MixedJEE Physics · Original learning card5 original chapter questions

de Broglie Wavelength

The de Broglie hypothesis assigns wavelength lambda = h/p to a particle of momentum p. For non-relativistic motion p = m v; the momentum form remains the safest starting point whenever direction or collisions matter.

Why this shows up in the exam

Estimating matter-wave scales · Comparing microscopic and macroscopic wave behavior · Inferring momentum from measured wavelength

Learn the idea

Every moving particle has a wavelength inversely proportional to its momentum. Matter behaves more wave-like when its momentum is small. Increasing either mass or speed usually shortens the wavelength, which is why wave effects are easy to see for microscopic particles but not everyday objects.

🧠 Memory hook: More momentum means less wavelength.

Get this one clearly and it pays off every single time it shows up in the paper. 🎯

Formulas & facts to keep ready

  • lambda = h/p — general de Broglie relation in terms of momentum magnitude
  • lambda = h/(m v) — non-relativistic wavelength for a particle of mass m and speed v

How to approach it

  1. 1Start from lambda = h/p
  2. 2Choose the correct momentum relation for the given regime
  3. 3Use ratios before substituting constants

Common slip-ups that cost marks

  • •Using velocity with sign instead of momentum magnitude for wavelength
  • •Applying p = m v at relativistic speeds
  • •Assuming only charged particles have matter waves

🌟 That's the whole idea — you've got this. Try the practice set below; every question you attempt makes it stick a little harder.

Original chapter practice

Original questions for this chapter, not past-paper questions or an exact mapping to this individual concept.

Question 1 of 5

Photons of energy 5 eV illuminate a metal of work function 2 eV. Find the stopping potential.

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