For Class 8, 9 & 10

Master the basics - and everything after gets easier

Concept-first questions with clear model answers in Physics, Chemistry, Maths and Biology, all NCERT-aligned. Start early, build the habit, and walk into your boards, NEET and JEE already ahead.

Interactive lessons

learn by playing

Drag, slide and build - watch each concept come alive, then reveal the answer.

200 interactive lessons

Interactive

Ohm's law

Class 10 Physics

Slide V & R, watch the bulb glow

Open
Interactive

pH scale

Class 10 Chemistry

Slide across acids and bases

Open
Interactive

Atomic number and mass number

Class 9 Chemistry

Add protons & neutrons, build shells

Open
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Laws of reflection

Class 8 Physics

Change the angle, watch it bounce

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Volume of a sphere

Class 9 Maths

Grow the radius, see the volume

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Area of a trapezium

Class 8 Maths

Drag the sides, read the area

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Power of a lens

Class 10 Physics

Move the object, trace the rays

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Food chain and energy flow

Class 10 Biology

Follow the energy as it flows

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Speed

Class 8 Physics

Slide distance & time, watch the speed

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Density

Class 9 Physics

Pack mass into volume, float or sink

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Work done

Class 9 Physics

Push harder or farther, watch work grow

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Kinetic energy

Class 9 Physics

Speed it up - energy grows with the square

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Power of a lens

Class 10 Physics

Shorten the focal length, boost the power

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Mole concept

Class 9 Chemistry

Weigh out grams, count the moles

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Avogadro's number

Class 9 Chemistry

Add moles, count the particles

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Microscope magnification

Class 8 Biology

Grow the image, read the magnification

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Population density

Class 10 Biology

Add individuals, shrink the land, see crowding

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Simple interest

Class 8 Maths

Slide money, rate & time, watch interest

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Pythagoras theorem

Class 9 Maths

Stretch the two sides, get the hypotenuse

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Probability of an event

Class 10 Maths

Change the outcomes, watch the odds

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Newton's second law

Class 9 Physics

Push a mass, pick an acceleration

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Momentum

Class 9 Physics

Slide mass & velocity, build momentum

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Pressure

Class 8 Physics

Shrink the area, feel the pressure rise

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Weight

Class 9 Physics

Change the planet's gravity, watch your weight

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Refractive index

Class 10 Physics

Slow light in the medium, raise the index

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Resistors in series

Class 10 Physics

Add two resistors in a line

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Mass percentage of a solution

Class 9 Chemistry

Dissolve solute, read the strength

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Concentration of a solution

Class 9 Chemistry

Pack solute into less liquid

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Population change

Class 10 Biology

Balance births against deaths

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Compound microscope

Class 8 Biology

Combine eyepiece & objective lenses

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Area of a circle

Class 8 Maths

Grow the radius, watch the area square

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Volume of a cuboid

Class 8 Maths

Stretch length, breadth & height

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Electronic configuration and valency

Class 9 Chemistry

Slide the atomic number, build the atom

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Homologous series (alkanes)

Class 10 Chemistry

Add carbons, name the compound

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Mass number

Class 9 Chemistry

Add protons & neutrons, get the mass number

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Power

Class 9 Physics

More work in less time = more power

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Potential energy

Class 9 Physics

Lift a mass higher, store energy

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Wave speed

Class 9 Physics

Tune frequency & wavelength, set the speed

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Electric current

Class 10 Physics

Push charge per second, get the current

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Percentage

Class 8 Maths

Compare part to whole as a %

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Electron dot structure

Class 9 Chemistry

Draw valence electrons as dots

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Acceleration

Class 9 Physics

Speed up over time, find acceleration

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Distance, speed and time

Class 8 Physics

Set speed & time, cover the distance

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Frequency and time period

Class 9 Physics

Shorten the period, raise the frequency

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Heating effect of current

Class 10 Physics

Raise the current, watch heating soar

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Area of a triangle

Class 8 Maths

Set base & height, halve the rectangle

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Area of a rectangle

Class 8 Maths

Set length & breadth, fill the area

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Mean (average)

Class 9 Maths

Share the total equally across items

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Discount

Class 8 Maths

Slide price & % off, see the saving

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Heart rate

Class 10 Biology

Set heart rate & time, count the beats

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Resistors in parallel

Class 10 Physics

Wire two resistors side by side

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Electric charge

Class 10 Physics

Flow current over time, collect charge

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Electrical energy and units

Class 10 Physics

Run appliances, add up the units

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Kelvin temperature scale

Class 9 Chemistry

Slide Celsius, read the Kelvin

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Moles from number of particles

Class 9 Chemistry

Divide particles by Avogadro's number

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Ten percent law

Class 10 Biology

See 10% of energy reach the next level

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Area of a square

Class 8 Maths

Grow the side, square the area

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Volume of a cube

Class 8 Maths

Grow the edge, cube the volume

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Circumference of a circle

Class 8 Maths

Grow the radius, roll out the rim

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Surface area of a cube

Class 9 Maths

Grow the edge, cover six faces

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Potential difference

Class 10 Physics

Share work across charge, get volts

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Resistance from Ohm's law

Class 10 Physics

Divide voltage by current, get resistance

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Echo and SONAR

Class 9 Physics

Time the echo, find the distance

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Mass from moles

Class 9 Chemistry

Multiply moles by molar mass

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Breathing rate

Class 10 Biology

Set breathing rate & time

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Volume of a cylinder

Class 10 Maths

Set radius & height, fill the can

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Compound interest

Class 8 Maths

Compound money over years

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Profit and loss percentage

Class 8 Maths

Set cost & selling price, see profit %

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Perimeter of a rectangle

Class 8 Maths

Set length & breadth, walk the border

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Surface area of a sphere

Class 10 Maths

Grow the radius, wrap the ball

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Time period

Class 9 Physics

Raise the frequency, shrink the period

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Relative velocity

Class 9 Physics

Two objects approach - add their speeds

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Average velocity

Class 9 Physics

Average the start and end speeds

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Equations of motion (v = u + at)

Class 9 Physics

Accelerate from u for a time t

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Kelvin to Celsius

Class 9 Chemistry

Slide Kelvin, read the Celsius

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Population growth rate

Class 10 Biology

Balance births vs deaths per population

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Perimeter of a square

Class 8 Maths

Grow the side, walk four edges

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Perimeter of a triangle

Class 8 Maths

Add the three sides

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Area of a parallelogram

Class 8 Maths

Set base & height, slide the shape

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Area of a rhombus

Class 8 Maths

Set the two diagonals

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Equations of motion (distance)

Class 9 Physics

Start, accelerate, cover ground

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Joule's law of heating

Class 10 Physics

Raise current, resistance or time

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Electric power (P = VI)

Class 10 Physics

Multiply voltage by current

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Average atomic mass of isotopes

Class 9 Chemistry

Mix two isotopes by abundance

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Seed germination percentage

Class 9 Biology

Count sprouted seeds out of the total

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Volume of a cone

Class 9 Maths

Set radius & height, fill the cone

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Surface area of a cylinder

Class 9 Maths

Wrap the side and both ends

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Surface area of a cuboid

Class 9 Maths

Cover all six rectangular faces

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nth term of an AP

Class 10 Maths

Step from the first term by d

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Sum of an AP

Class 10 Maths

Add up the first n terms

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Focal length of a mirror

Class 10 Physics

Halve the radius to find the focus

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Speed of light in a medium

Class 10 Physics

Raise the index, slow the light

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Percentage purity

Class 9 Chemistry

Weigh the pure part of a sample

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Slope of a line

Class 10 Maths

Rise over run gives the steepness

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Percentage change

Class 8 Maths

Compare a new value to the old

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Volume of a hemisphere

Class 9 Maths

Grow the radius of half a ball

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Area of a sector

Class 10 Maths

Cut a slice of angle from a circle

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Length of an arc

Class 10 Maths

Measure the curved edge of a slice

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Slant height of a cone

Class 9 Maths

Combine radius & height for the slant

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Unit conversion (km/h to m/s)

Class 9 Physics

Convert km/h into m/s

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Equations of motion (v^2 = u^2 + 2as)

Class 9 Physics

Accelerate over a distance, find v

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Impulse

Class 9 Physics

Hit harder or longer, change momentum

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Wavelength

Class 9 Physics

Speed over frequency gives wavelength

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Oscillations

Class 9 Physics

Vibrate at a frequency for a time

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Cost of electricity

Class 10 Physics

Units times rate gives the bill

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Number of neutrons

Class 9 Chemistry

Take protons away from the mass number

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Curved surface area of a cone

