MixedJEE Physics · Original learning card5 original chapter questions

Radiation Pressure and Photon Momentum Transfer

Radiation force is the rate of photon momentum transfer. For normal incidence on an ideal absorber the pressure is intensity divided by c; for an ideal reflector it is twice that value.

Why this shows up in the exam

Solar sails · Laser trapping and manipulation · Estimating recoil of illuminated mirrors

Learn the idea

Light exerts force when photon momentum is absorbed or reversed at a surface. Absorbing a photon gives its forward momentum to a surface. Reflecting it reverses that momentum, so the surface receives twice the momentum change for normal incidence.

🧠 Memory hook: Absorb gives p; reflect reverses p and gives 2p.

Get this one clearly and it pays off every single time it shows up in the paper. 🎯

Formulas & facts to keep ready

  • pressure_absorb = I/c — radiation pressure on an ideal absorbing surface at normal incidence
  • pressure_reflect = 2I/c — radiation pressure on an ideal reflecting surface at normal incidence
  • impulse = Delta E/c or 2 Delta E/c — pulse impulse for complete absorption or normal reflection

How to approach it

  1. 1Decide whether light is absorbed or reflected
  2. 2Convert power or pulse energy to momentum transfer
  3. 3Use force times time equals impulse for mechanical motion

Common slip-ups that cost marks

  • •Using the reflecting formula for an absorbing surface
  • •Confusing intensity with total power
  • •Ignoring the illuminated area when converting pressure to force

🌟 That's the whole idea — you've got this. Try the practice set below; every question you attempt makes it stick a little harder.

Original chapter practice

Original questions for this chapter, not past-paper questions or an exact mapping to this individual concept.

Question 1 of 5

Photons of energy 5 eV illuminate a metal of work function 2 eV. Find the stopping potential.

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