A car starting from rest accelerates uniformly at 2 m/s^2 for 5 seconds. Find its final velocity and the distance travelled.
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What it is
The three equations of motion connect initial velocity, acceleration, time, distance and final velocity for steady acceleration.
Answer
Given u = 0, a = 2 m/s^2, t = 5 s. Final velocity v = u + at = 0 + 2 x 5 = 10 m/s. Distance s = ut + (1/2)at^2 = 0 + (1/2)(2)(5^2) = 25 m. So the car reaches 10 m/s and covers 25 m.
v = u + at ; s = ut + (1/2)at^2
- •v = u + at = 10 m/s
- •s = ut + (1/2)at^2 = 25 m
- •u = 0 (starts from rest)
Why learn this
They let engineers predict a rocket's speed, a car's braking distance and a ball's flight - the maths of all moving things.
💡 Memory trick
Use 'v = u + at' first (no distance), then 's = ut + 1/2 at^2'. Velocity gets a time-boost 'at'.