Class 9 Maths

Wrap the slanted side of a cone

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Total surface area of a cone

Class 9 Maths

Add the base circle to the cone's side

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Curved surface area of a hemisphere

Class 9 Maths

Cover the dome of a hemisphere

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Diagonal of a square

Class 9 Maths

Cross a square corner to corner

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Unit conversion (m/s to km/h)

Class 9 Physics

Convert m/s into km/h

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Distance from velocities

Class 9 Physics

From two speeds, find the distance

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Diagonal of a rectangle

Class 9 Maths

Cross a rectangle corner to corner

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Diagonal of a cuboid

Class 9 Maths

The longest rod that fits in a box

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Area by Heron's formula

Class 9 Maths

Area from just the three sides

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Interior angle sum of a polygon

Class 8 Maths

Add up a polygon's inside angles

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Exterior angle of a regular polygon

Class 8 Maths

Share 360 among a polygon's corners

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Number of diagonals of a polygon

Class 8 Maths

Count the diagonals of a polygon

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Discriminant

Class 10 Maths

Test how many roots a quadratic has

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Sum of roots

Class 10 Maths

Sum of a quadratic's roots

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Punnett square (monohybrid cross)

Class 10 Biology

Cross two parents, predict the offspring

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Balancing chemical equations

Class 10 Chemistry

Slide coefficients until atoms balance

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Writing chemical formulae (valency)

Class 9 Chemistry

Criss-cross valencies into a formula

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Current from power

Class 10 Physics

Divide power by voltage for current

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Power (P = V^2 / R)

Class 10 Physics

Voltage squared over resistance

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Sine ratio

Class 10 Maths

Opposite over hypotenuse

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Cosine ratio

Class 10 Maths

Adjacent over hypotenuse

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Tangent ratio

Class 10 Maths

Opposite over adjacent

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Area of an equilateral triangle

Class 9 Maths

Area of an equilateral triangle

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Curved surface area of a cylinder

Class 9 Maths

Wrap only the curved side

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Loss percentage

Class 8 Maths

Sell below cost, find the loss %

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Amount with simple interest

Class 8 Maths

Principal plus its simple interest

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Distance formula

Class 10 Maths

Straight distance between two points

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States of matter

Class 9 Chemistry

Heat particles solid → liquid → gas

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Parts of a plant cell

Class 8 Biology

Tap a cell part to see its job

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Diagonal of a cube

Class 9 Maths

Longest diagonal through a cube

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Total surface area of a hemisphere

Class 9 Maths

Dome plus its flat circle

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Sum of first n natural numbers

Class 10 Maths

Add 1 + 2 + ... + n instantly

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Range of data

Class 9 Maths

Spread from smallest to largest

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Class mark

Class 9 Maths

Midpoint of a class interval

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Selling price from profit percent

Class 8 Maths

Mark up cost by a profit %

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Perimeter of a sector

Class 10 Maths

Two radii plus the curved arc

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Circumference from diameter

Class 8 Maths

Circumference straight from diameter

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Power (P = F x v)

Class 9 Physics

Force times velocity gives power

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Percentage of a number

Class 8 Maths

Find a percentage of a number

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Series and parallel circuits

Class 10 Physics

Break a bulb in series vs parallel

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Symbols of elements

Class 9 Chemistry

Match each element to its symbol

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Free fall (velocity)

Class 9 Physics

Drop from a height, hit this speed

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Free fall (time)

Class 9 Physics

How long a drop takes

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Free fall (distance)

Class 9 Physics

Distance fallen in a given time

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Complement of an event

Class 10 Maths

Chance an event does NOT happen

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Product of roots

Class 10 Maths

Product of a quadratic's roots

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Exterior angle theorem

Class 9 Maths

Exterior angle = sum of remote interiors

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Complementary angles

Class 10 Maths

What adds to 90 degrees

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Supplementary angles

Class 9 Maths

What adds to 180 degrees

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Perimeter of a semicircle

Class 10 Maths

Curved half plus the diameter

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Area of a semicircle

Class 10 Maths

Half the area of a circle

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Turning effect (moments)

Class 9 Physics

Balance the see-saw with moments

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Reflex arc

Class 10 Biology

Step through a reflex, stimulus to action

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Buoyant force (upthrust)

Class 9 Physics

Displace liquid, feel the upthrust

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Relative density

Class 9 Physics

Compare a density to water's

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Power in lifting a load

Class 9 Physics

Lift a load, faster needs more power

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Cosecant ratio

Class 10 Maths

Hypotenuse over opposite

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Secant ratio

Class 10 Maths

Hypotenuse over adjacent

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Cotangent ratio

Class 10 Maths

Adjacent over opposite

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Height from angle of elevation

Class 10 Maths

Height from an angle of elevation

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Area of a quadrant

Class 10 Maths

A quarter of a circle's area

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Interior angle of a regular polygon

Class 8 Maths

One inside angle of a regular polygon

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Sum of first n odd numbers

Class 10 Maths

Add the first n odd numbers

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Sum of first n even numbers

Class 10 Maths

Add the first n even numbers

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Quadratic formula (a root)

Class 10 Maths

Larger root of a quadratic

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LCM from HCF

Class 10 Maths

LCM from the product and HCF

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Depreciation

Class 8 Maths

Value drops by a % each year

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Cost price from selling price

Class 8 Maths

Work back to the cost price

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Downstream speed

Class 8 Maths

Row with the current

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Upstream speed

Class 8 Maths

Row against the current

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Average speed for a round trip

Class 8 Maths

Average speed there and back

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Sales tax / GST

Class 8 Maths

Tax added on a price

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Area of a ring (annulus)

Class 10 Maths

Area of a ring between two circles

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Edge of a cube from volume

Class 9 Maths

Edge back from the volume

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Radius from area

Class 10 Maths

Radius back from a circle's area

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Side from area of a square

Class 8 Maths

Side back from a square's area

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Height of a triangle from area

Class 9 Maths

Height back from area and base

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Rate from simple interest

Class 8 Maths

Rate back from the interest

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Time from simple interest

Class 8 Maths

Time back from the interest

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Principal from simple interest

Class 8 Maths

Principal back from the interest

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Mean proportional

Class 10 Maths

Geometric mean of two numbers

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Fourth proportional

Class 8 Maths

Complete the proportion a : b = c : ?

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Marked price from selling price

Class 8 Maths

Marked price back from the sale price

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Chambers of the human heart

Class 10 Biology

Tap a heart chamber to see its job

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Equation of a line (y = mx + c)

Class 9 Maths

Read y off a straight line

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Average term of an AP

Class 10 Maths

Average of first and last term

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Number of terms in an AP

Class 10 Maths

How many terms in an AP

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Midpoint of two points

Class 10 Maths

x-coordinate of a midpoint

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Empirical mode

Class 10 Maths

Estimate the mode from mean & median

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Length of a shadow

Class 10 Maths

Shadow from height and sun angle

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Train crossing a pole

Class 8 Maths

Speed to cross a pole

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Time and work

Class 8 Maths

More workers, fewer days

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Dividing in a ratio

Class 8 Maths

Split a total in a ratio

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Unitary method

Class 8 Maths

Cost of a single item

Open

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Showing 78 questions in Mathematics for Class 10. Tap a card to reveal the answer.

MathematicsReal Numbersmedium

Find the HCF of 96 and 404 using Euclid's division algorithm.

Reveal answer ↓

What it is

Euclid's algorithm finds the HCF by repeated division until the remainder becomes zero.

Answer

Apply repeated division: 404 = 96 x 4 + 20; 96 = 20 x 4 + 16; 20 = 16 x 1 + 4; 16 = 4 x 4 + 0. The last non-zero remainder is 4, so HCF(96, 404) = 4.

a = bq + r, then HCF(a,b) = HCF(b,r)

  • 404 = 96 x 4 + 20
  • 96 = 20 x 4 + 16
  • 20 = 16 x 1 + 4
  • 16 = 4 x 4 + 0 -> HCF = 4

Why learn this

HCF simplifies fractions, shares things equally and even underpins computer cryptography (RSA).

💡 Memory trick

Divide, take the remainder, divide again. Last non-zero remainder = HCF.

MathematicsPolynomialseasy

Find the zeroes of the polynomial x^2 - 7x + 10 and verify the relationship between the zeroes and the coefficients.

