Photoelectric Effect
The photoelectric effect describes the emission of electrons from a material when it is exposed to light of sufficient frequency, governed by concepts such as threshold frequency, work function, stopping potential, and the Einstein photoelectric equation.
Why this shows up in the exam
NEET tests your understanding of how light interacts with matter, including calculations involving threshold frequency, kinetic energy, stopping potential, and the interpretation of experimental data.
How NEET tests this
Learn the idea
When light of frequency above a material's threshold strikes it, each photon can liberate one electron; the excess photon energy becomes the electron's kinetic energy (Einstein's equation). The key insight is that frequency (not intensity) decides whether electrons are emitted, while intensity controls how many are emitted.
🧠 Memory hook: Frequency opens the door (emission), intensity fills the room (current).
Get this one clearly and it pays off every single time it shows up in the paper. 🎯
Formulas & facts to keep ready
- Photon energy E = hν = hc/λ
- Threshold frequency ν₀ = φ/h and threshold wavelength λ₀ = hc/φ
- Einstein photoelectric equation KE_max = hν – φ = eV_s
- Photoelectric current ∝ light intensity (number of photons) for ν > ν₀
- If ν ≤ ν₀ no electrons are emitted regardless of intensity
How to approach it
- 11) Verify ν > ν₀ (or λ < λ₀) to confirm emission.
- 22) Compute photon energy using E = hc/λ (or hν).
- 33) Subtract the work function φ to get KE_max; if stopping potential is required, use V_s = KE_max/e.
- 44) For current, relate intensity to photon flux; for speed, use KE_max = ½mv².
Worked example — watch it click
The photoelectric threshold wavelength of silver is 3250 × 10⁻¹⁰ m. The velocity of the electron ejected from a silver surface by ultraviolet light of wavelength 2536 × 10⁻¹⁰ m is: (Given h = 4.14×10⁻¹⁵ eVs and c = 3×10⁸ m/s)
- A)0.6 x 10⁶ m/s
- B)61 x 10³ m/s
- C)0.3 x 10⁶ m/s
- ✅6.1 x 10⁵ m/s
The concept behind this problem
The example forces you to turn a wavelength into photon energy, subtract the work function, and then translate the remaining kinetic energy into electron speed – exactly the steps of Einstein's photoelectric equation.
Step by step
- 1Work function φ = hc/λ₀ = (4.14×10⁻¹⁵ × 3×10⁸)/(3250×10⁻¹⁰) = 3.82 eV.
- 2Incident photon energy E = hc/λ = (4.14×10⁻¹⁵ × 3×10⁸)/(2536×10⁻¹⁰) = 4.90 eV.
- 3KE = E - φ = 4.90 - 3.82 = 1.08 eV = 1.73×10⁻¹⁹ J.
- 4Using ½mv² = KE: v = √(2×1.73×10⁻¹⁹/9.1×10⁻³¹) ≈ 6.2×10⁵ m/s ≈ 6.1×10⁵ m/s.
Watch out
Students often skip converting the work function from eV to joules before using KE = ½mv², giving an incorrect speed.
Common slip-ups that cost marks
- •Mixing up intensity with kinetic energy – intensity changes current, not KE.
- •Using λ instead of λ₀ (or ν instead of ν₀) and concluding emission when there is none.
- •For speed calculations, forgetting to convert eV to joules before applying ½mv².
🌟 That's the whole idea — you've got this. Try the practice set below; every question you attempt makes it stick a little harder.
Practise it
These are real questions from past NEET papers that test this exact idea.
Light of frequency 1.5 times the threshold frequency is incident on a photosensitive material. What will be the photoelectric current if the frequency is halved and intensity is doubled?
Push further
More challenging24 harder questions built from the past papers above — a step up in difficulty, with distractors designed so you can't get there by elimination. Written and checked by our reviewers, not from a real paper.
A metallic surface has a threshold frequency of 6.0 x 10¹⁴ Hz. If light of frequency 9.0 x 10¹⁴ Hz is incident on it, photoelectrons are emitted. What happens to the photoelectric current if the incident light's frequency is changed to 4.0 x 10¹⁴ Hz, while its intensity is kept constant?
More from Dual Nature of Matter and Radiation
de Broglie Wavelength and Matter Waves
All matter exhibits wave-like properties, with the de Broglie wavelength inversely proportional to momentum and dependent on factors like velocity, temperature, and particle type.
Photon Properties and Energy-Momentum Relations
Photons are massless particles of light characterized by their energy, frequency, momentum, and charge neutrality, and their interactions obey conservation laws.
Photon Energy and Momentum
For a photon in vacuum, energy is proportional to frequency and momentum is energy divided by c. Frequency and wavelength obey c = nu lambda, so shorter-wavelength photons have larger energy and momentum.
Photon Rate, Power, and Energy Density
For monochromatic radiation, total energy is the number of photons times h nu. Power is energy per unit time, so the photon emission rate equals power divided by single-photon energy.
Radiation Pressure and Photon Momentum Transfer
Radiation force is the rate of photon momentum transfer. For normal incidence on an ideal absorber the pressure is intensity divided by c; for an ideal reflector it is twice that value.
Photoelectric Effect Observations
For a fixed emitter, emission occurs only when incident frequency reaches the threshold frequency. Above threshold, maximum kinetic energy depends on frequency, while saturation current is primarily proportional to intensity.