MixedJEE Physics · Original learning card5 original chapter questions

Photon Energy and Momentum

For a photon in vacuum, energy is proportional to frequency and momentum is energy divided by c. Frequency and wavelength obey c = nu lambda, so shorter-wavelength photons have larger energy and momentum.

Why this shows up in the exam

Comparing photon energies across the electromagnetic spectrum · Calculating atomic absorption or emission energy · Relating light momentum to mechanical effects

Learn the idea

A photon carries discrete energy and momentum even though its rest mass is zero. Light exchanges energy in packets. A higher-frequency packet carries more energy, and every photon also carries momentum, so light can push matter without having rest mass.

🧠 Memory hook: Shorter wave, bigger photon energy and momentum.

Get this one clearly and it pays off every single time it shows up in the paper. 🎯

Formulas & facts to keep ready

  • E = h nu = h c / lambda — energy of one photon of frequency nu and vacuum wavelength lambda
  • p = E/c = h/lambda — magnitude of photon momentum in vacuum

How to approach it

  1. 1Identify whether the object is a photon or a massive particle
  2. 2Convert wavelength to metres or use a consistent h c unit
  3. 3Use E = h nu and p = E/c before comparing quantities

Common slip-ups that cost marks

  • •Setting photon momentum to zero because photon rest mass is zero
  • •Using E = pc for a massive non-relativistic particle
  • •Mixing wavelength units when using h c / lambda

🌟 That's the whole idea — you've got this. Try the practice set below; every question you attempt makes it stick a little harder.

Original chapter practice

Original questions for this chapter, not past-paper questions or an exact mapping to this individual concept.

Question 1 of 5

Photons of energy 5 eV illuminate a metal of work function 2 eV. Find the stopping potential.

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