Reveal answer ↓

What it is

The zeroes of a quadratic are where it equals zero; their sum is -b/a and product is c/a.

Answer

Factorise: x^2 - 7x + 10 = (x - 2)(x - 5), so the zeroes are 2 and 5. Sum of zeroes = 2 + 5 = 7 = -(-7)/1 = -b/a. Product of zeroes = 2 x 5 = 10 = 10/1 = c/a. Both relations hold.

Sum = -b/a ; Product = c/a

  • (x - 2)(x - 5) -> zeroes 2, 5
  • Sum = 7 = -b/a
  • Product = 10 = c/a

Why learn this

Finding roots is how we solve projectile paths, profit models and design problems in engineering.

💡 Memory trick

Sum = -b/a (has the minus), Product = c/a (plain).

MathematicsPair of Linear Equations in Two Variablesmedium

Solve the pair of equations: 2x + 3y = 13 and x - y = -1.

Reveal answer ↓

What it is

Two linear equations meet at one point - the (x, y) that satisfies both at once.

Answer

From the second equation, x = y - 1. Substitute into the first: 2(y - 1) + 3y = 13, so 5y - 2 = 13, giving 5y = 15 and y = 3. Then x = y - 1 = 2. Solution: x = 2, y = 3.

Substitution: express one variable, substitute into the other

  • x = y - 1 from second equation
  • 2(y-1) + 3y = 13 -> 5y = 15
  • y = 3, x = 2

Why learn this

It solves 'two unknowns' problems: prices, mixtures, speed-time and business break-even.

💡 Memory trick

Substitution: make one variable the subject, then plug it into the other equation.

MathematicsQuadratic Equationsmedium

Find the roots of x^2 - 5x + 6 = 0 and state the nature of the roots using the discriminant.

Reveal answer ↓

What it is

The discriminant D = b^2 - 4ac reveals the nature of a quadratic's roots before you solve it.

Answer

Factorise: (x - 2)(x - 3) = 0, so the roots are x = 2 and x = 3. The discriminant D = b^2 - 4ac = (-5)^2 - 4(1)(6) = 25 - 24 = 1. Since D > 0 and is a perfect square, the roots are real, distinct and rational.

D = b^2 - 4ac ; x = (-b +/- sqrt(D)) / 2a

  • (x-2)(x-3) = 0 -> roots 2, 3
  • D = b^2 - 4ac = 1
  • D > 0 -> two distinct real roots

Why learn this

Engineers use it to know at a glance if a design has real solutions (bridges, projectiles).

💡 Memory trick

D > 0 real and distinct; D = 0 real and equal; D < 0 no real roots.

MathematicsArithmetic Progressionseasy

The first term of an AP is 3 and the common difference is 5. Find its 10th term.

Reveal answer ↓

What it is

In an AP each term rises by a fixed step d; the nth term is a + (n - 1)d.

Answer

The nth term of an AP is a_n = a + (n - 1)d. Here a = 3, d = 5, n = 10, so a_10 = 3 + (10 - 1) x 5 = 3 + 45 = 48.

a_n = a + (n - 1)d

  • a_n = a + (n - 1)d
  • a = 3, d = 5, n = 10
  • a_10 = 48

Why learn this

APs model salaries with fixed raises, seating rows, EMIs and steady savings.

💡 Memory trick

nth term = start + (steps taken) x step = a + (n - 1)d.

MathematicsArithmetic Progressionsmedium

Find the sum of the first 20 terms of the AP 2, 5, 8, 11, ...

Reveal answer ↓

What it is

The sum of an AP pairs the first and last terms: S = n/2 [2a + (n - 1)d].

Answer

Here a = 2 and d = 3. The sum of n terms is S_n = n/2 [2a + (n - 1)d]. So S_20 = 20/2 [2(2) + 19(3)] = 10 [4 + 57] = 10 x 61 = 610.

S_n = n/2 [2a + (n - 1)d]

  • a = 2, d = 3, n = 20
  • S_n = n/2 [2a + (n-1)d]
  • S_20 = 10 x 61 = 610

Why learn this

It quickly totals things that grow steadily - savings, stacked logs, salaries over years.

💡 Memory trick

Sum = (number of terms / 2) x (2a + (n - 1)d): half the count times the bracket.

MathematicsTrianglesmedium

State the Basic Proportionality Theorem (Thales' theorem).

Reveal answer ↓

What it is

A line parallel to one side of a triangle cuts the other two sides in the same ratio.

Answer

The Basic Proportionality Theorem states that if a line is drawn parallel to one side of a triangle to intersect the other two sides at distinct points, then it divides those two sides in the same ratio. In triangle ABC, if DE is parallel to BC and meets AB at D and AC at E, then AD/DB = AE/EC.

If DE || BC then AD/DB = AE/EC

  • Line parallel to one side of a triangle
  • Divides the other two sides in the same ratio
  • AD/DB = AE/EC
  • Basis of similarity of triangles

Why learn this

It's the basis of similarity, scale drawings, maps and finding heights from shadows.

💡 Memory trick

Parallel line inside a triangle -> equal ratios: AD/DB = AE/EC.

MathematicsCoordinate Geometryeasy

Find the distance between the points (2, 3) and (5, 7).

Reveal answer ↓

What it is

The distance between two points is the hypotenuse of the right triangle of their coordinate gaps.

Answer

The distance formula is d = sqrt[(x2 - x1)^2 + (y2 - y1)^2]. Here d = sqrt[(5 - 2)^2 + (7 - 3)^2] = sqrt[9 + 16] = sqrt[25] = 5 units.

d = sqrt[(x2 - x1)^2 + (y2 - y1)^2]

  • d = sqrt[(x2-x1)^2 + (y2-y1)^2]
  • = sqrt[9 + 16] = sqrt[25]
  • Distance = 5 units

Why learn this

GPS, video games, robotics and maps all compute 'how far' with this exact formula.

💡 Memory trick

It's just Pythagoras: sqrt of (x-gap)^2 + (y-gap)^2.

MathematicsIntroduction to Trigonometrymedium

If sin(theta) = 3/5, find cos(theta) and tan(theta), where theta is acute.

Reveal answer ↓

What it is

The identity sin^2 + cos^2 = 1 lets you find one trig ratio from another for the same angle.

Answer

Using the identity sin^2(theta) + cos^2(theta) = 1, cos^2(theta) = 1 - (3/5)^2 = 1 - 9/25 = 16/25, so cos(theta) = 4/5 (positive since theta is acute). Then tan(theta) = sin/cos = (3/5) / (4/5) = 3/4.

sin^2(theta) + cos^2(theta) = 1 ; tan = sin/cos

  • sin^2 + cos^2 = 1
  • cos(theta) = 4/5
  • tan(theta) = sin/cos = 3/4

Why learn this

Trig ratios drive navigation, physics waves, construction and computer graphics.

💡 Memory trick

Think of the 3-4-5 triangle: sin 3/5 -> cos 4/5 -> tan 3/4.

MathematicsSome Applications of Trigonometrymedium

The angle of elevation of the top of a tower from a point 30 m from its base is 30 degrees. Find the height of the tower.

Reveal answer ↓

What it is

An angle of elevation turns a triangle into a height problem using tan = opposite / adjacent.

Answer

Let the height be h. tan(30 degrees) = h / 30, and tan(30 degrees) = 1/sqrt(3). So h = 30 x (1/sqrt(3)) = 30/sqrt(3) = 10 sqrt(3) m, which is about 17.3 m.

tan(theta) = height / base distance

  • tan(angle) = opposite/adjacent = h/30
  • tan(30 deg) = 1/sqrt(3)
  • h = 10 sqrt(3) m (about 17.3 m)

Why learn this

Surveyors, pilots and builders measure unreachable heights (towers, hills) exactly this way.

💡 Memory trick

Draw the right triangle; tan(angle) = height / base distance.

MathematicsCirclesmedium

A point P is 13 cm from the centre of a circle of radius 5 cm. Find the length of the tangent drawn from P to the circle.

Reveal answer ↓

What it is

A tangent touches a circle at one point and is perpendicular to the radius at that point.

Answer

The tangent is perpendicular to the radius at the point of contact, so the radius, tangent and line OP form a right-angled triangle with OP as the hypotenuse. Length of tangent = sqrt[OP^2 - r^2] = sqrt[13^2 - 5^2] = sqrt[169 - 25] = sqrt[144] = 12 cm.

tangent length = sqrt[OP^2 - r^2]

  • Tangent is perpendicular to radius at contact
  • Right triangle: OP hypotenuse
  • Length = sqrt[13^2 - 5^2] = 12 cm

Why learn this

It's used in gear design, road curves and belt-and-pulley engineering.

