MixedJEE Physics · Original learning card5 original chapter questions

Matter Wavelength and Kinetic Energy

For a non-relativistic particle, K = p squared divided by 2m. Substitution into lambda = h/p gives lambda = h divided by the square root of 2mK.

Why this shows up in the exam

Reading wavelength-energy graphs · Finding energy changes from wavelength ratios · Comparing electron wavelength at two kinetic energies

Learn the idea

For fixed non-relativistic mass, de Broglie wavelength varies as the inverse square root of kinetic energy. Kinetic energy grows with the square of momentum, while wavelength falls as the inverse of momentum. Combining these facts makes wavelength fall only as the square root of energy.

🧠 Memory hook: At fixed mass, wavelength follows one over root K.

Get this one clearly and it pays off every single time it shows up in the paper. 🎯

Formulas & facts to keep ready

  • lambda = h / sqrt(2 m K) — non-relativistic matter wavelength in terms of kinetic energy
  • K lambda² = h²/(2m) — constant relation for particles of one fixed mass

How to approach it

  1. 1Confirm that the motion is non-relativistic
  2. 2Write lambda proportional to one over square root of mK
  3. 3Square wavelength ratios only after arranging the ratio correctly

Common slip-ups that cost marks

  • •Using lambda proportional to one over K
  • •Comparing different masses with a fixed-mass shortcut
  • •Using the non-relativistic expression at very high kinetic energy

🌟 That's the whole idea — you've got this. Try the practice set below; every question you attempt makes it stick a little harder.

Original chapter practice

Original questions for this chapter, not past-paper questions or an exact mapping to this individual concept.

Question 1 of 5

Photons of energy 5 eV illuminate a metal of work function 2 eV. Find the stopping potential.

Take a timed JEE Physics sectional mock