MixedJEE Physics · Original learning card5 original chapter questions

Cell Terminal Voltage and Internal Resistance Graph

For a cell of emf E and approximately constant internal resistance r delivering current I, terminal voltage is V = E - Ir, so a plot of V against I is a straight line with intercept E and slope -r.

Why this shows up in the exam

Battery load testing · Finding cell emf from an intercept · Finding internal resistance from a V-I graph

Learn the idea

A discharging cell's terminal voltage falls linearly with current because of its internal resistance. The cell supplies emf, but part of that energy per charge is lost inside the cell as current crosses its internal resistance; the graph intercept gives emf and the downward slope gives that resistance.

🧠 Memory hook: Intercept is emf; downward slope magnitude is internal resistance.

Get this one clearly and it pays off every single time it shows up in the paper. 🎯

Formulas & facts to keep ready

  • V = E - Ir — terminal voltage of a discharging cell
  • E = V at I=0; r = -dV/dI — graphical extraction of emf and internal resistance

How to approach it

  1. 1Identify graph axes and units
  2. 2Read the zero-current intercept
  3. 3Use the magnitude of Delta V/Delta I for r

Common slip-ups that cost marks

  • •Taking the loaded terminal voltage as emf
  • •Using slope I/V instead of V/I
  • •Assigning a negative physical resistance because the graph slopes down

🌟 That's the whole idea — you've got this. Try the practice set below; every question you attempt makes it stick a little harder.

Original chapter practice

Original questions for this chapter, not past-paper questions or an exact mapping to this individual concept.

Question 1 of 5

In a meter bridge, resistance 2 ohm is in the left gap and balance occurs at 40 cm from the left end. Find the right-gap resistance.

Take a timed JEE Physics sectional mock

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