💡 Memory trick

Radius, tangent and line to the point form a right triangle: tangent = sqrt(OP^2 - r^2).

MathematicsSurface Areas and Volumeseasy

Find the volume of a cone whose base radius is 3 cm and height is 4 cm. (Take pi = 22/7.)

Reveal answer ↓

What it is

A cone's volume is exactly one-third of a cylinder with the same base and height.

Answer

Volume of a cone = (1/3) x pi x r^2 x h = (1/3) x (22/7) x 3^2 x 4 = (1/3) x (22/7) x 36 = (22 x 12) / 7 = 264/7, which is about 37.7 cubic cm.

V(cone) = (1/3) pi r^2 h

  • V = (1/3) pi r^2 h
  • = (1/3)(22/7)(9)(4)
  • = 264/7 = about 37.7 cm^3

Why learn this

It's how we measure ice-cream cones, funnels, heaps of grain and tent capacity.

💡 Memory trick

Cone = 1/3 x pi r^2 h - a cone is a third of its cylinder.

MathematicsStatisticsmedium

The mean of a distribution is 27 and its median is 30. Estimate the mode using the empirical relationship.

Reveal answer ↓

What it is

For a moderately skewed data set, the three averages link as Mode = 3 Median - 2 Mean.

Answer

The empirical relationship between the three measures of central tendency is Mode = 3 Median - 2 Mean. Substituting, Mode = 3(30) - 2(27) = 90 - 54 = 36.

Mode = 3 Median - 2 Mean

  • Mode = 3 Median - 2 Mean
  • = 3(30) - 2(27)
  • = 90 - 54 = 36

Why learn this

It estimates the most common value from the other two - handy in surveys and economics.

💡 Memory trick

Mode = 3 Median - 2 Mean ('3M minus 2-Mean gives the Mode').

MathematicsProbabilityeasy

One card is drawn at random from a well-shuffled deck of 52 playing cards. What is the probability that it is a king?

Reveal answer ↓

What it is

Probability = favourable outcomes / total outcomes, always a number between 0 and 1.

Answer

There are 4 kings in a deck of 52 cards. Probability = number of favourable outcomes / total outcomes = 4/52 = 1/13.

P(event) = favourable outcomes / total outcomes

  • 4 kings in 52 cards
  • P = favourable/total = 4/52
  • = 1/13

Why learn this

It powers weather forecasts, insurance, games, medical trials and AI.

💡 Memory trick

Favourable over Total: 4 kings out of 52 -> 4/52 = 1/13.

MathematicsIntroduction to Trigonometrymedium

Evaluate 2 tan^2(45 degrees) + cos^2(30 degrees) - sin^2(60 degrees).

Reveal answer ↓

What it is

The standard angles 0, 30, 45, 60 and 90 degrees have fixed trig values worth memorising.

Answer

Use standard values: tan(45 deg) = 1, cos(30 deg) = sqrt(3)/2, sin(60 deg) = sqrt(3)/2. So the expression = 2(1)^2 + (sqrt(3)/2)^2 - (sqrt(3)/2)^2 = 2 + 3/4 - 3/4 = 2.

tan45 = 1 ; cos30 = sqrt(3)/2 ; sin60 = sqrt(3)/2

  • tan45 = 1, cos30 = sin60 = sqrt(3)/2
  • 2(1) + 3/4 - 3/4
  • = 2

Why learn this

They appear in nearly every physics and maths problem - knowing them saves huge time.

💡 Memory trick

For sin, use sqrt(0..4)/2 across 0,30,45,60,90; cos is the same list reversed.

MathematicsProbabilityeasy

What is the probability of rolling a 4 on a fair die? Change the outcomes to explore.

Reveal answer ↓

What it is

Probability measures how likely an event is - favourable outcomes out of all equally likely outcomes.

Probability = favourable ÷ total
Probability0.17

Answer

Probability = favourable outcomes / total outcomes = 1 / 6 = 0.167 (about 17%). A fair die has 6 equally likely faces and only one of them is a 4. Every probability lies between 0 (impossible) and 1 (certain).

P(event) = favourable outcomes / total outcomes

  • P = favourable outcomes / total outcomes
  • Always between 0 and 1
  • One face of a die: 1/6

Why learn this

It's the maths behind games, weather forecasts and risk.

💡 Memory trick

P = favourable / total, always between 0 and 1.

MathematicsSurface Areas and Volumesmedium

Find the volume of a cylinder of radius 3 and height 7 units (pi = 3.14159). Slide to explore.

Reveal answer ↓

What it is

The volume of a cylinder is the area of its circular base times its height.

Cylinder volume = π × r² × h
Volume197.9 units³

Answer

Volume = pi x r^2 x h = 3.14159 x 3^2 x 7 = 3.14159 x 9 x 7 = 197.9 cubic units. The base is a circle of area pi x r^2, and stacking it to a height h gives the volume.

V = pi x r^2 x h

  • Volume = pi x r^2 x h
  • Base area (pi x r^2) times height
  • Unit: cubic units

Why learn this

It measures the capacity of cans, pipes, tanks and drums.

💡 Memory trick

Volume = pi x r^2 x h - base area times height.

MathematicsSurface Areas and Volumesmedium

Find the surface area of a sphere of radius 7 units (pi = 3.14159). Slide to explore.

Reveal answer ↓

What it is

The surface area of a sphere is four times pi times the square of its radius.

Sphere surface area = 4 × π × r²
Surface area615.8 units²

Answer

Surface area = 4 x pi x r^2 = 4 x 3.14159 x 7^2 = 4 x 3.14159 x 49 = 615.75 square units. Remarkably, a sphere's surface is exactly four times the area of its flat circular cross-section (pi x r^2).

S = 4 x pi x r^2

  • Surface area = 4 x pi x r^2
  • Four times the flat circle pi x r^2
  • Unit: square units

Why learn this

It measures the skin of balls, bubbles and planets.

💡 Memory trick

Surface area = 4 x pi x r^2 - four times the flat circle.

MathematicsArithmetic Progressionsmedium

Find the 5th term of the AP starting at 2 with common difference 3. Slide to explore.

Reveal answer ↓

What it is

In an arithmetic progression, each term is found by adding the common difference to the first term repeatedly.

nth term = a + (n − 1) × d
nth term14

Answer

nth term = a + (n - 1) d = 2 + (5 - 1) x 3 = 2 + 12 = 14. We add the common difference (n - 1) times because the first term already counts as term 1.

a_n = a + (n - 1) d

  • nth term = a + (n - 1) d
  • a is the first term, d the common difference
  • Add d one time fewer than n

Why learn this

It's how we jump straight to any term without listing them all.

💡 Memory trick

nth term = a + (n - 1) d.

MathematicsArithmetic Progressionsmedium

Find the sum of the first 5 terms of the AP starting at 2 with common difference 3. Slide to explore.

Reveal answer ↓

What it is

The sum of the first n terms of an arithmetic progression is n/2 times the sum of twice the first term and (n - 1) times the common difference.

Sum = n÷2 × (2a + (n − 1)d)
Sum of n terms40

Answer

Sum = n/2 x (2a + (n - 1) d) = 5/2 x (2x2 + (5 - 1) x 3) = 5/2 x (4 + 12) = 5/2 x 16 = 40. This equals the number of terms times the average of the first and last term.

S_n = n/2 x (2a + (n - 1) d)

  • Sum = n/2 x (2a + (n - 1) d)
  • Equals n x average of first and last term
  • For evenly spaced terms

Why learn this

It adds up long evenly-spaced lists, like seats or savings, in one step.

💡 Memory trick

Sum = n/2 x (2a + (n - 1) d).

MathematicsCoordinate Geometrymedium

A line rises 6 units over a run of 3 units. Find its slope. Slide to explore.

Reveal answer ↓

What it is

The slope of a line is how much it rises for each unit it runs across.

Slope = rise ÷ run
Slope (m)2.00

Answer

Slope = rise / run = 6 / 3 = 2. A slope of 2 means the line climbs 2 units for every 1 unit across. A negative slope would mean the line falls as you move right.

slope = rise / run

  • Slope = rise / run
  • Positive climbs, negative falls
  • Zero slope is a flat line

Why learn this

It measures steepness for graphs, roads, ramps and roofs.

