MixedJEE Physics · Original learning card5 original chapter questions

Work Function and Threshold

The work function phi is the minimum energy required to remove an electron from a material surface. At threshold the emitted electron has zero maximum kinetic energy, giving phi = h nu_0 = h c / lambda_0.

Why this shows up in the exam

Selecting photocathode materials · Finding threshold wavelength or frequency · Checking whether visible light can eject electrons

Learn the idea

The work function fixes the minimum photon frequency and maximum threshold wavelength for emission. Different metals hold electrons with different strengths. The work function is the least energy needed to free an electron, so it creates a sharp frequency threshold for incident light.

🧠 Memory hook: Threshold frequency is minimum; threshold wavelength is maximum.

Get this one clearly and it pays off every single time it shows up in the paper. 🎯

Formulas & facts to keep ready

  • phi = h nu₀ = h c / lambda₀ — relation among work function, threshold frequency, and threshold wavelength
  • lambda <= lambda₀ — wavelength condition for photoemission from that surface

How to approach it

  1. 1Convert the work function into the same energy unit as h nu
  2. 2Compute nu₀ or lambda₀ at zero kinetic energy
  3. 3Compare incident frequency upward or wavelength downward with threshold

Common slip-ups that cost marks

  • •Calling threshold wavelength the minimum allowed wavelength
  • •Using ordinary frequency where angular frequency is intended
  • •Forgetting that work function depends on the surface material

🌟 That's the whole idea — you've got this. Try the practice set below; every question you attempt makes it stick a little harder.

Original chapter practice

Original questions for this chapter, not past-paper questions or an exact mapping to this individual concept.

Question 1 of 5

Photons of energy 5 eV illuminate a metal of work function 2 eV. Find the stopping potential.

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