MixedJEE Physics · Original learning card5 original chapter questions

X-ray Tube Controls and Spectrum

In an X-ray tube, electron rate is controlled primarily by tube current and electron energy by accelerating voltage. Target material sets characteristic lines; voltage sets the continuous cutoff and must exceed shell thresholds for characteristic emission.

Why this shows up in the exam

Interpreting Coolidge-tube spectra · Separating tube-current and tube-voltage effects · Selecting medical-imaging exposure settings

Learn the idea

Tube current mainly changes X-ray intensity, while voltage changes photon energies and the cutoff. Sending more electrons to the target creates more X-ray photons, making the spectrum taller. Accelerating each electron more strongly gives access to higher photon energies and shifts the short-wavelength edge.

🧠 Memory hook: Current changes how many; voltage changes how energetic.

Get this one clearly and it pays off every single time it shows up in the paper. 🎯

Formulas & facts to keep ready

  • X-ray intensity proportional to electron arrival rate — first-order effect of tube current at fixed voltage and target
  • lambda_min = h c/(e V) — voltage control of the continuous-spectrum cutoff

How to approach it

  1. 1Classify the requested change as intensity, cutoff, or line position
  2. 2Assign current, voltage, or target material respectively
  3. 3Check threshold conditions when characteristic lines are involved

Common slip-ups that cost marks

  • •Shifting characteristic-line positions by changing tube current
  • •Changing cutoff wavelength when only electron count changes
  • •Assuming all electron energy becomes useful X-rays

🌟 That's the whole idea — you've got this. Try the practice set below; every question you attempt makes it stick a little harder.

Original chapter practice

Original questions for this chapter, not past-paper questions or an exact mapping to this individual concept.

Question 1 of 5

Photons of energy 5 eV illuminate a metal of work function 2 eV. Find the stopping potential.

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