💡 Memory trick

Slope = rise / run. Up is positive, down is negative.

MathematicsAreas Related to Circlesmedium

Find the area of a 90 degree sector of a circle of radius 7 units (pi = 3.14159). Slide to explore.

Reveal answer ↓

What it is

The area of a sector is the fraction of the circle its angle covers, times the circle's area.

Sector area = (θ ÷ 360) × πr²
Sector area38.5 units²

Answer

Sector area = (angle / 360) x pi x r^2 = (90 / 360) x 3.14159 x 7^2 = 0.25 x 3.14159 x 49 = 38.48 square units. A 90 degree sector is one quarter of the circle, so it has a quarter of the circle's area.

sector area = (angle / 360) x pi x r^2

  • Sector area = (angle / 360) x pi x r^2
  • It's a fraction of the whole circle
  • At 360 degrees it is the full circle

Why learn this

It measures pie-chart slices, fan sweeps and pizza pieces.

💡 Memory trick

Sector area = (angle / 360) x pi x r^2.

MathematicsAreas Related to Circlesmedium

Find the length of a 90 degree arc of a circle of radius 7 units (pi = 3.14159). Slide to explore.

Reveal answer ↓

What it is

The length of an arc is the fraction of the circumference that its angle subtends.

Arc length = (θ ÷ 360) × 2πr
Arc length11.0 units

Answer

Arc length = (angle / 360) x 2 x pi x r = (90 / 360) x 2 x 3.14159 x 7 = 0.25 x 43.98 = 11.0 units. A 90 degree arc is one quarter of the full circumference of the circle.

arc length = (angle / 360) x 2 x pi x r

  • Arc length = (angle / 360) x 2 x pi x r
  • A fraction of the circumference
  • Unit: units of length

Why learn this

It measures curved paths, tracks and the edges of sectors.

💡 Memory trick

Arc length = (angle / 360) x 2 x pi x r.

MathematicsQuadratic Equationsmedium

Find the discriminant of x^2 + 5x + 6 = 0. Slide a, b and c to explore.

Reveal answer ↓

What it is

The discriminant of a quadratic equation tells how many real roots it has.

Discriminant = b² − 4ac
Discriminant (D)1

Answer

Discriminant D = b^2 - 4ac = 5^2 - 4 x 1 x 6 = 25 - 24 = 1. Since D is positive, the equation has two distinct real roots. If D were 0 there would be one repeated root, and if D were negative there would be no real roots.

D = b^2 - 4ac

  • D = b^2 - 4ac
  • D > 0: two real roots; D = 0: one; D < 0: none
  • Found without solving

Why learn this

It reveals the nature of the roots without actually solving the equation.

💡 Memory trick

D = b^2 - 4ac. Positive -> 2 roots, zero -> 1, negative -> none.

MathematicsQuadratic Equationsmedium

Find the sum of the roots of x^2 - 5x + 6 = 0. Slide a and b to explore.

Reveal answer ↓

What it is

The sum of the roots of a quadratic equation is minus b divided by a.

Sum of roots = −b ÷ a
Sum of roots5.00

Answer

Sum of roots = -b / a = -(-5) / 1 = 5. Indeed the roots of x^2 - 5x + 6 = 0 are 2 and 3, which add to 5. The product of the roots is c / a = 6, matching 2 x 3.

sum of roots = -b / a

  • Sum of roots = -b / a
  • Product of roots = c / a
  • Relates roots to coefficients

Why learn this

It relates the roots directly to the coefficients, without solving.

💡 Memory trick

Sum of roots = -b / a; product = c / a.

MathematicsIntroduction to Trigonometrymedium

In a right triangle the opposite side is 3 and the hypotenuse is 5. Find sin of the angle. Slide to explore.

Reveal answer ↓

What it is

In a right triangle, the sine of an angle is the opposite side divided by the hypotenuse.

sin θ = opposite ÷ hypotenuse
sin θ0.600

Answer

sin(theta) = opposite / hypotenuse = 3 / 5 = 0.6. The sine of an acute angle is always between 0 and 1, because the opposite side is never longer than the hypotenuse.

sin(theta) = opposite / hypotenuse

  • sin = opposite / hypotenuse (SOH)
  • Always between 0 and 1
  • 3-4-5 triangle gives sin = 0.6

Why learn this

Sine links an angle to side lengths - the heart of trigonometry.

💡 Memory trick

SOH: Sine = Opposite / Hypotenuse.

MathematicsIntroduction to Trigonometrymedium

In a right triangle the adjacent side is 4 and the hypotenuse is 5. Find cos of the angle. Slide to explore.

Reveal answer ↓

What it is

In a right triangle, the cosine of an angle is the adjacent side divided by the hypotenuse.

cos θ = adjacent ÷ hypotenuse
cos θ0.800

Answer

cos(theta) = adjacent / hypotenuse = 4 / 5 = 0.8. Like sine, it lies between 0 and 1, and the two obey the identity sin^2(theta) + cos^2(theta) = 1.

cos(theta) = adjacent / hypotenuse

  • cos = adjacent / hypotenuse (CAH)
  • Always between 0 and 1
  • sin^2 + cos^2 = 1

Why learn this

Cosine pairs with sine to resolve forces, waves and vectors.

💡 Memory trick

CAH: Cosine = Adjacent / Hypotenuse.

MathematicsIntroduction to Trigonometrymedium

In a right triangle the opposite side is 3 and the adjacent side is 4. Find tan of the angle. Slide to explore.

Reveal answer ↓

What it is

In a right triangle, the tangent of an angle is the opposite side divided by the adjacent side.

tan θ = opposite ÷ adjacent
tan θ0.750

Answer

tan(theta) = opposite / adjacent = 3 / 4 = 0.75. It also equals sin(theta) / cos(theta), and it grows without limit as the angle approaches 90 degrees.

tan(theta) = opposite / adjacent

  • tan = opposite / adjacent (TOA)
  • tan = sin / cos
  • Grows large near 90 degrees

Why learn this

Tangent gives the slope of a line and heights from angles of elevation.

💡 Memory trick

TOA: Tangent = Opposite / Adjacent.

MathematicsCoordinate Geometrymedium

Find the distance between (0, 0) and (3, 4). Slide the coordinates to explore.

Reveal answer ↓

What it is

The distance between two points is the square root of the sum of the squares of the differences in their coordinates.

Distance = √((x₂−x₁)² + (y₂−y₁)²)
Distance5.00 units

Answer

Distance = sqrt((x2 - x1)^2 + (y2 - y1)^2) = sqrt((3 - 0)^2 + (4 - 0)^2) = sqrt(9 + 16) = sqrt(25) = 5 units. It is simply the Pythagoras theorem applied to the horizontal and vertical gaps between the points.

d = sqrt((x2 - x1)^2 + (y2 - y1)^2)

  • Distance = sqrt((x2 - x1)^2 + (y2 - y1)^2)
  • Pythagoras on coordinates
  • (0,0) to (3,4) is 5

Why learn this

It measures straight-line gaps on a graph or map.

💡 Memory trick

Distance = sqrt((x2 - x1)^2 + (y2 - y1)^2).

MathematicsArithmetic Progressionseasy

Find the sum 1 + 2 + 3 + ... + 10. Slide n to explore.

Reveal answer ↓

What it is

The sum of the first n natural numbers is n times n plus one, divided by two.

Sum = n × (n + 1) ÷ 2
Sum 1 to n55

Answer

Sum = n(n + 1) / 2 = 10 x 11 / 2 = 55. This is an arithmetic progression with first term 1 and common difference 1; pairing the first and last terms gives the neat n(n + 1) / 2 formula.

sum = n(n + 1) / 2

  • Sum = n(n + 1) / 2
  • 1 to 100 sums to 5050
  • An AP with a = 1, d = 1

Why learn this

It totals a long list of consecutive numbers in one step.

💡 Memory trick

Sum = n(n + 1) / 2.

MathematicsAreas Related to Circlesmedium

Find the perimeter of a 90 degree sector of radius 7 units (pi = 3.14159). Slide to explore.

Reveal answer ↓

What it is

The perimeter of a sector is its two straight radii plus the curved arc.

