
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An intrinsic semiconductor is a pure semiconductor (such as pure silicon or germanium) with no added impurity; its conductivity is low and is due to the equal number of electrons and holes generated thermally. An extrinsic semiconductor is one to which a small amount of a suitable impurity has been added (doping); this greatly increases its conductivity. Extrinsic semiconductors are of two types, n-type and p-type.
Marking-scheme points
- ✓Intrinsic: pure semiconductor, low conductivity, equal electrons and holes
- ✓Extrinsic: doped with impurity, higher conductivity
- ✓Extrinsic types: n-type and p-type
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