MixedJEE Physics · Original learning card5 original chapter questions

Photon Rate, Power, and Energy Density

For monochromatic radiation, total energy is the number of photons times h nu. Power is energy per unit time, so the photon emission rate equals power divided by single-photon energy.

Why this shows up in the exam

Estimating laser photon output · Comparing photon counts from equal-power sources · Converting photon number density to electromagnetic energy density

Learn the idea

Optical power counts photon energy delivered per unit time, not photons alone. A beam with fixed power can contain many low-energy photons or fewer high-energy photons. Counting photons therefore requires both the beam power and the energy carried by each photon.

🧠 Memory hook: Photon rate equals power divided by energy per photon.

Get this one clearly and it pays off every single time it shows up in the paper. 🎯

Formulas & facts to keep ready

  • P = N_dot h nu = N_dot h c / lambda — power of a monochromatic source emitting N_dot photons per second
  • u = n h nu — energy density when n is the number of equal-frequency photons per unit volume

How to approach it

  1. 1Calculate one photon energy from wavelength or frequency
  2. 2Write power as photon rate times photon energy
  3. 3Cancel constants before inserting numerical values in ratios

Common slip-ups that cost marks

  • •Assuming equal powers imply equal photon rates at different wavelengths
  • •Using total photon number where photons per second are required
  • •Forgetting that longer wavelength means smaller energy per photon

🌟 That's the whole idea — you've got this. Try the practice set below; every question you attempt makes it stick a little harder.

Original chapter practice

Original questions for this chapter, not past-paper questions or an exact mapping to this individual concept.

Question 1 of 5

Photons of energy 5 eV illuminate a metal of work function 2 eV. Find the stopping potential.

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