Sector perimeter = 2r + arc
Perimeter25.0 units

Answer

Perimeter = 2r + arc = 2 x 7 + (90 / 360) x 2 x 3.14159 x 7 = 14 + 11.0 = 25.0 units. It is the two radii bounding the sector plus the curved arc along the circle.

perimeter = 2r + (angle / 360) x 2 pi r

  • Perimeter = 2r + arc length
  • Arc = (angle / 360) x 2 pi r
  • Two radii plus the curved edge

Why learn this

It measures the boundary of a pie slice or a fan.

💡 Memory trick

Perimeter = 2r + arc = 2r + (angle / 360) x 2 pi r.

MathematicsProbabilityeasy

What is the probability of NOT rolling a 4 on a die? Change the outcomes to explore.

Reveal answer ↓

What it is

The probability that an event does not happen is one minus the probability that it does.

P(not E) = 1 − P(E)
P(not E)0.833

Answer

P(not E) = 1 - P(E) = 1 - 1/6 = 5/6 (about 0.833). The event and its complement together cover every outcome, so their probabilities always add up to 1.

P(not E) = 1 - P(E)

  • P(not E) = 1 - P(E)
  • An event and its complement add to 1
  • Not rolling a 4 has probability 5/6

Why learn this

It's often far easier to find the chance of the opposite event.

💡 Memory trick

P(not E) = 1 - P(E).

MathematicsQuadratic Equationsmedium

Find the product of the roots of x^2 - 5x + 6 = 0. Slide a and c to explore.

Reveal answer ↓

What it is

The product of the roots of a quadratic equation is c divided by a.

Product of roots = c ÷ a
Product of roots6.00

Answer

Product of roots = c / a = 6 / 1 = 6. The roots of x^2 - 5x + 6 = 0 are 2 and 3, and indeed 2 x 3 = 6. Their sum is -b / a = 5, matching 2 + 3.

product of roots = c / a

  • Product of roots = c / a
  • Sum of roots = -b / a
  • Relates roots to coefficients

Why learn this

It relates the roots to the coefficients without solving the equation.

💡 Memory trick

Product of roots = c / a; sum = -b / a.

MathematicsIntroduction to Trigonometryeasy

What is the complement of a 30 degree angle? Slide the angle to explore.

Reveal answer ↓

What it is

Two angles are complementary when they add up to 90 degrees.

Complement = 90° − angle
Complementary angle60 °

Answer

Complement = 90 - angle = 90 - 30 = 60 degrees. Complementary angles add to a right angle, which is why the sine of an angle equals the cosine of its complement: sin(30) = cos(60).

complement = 90 - angle

  • Complement = 90 - angle
  • The two add to 90 degrees
  • sin(theta) = cos(90 - theta)

Why learn this

Complementary angles link sine and cosine: sin(theta) = cos(90 - theta).

💡 Memory trick

Complement = 90 - angle.

MathematicsAreas Related to Circlesmedium

Find the perimeter of a semicircle of radius 7 units (pi = 3.14159). Slide to explore.

Reveal answer ↓

What it is

The perimeter of a semicircle is the curved half of the circumference plus the straight diameter.

Semicircle perimeter = πr + 2r
Perimeter36.0 units

Answer

Perimeter = pi x r + 2r = 3.14159 x 7 + 2 x 7 = 21.99 + 14 = 35.99 units. The curved part is half the circumference (pi x r), and we must add the straight diameter (2r) that closes the shape.

perimeter = pi x r + 2r

  • Perimeter = pi x r + 2r
  • Curved half + straight diameter
  • Do not forget the diameter

Why learn this

A common trap is to forget the straight edge and halve the whole circumference.

💡 Memory trick

Perimeter = pi x r + 2r (curved half + diameter).

MathematicsAreas Related to Circleseasy

Find the area of a semicircle of radius 7 units (pi = 3.14159). Slide to explore.

Reveal answer ↓

What it is

The area of a semicircle is half the area of the full circle.

Semicircle area = ½ × π × r²
Area77.0 units²

Answer

Area = 1/2 x pi x r^2 = 1/2 x 3.14159 x 7^2 = 1/2 x 3.14159 x 49 = 76.97 square units. A semicircle is exactly half a circle, so we take half of pi x r^2.

area = (1/2) x pi x r^2

  • Area = 1/2 x pi x r^2
  • Half of a full circle
  • Unit: square units

Why learn this

It sizes half-round windows, arches and protractors.

💡 Memory trick

Area = 1/2 x pi x r^2.

MathematicsIntroduction to Trigonometrymedium

In a right triangle the hypotenuse is 5 and the opposite side is 3. Find cosec of the angle. Slide to explore.

Reveal answer ↓

What it is

The cosecant of an angle is the hypotenuse divided by the opposite side, the reciprocal of sine.

cosec θ = hypotenuse ÷ opposite
cosec θ1.667

Answer

cosec(theta) = hypotenuse / opposite = 5 / 3 = 1.667. It is the reciprocal of the sine ratio, so cosec(theta) = 1 / sin(theta).

cosec(theta) = hypotenuse / opposite

  • cosec = hypotenuse / opposite
  • cosec = 1 / sin
  • A reciprocal ratio

Why learn this

The reciprocal ratios complete the trigonometric toolkit.

💡 Memory trick

cosec = hypotenuse / opposite = 1 / sin.

MathematicsIntroduction to Trigonometrymedium

In a right triangle the hypotenuse is 5 and the adjacent side is 4. Find sec of the angle. Slide to explore.

Reveal answer ↓

What it is

The secant of an angle is the hypotenuse divided by the adjacent side, the reciprocal of cosine.

sec θ = hypotenuse ÷ adjacent
sec θ1.250

Answer

sec(theta) = hypotenuse / adjacent = 5 / 4 = 1.25. It is the reciprocal of the cosine ratio, so sec(theta) = 1 / cos(theta).

sec(theta) = hypotenuse / adjacent

  • sec = hypotenuse / adjacent
  • sec = 1 / cos
  • A reciprocal ratio

Why learn this

It appears whenever the cosine sits in a denominator.

💡 Memory trick

sec = hypotenuse / adjacent = 1 / cos.

MathematicsIntroduction to Trigonometrymedium

In a right triangle the adjacent side is 4 and the opposite side is 3. Find cot of the angle. Slide to explore.

Reveal answer ↓

What it is

The cotangent of an angle is the adjacent side divided by the opposite side, the reciprocal of tangent.

cot θ = adjacent ÷ opposite
cot θ1.333

Answer

cot(theta) = adjacent / opposite = 4 / 3 = 1.333. It is the reciprocal of the tangent ratio, so cot(theta) = 1 / tan(theta).

cot(theta) = adjacent / opposite

  • cot = adjacent / opposite
  • cot = 1 / tan
  • A reciprocal ratio

Why learn this

It completes the six trigonometric ratios.

💡 Memory trick

cot = adjacent / opposite = 1 / tan.

MathematicsSome Applications of Trigonometrymedium

From 50 m away, the top of a tower has an angle of elevation of 30 degrees. Find its height. Slide to explore.

Reveal answer ↓

What it is

The height of an object is the horizontal distance to it times the tangent of the angle of elevation.

Height = distance × tan θ
Height28.9 m

Answer

Height = distance x tan(theta) = 50 x tan(30) = 50 x 0.577 = 28.87 m. The horizontal distance is the adjacent side and the height is the opposite side, so tan links them.

height = distance x tan(angle of elevation)

  • Height = distance x tan(angle)
  • Uses tan = opposite / adjacent
  • Measures unreachable heights

Why learn this

It's how we measure the height of towers, trees and hills from the ground.

💡 Memory trick

Height = distance x tan(angle of elevation).

MathematicsAreas Related to Circleseasy

Find the area of a quadrant of radius 7 units (pi = 3.14159). Slide to explore.

Reveal answer ↓

What it is

A quadrant is a quarter of a circle, so its area is a quarter of the circle's area.

Quadrant area = ¼ × π × r²
Area38.5 units²

Answer

Area = 1/4 x pi x r^2 = 1/4 x 3.14159 x 7^2 = 1/4 x 3.14159 x 49 = 38.48 square units. A quadrant is a 90 degree sector, which is one quarter of the whole circle.

area = (1/4) x pi x r^2

  • Quadrant area = 1/4 x pi x r^2
  • A 90 degree sector
  • One quarter of the circle

Why learn this

It sizes quarter-round corners, fans and garden beds.

💡 Memory trick

Quadrant area = 1/4 x pi x r^2.

MathematicsArithmetic Progressionseasy

Find 1 + 3 + 5 + 7 + 9. Slide how many odd numbers to explore.

Reveal answer ↓

What it is

The sum of the first n odd numbers is always n squared.

1 + 3 + 5 + ... (n terms) = n²
Sum25

Answer

The sum of the first n odd numbers = n^2. For n = 5 that is 1 + 3 + 5 + 7 + 9 = 25 = 5^2. It is an arithmetic progression with first term 1 and common difference 2.

sum = n^2

  • Sum of first n odd numbers = n^2
  • 1 + 3 + 5 + 7 + 9 = 25
  • An AP with a = 1, d = 2

Why learn this

It's a neat pattern that connects odd numbers to perfect squares.

💡 Memory trick

1 + 3 + 5 + ... (n terms) = n^2.

MathematicsArithmetic Progressionseasy

Find 2 + 4 + 6 + 8 + 10. Slide how many even numbers to explore.

Reveal answer ↓

What it is

The sum of the first n even numbers is n times n plus one.

2 + 4 + 6 + ... (n terms) = n(n + 1)
Sum30

Answer

The sum of the first n even numbers = n(n + 1). For n = 5 that is 2 + 4 + 6 + 8 + 10 = 30 = 5 x 6. It is an arithmetic progression with first term 2 and common difference 2.

sum = n(n + 1)

  • Sum of first n even numbers = n(n + 1)
  • 2 + 4 + 6 + 8 + 10 = 30
  • An AP with a = 2, d = 2

Why learn this

It's a quick pattern that mirrors the odd-number sum.

💡 Memory trick

2 + 4 + 6 + ... (n terms) = n(n + 1).

MathematicsQuadratic Equationshard

Find a root of x^2 - 5x + 6 = 0 using the quadratic formula. Slide a, b, c to explore.

Reveal answer ↓

What it is

The quadratic formula gives the roots of any quadratic equation from its coefficients.

Root = (−b + √D) ÷ 2a
Larger root3.00

Answer

x = (-b + sqrt(b^2 - 4ac)) / 2a = (5 + sqrt(25 - 24)) / 2 = (5 + 1) / 2 = 3. Using the minus sign gives the other root, 2. If b^2 - 4ac is negative there are no real roots.

x = (-b + sqrt(b^2 - 4ac)) / 2a

  • x = (-b +/- sqrt(b^2 - 4ac)) / 2a
  • The + sign gives the larger root
  • No real root when b^2 - 4ac < 0

Why learn this

It solves every quadratic, even those that do not factorise neatly.

💡 Memory trick

x = (-b +/- sqrt(b^2 - 4ac)) / 2a.

MathematicsReal Numbersmedium

The HCF of 12 and 18 is 6. Find their LCM. Slide the values to explore.

Reveal answer ↓

What it is

For two numbers, the product of the HCF and LCM equals the product of the numbers.

LCM = (a × b) ÷ HCF
LCM36

Answer

Since HCF x LCM = a x b, LCM = (a x b) / HCF = (12 x 18) / 6 = 216 / 6 = 36. This identity holds for any pair of positive integers.

LCM = (a x b) / HCF

  • HCF x LCM = a x b
  • LCM = (a x b) / HCF
  • For 12 and 18, LCM = 36

Why learn this

It's a fast way to find the LCM once you know the HCF.

💡 Memory trick

HCF x LCM = a x b, so LCM = (a x b) / HCF.

MathematicsAreas Related to Circlesmedium

Find the area of a ring with outer radius 10 and inner radius 6 units (pi = 3.14159). Slide to explore.

Reveal answer ↓

What it is

The area of a ring is the area of the outer circle minus the area of the inner circle.

Ring area = π × (R² − r²)
Ring area201.1 units²

Answer

Ring area = pi x (R^2 - r^2) = 3.14159 x (10^2 - 6^2) = 3.14159 x (100 - 36) = 3.14159 x 64 = 201.06 square units. We take the big circle's area and subtract the hole in the middle.

area = pi x (R^2 - r^2)

  • Ring area = pi x (R^2 - r^2)
  • Outer circle minus inner circle
  • Unit: square units

Why learn this

It measures washers, pipe cross-sections and circular tracks.

💡 Memory trick

Ring area = pi x (R^2 - r^2).

MathematicsAreas Related to Circlesmedium

A circle has an area of 154 square units. Find its radius (pi = 3.14159). Slide to explore.

Reveal answer ↓

What it is

The radius of a circle is the square root of its area divided by pi.

Radius = √(area ÷ π)
Radius7.00 units

Answer

Radius = sqrt(area / pi) = sqrt(154 / 3.14159) = sqrt(49.02) = 7.0 units. This reverses the area formula area = pi x r^2 to make the radius the subject.

r = sqrt(area / pi)

  • r = sqrt(area / pi)
  • Reverses area = pi x r^2
  • Area 154 -> radius 7

Why learn this

It reverses the area formula to find the radius.

💡 Memory trick

Since area = pi x r^2, r = sqrt(area / pi).

MathematicsTrianglesmedium

Find the mean proportional between 4 and 9. Slide the values to explore.

Reveal answer ↓

What it is

The mean proportional between two numbers is the square root of their product.

Mean proportional = √(a × b)
Mean proportional6.00

Answer

Mean proportional = sqrt(a x b) = sqrt(4 x 9) = sqrt(36) = 6. It is the value x for which a : x = x : b, so x^2 = a x b.

mean proportional = sqrt(a x b)

  • Mean proportional = sqrt(a x b)
  • The geometric mean
  • Between 4 and 9 it is 6

Why learn this

It appears in similar triangles and the geometric mean.

💡 Memory trick

Mean proportional between a and b = sqrt(a x b).

MathematicsArithmetic Progressionseasy

Find the average term of the AP from 2 to 14. Slide the first and last terms to explore.

Reveal answer ↓

What it is

The average of all terms of an arithmetic progression equals the average of its first and last term.

AP mean = (first + last) ÷ 2
Average term8.0

Answer

Average term = (first + last) / 2 = (2 + 14) / 2 = 16 / 2 = 8. Because the terms are evenly spaced, the middle value is exactly the average of the two ends.

average term = (first + last) / 2

  • Average term = (first + last) / 2
  • Terms are evenly spaced
  • Sum = number of terms x average

Why learn this

It's why the AP sum equals the number of terms times this average.

💡 Memory trick

Average term = (first + last) / 2.

MathematicsArithmetic Progressionsmedium

How many terms are in the AP 2, 5, 8, 11, 14? Slide the values to explore.

Reveal answer ↓

What it is

The number of terms in an arithmetic progression is found from the first term, last term and common difference.

n = (last − first) ÷ d + 1
Number of terms5

Answer

Number of terms n = (last - first) / d + 1 = (14 - 2) / 3 + 1 = 12 / 3 + 1 = 4 + 1 = 5. We count the steps of size d from the first to the last term, then add one for the starting term.

n = (last - first) / d + 1

  • n = (last - first) / d + 1
  • Count the steps, then add 1
  • 2, 5, 8, 11, 14 has 5 terms

Why learn this

It tells how long a sequence of evenly spaced values is.

💡 Memory trick

n = (last - first) / d + 1.

MathematicsCoordinate Geometryeasy

Find the x-coordinate of the midpoint of x = 2 and x = 8. Slide the values to explore.

Reveal answer ↓

What it is

The midpoint of two points is found by averaging their x-coordinates and their y-coordinates.

Midpoint x = (x₁ + x₂) ÷ 2
Midpoint x5.0

Answer

Midpoint x = (x1 + x2) / 2 = (2 + 8) / 2 = 10 / 2 = 5. The full midpoint formula averages both coordinates: ((x1 + x2)/2, (y1 + y2)/2).

midpoint x = (x1 + x2) / 2

  • Midpoint x = (x1 + x2) / 2
  • Average both coordinates
  • Midpoint of 2 and 8 is 5

Why learn this

It locates the exact centre of a line segment.

💡 Memory trick

Midpoint x = (x1 + x2) / 2 (and the same for y).

MathematicsStatisticsmedium

A data set has a median of 40 and a mean of 38. Estimate the mode. Slide the values to explore.

Reveal answer ↓

What it is

An empirical relation estimates the mode from the mean and the median.

Mode = 3 × median − 2 × mean
Mode (estimate)44.0

Answer

Mode = 3 x Median - 2 x Mean = 3 x 40 - 2 x 38 = 120 - 76 = 44. This empirical formula connects the mean, median and mode for moderately skewed data.

mode = 3 x median - 2 x mean

  • Mode = 3 x Median - 2 x Mean
  • Links the three averages
  • Median 40, mean 38 -> mode 44

Why learn this

It links the three measures of central tendency.

💡 Memory trick

Mode = 3 x Median - 2 x Mean.

MathematicsSome Applications of Trigonometrymedium

A 50 m tower casts a shadow when the sun is at 45 degrees. Find the shadow length. Slide to explore.

Reveal answer ↓

What it is

The length of a shadow is the object's height divided by the tangent of the sun's angle of elevation.

Shadow = height ÷ tan θ
Shadow length50.0 m

Answer

Shadow = height / tan(angle) = 50 / tan(45) = 50 / 1 = 50 m. As the sun gets lower, the angle shrinks, tan gets smaller, and the shadow grows much longer.

shadow = height / tan(angle of elevation)

  • Shadow = height / tan(angle)
  • Lower sun -> longer shadow
  • At 45 degrees, shadow equals the height

Why learn this

It's why shadows are long at sunrise and short at noon.

💡 Memory trick

Shadow = height / tan(sun's angle).

MathematicsReal Numbersmedium

The HCF of two numbers is 6 and their product is 216. Find their LCM.

Reveal answer ↓

What it is

For two numbers, the product of their HCF and LCM equals the product of the numbers.

Answer

For any two numbers, HCF x LCM = product of the two numbers. So LCM = product / HCF = 216 / 6 = 36. Therefore the LCM of the two numbers is 36.

HCF x LCM = product of the two numbers

  • HCF x LCM = product of the numbers
  • LCM = product / HCF
  • = 216 / 6
  • LCM = 36

Why learn this

It lets you find the LCM quickly once you know the HCF, and vice versa.

💡 Memory trick

HCF x LCM = product of the two numbers.

MathematicsReal Numbersmedium

State the fundamental theorem of arithmetic and use it to find the HCF and LCM of 12 and 18.

Reveal answer ↓

What it is

Every composite number can be expressed as a unique product of prime numbers.

Answer

The fundamental theorem of arithmetic states that every composite number can be expressed (factorised) as a product of primes, and this factorisation is unique except for the order of the factors. Prime factorising: 12 = 2^2 x 3 and 18 = 2 x 3^2. The HCF is the product of the smallest powers of common primes = 2^1 x 3^1 = 6. The LCM is the product of the greatest powers of all primes = 2^2 x 3^2 = 36.

HCF = product of least powers ; LCM = product of greatest powers

  • Every composite number = unique product of primes
  • 12 = 2^2 x 3, 18 = 2 x 3^2
  • HCF = smallest powers of common primes = 6
  • LCM = greatest powers of all primes = 36

Why learn this

It is used to find the HCF and LCM by prime factorisation.

💡 Memory trick

Break a number into primes - the factorisation is unique (order aside).

MathematicsReal Numbershard

How is sqrt(2) proved to be irrational (outline)?

Reveal answer ↓

What it is

A number that cannot be written as p/q (with q not zero) is irrational, and can be proved so by contradiction.

Answer

We prove sqrt(2) is irrational by contradiction. Assume that sqrt(2) is rational, so sqrt(2) = p/q where p and q are co-prime integers (no common factor) and q is not zero. Squaring gives 2 = p^2/q^2, so p^2 = 2q^2, which means p^2 is even, and hence p is even. Let p = 2m; then 2q^2 = 4m^2, so q^2 = 2m^2, meaning q^2 is even and q is even too. But then p and q have a common factor 2, contradicting our assumption that they are co-prime. Hence our assumption is wrong, and sqrt(2) is irrational.

Irrational: cannot be written as p/q

  • Proof by contradiction
  • Assume sqrt(2) = p/q in lowest terms
  • Show both p and q are even -> contradiction
  • So sqrt(2) is irrational

Why learn this

It shows that numbers like sqrt(2) are not fractions, deepening the number system.

💡 Memory trick

To prove sqrt(2) irrational: assume it is p/q in lowest terms, then reach a contradiction.

MathematicsPolynomialsmedium

Find the sum and product of the zeroes of the polynomial x^2 - 5x + 6.

Reveal answer ↓

What it is

For a quadratic ax^2 + bx + c, the sum of zeroes is -b/a and the product is c/a.

Answer

For a quadratic polynomial ax^2 + bx + c, the sum of the zeroes is -b/a and the product of the zeroes is c/a. Here a = 1, b = -5, c = 6. Sum of zeroes = -b/a = -(-5)/1 = 5. Product of zeroes = c/a = 6/1 = 6. (Indeed the zeroes are 2 and 3, whose sum is 5 and product is 6.)

Sum = -b/a ; Product = c/a

  • Sum of zeroes = -b/a = 5
  • Product of zeroes = c/a = 6
  • a = 1, b = -5, c = 6
  • Zeroes are 2 and 3

Why learn this

It lets us check zeroes or form a quadratic from its zeroes without solving.

💡 Memory trick

Sum of zeroes = -b/a ; product of zeroes = c/a.

MathematicsPair of Linear Equations in Two Variablesmedium

Solve by substitution: x + y = 10 and x - y = 4.

Reveal answer ↓

What it is

A pair of linear equations can be solved by expressing one variable in terms of the other and substituting.

Answer

From the first equation, x = 10 - y. Substitute this into the second equation: (10 - y) - y = 4, so 10 - 2y = 4, which gives 2y = 6 and y = 3. Then x = 10 - y = 10 - 3 = 7. So the solution is x = 7 and y = 3. Check: 7 + 3 = 10 and 7 - 3 = 4, both correct.

Substitute one variable to solve the pair

  • Express x = 10 - y
  • Substitute: 10 - 2y = 4
  • y = 3, then x = 7
  • Solution: x = 7, y = 3

Why learn this

It is a reliable algebraic method to find a unique solution.

💡 Memory trick

Make one variable the subject, substitute into the other equation, then solve.

MathematicsPair of Linear Equations in Two Variableshard

State the conditions for a pair of linear equations to have a unique solution, no solution and infinitely many solutions.

Reveal answer ↓

What it is

The ratios of coefficients decide whether a pair of linear equations has one solution, no solution or infinitely many.

Answer

For a pair of linear equations a1x + b1y + c1 = 0 and a2x + b2y + c2 = 0: if a1/a2 is not equal to b1/b2, the lines intersect at one point and there is a unique solution (consistent). If a1/a2 = b1/b2 = c1/c2, the lines are coincident and there are infinitely many solutions (consistent and dependent). If a1/a2 = b1/b2 but not equal to c1/c2, the lines are parallel and there is no solution (inconsistent).

Compare a1/a2, b1/b2, c1/c2

  • a1/a2 not equal b1/b2: unique solution (intersecting lines)
  • a1/a2 = b1/b2 = c1/c2: infinitely many (coincident)
  • a1/a2 = b1/b2 not equal c1/c2: no solution (parallel)
  • Ratios of coefficients decide the type

Why learn this

It tells us in advance the kind of solution and how the lines are related.

💡 Memory trick

a1/a2 not equal b1/b2 -> one solution; all three equal -> infinite; first two equal but not third -> none.

MathematicsQuadratic Equationsmedium

Solve the quadratic equation x^2 - 5x + 6 = 0 by factorisation.

Reveal answer ↓

What it is

A quadratic equation can be solved by splitting the middle term and factorising into two brackets.

Answer

To factorise x^2 - 5x + 6, split the middle term -5x into two terms whose product is 1 x 6 = 6 and whose sum is -5; these are -2 and -3. So x^2 - 2x - 3x + 6 = 0, giving x(x - 2) - 3(x - 2) = 0, that is (x - 2)(x - 3) = 0. Setting each factor to zero, x = 2 or x = 3. So the roots are 2 and 3.

Split middle term to factorise

  • Split -5x into -2x and -3x (product 6, sum -5)
  • x(x-2) - 3(x-2) = 0
  • (x - 2)(x - 3) = 0
  • Roots: x = 2 and x = 3

Why learn this

It is the quickest method when the quadratic factorises neatly.

💡 Memory trick

Split the middle term into two numbers that add to b and multiply to a x c.

MathematicsQuadratic Equationsmedium

Solve x^2 - 4x + 1 = 0 using the quadratic formula.

Reveal answer ↓

What it is

Any quadratic ax^2 + bx + c = 0 can be solved using the quadratic formula.

Answer

Here a = 1, b = -4, c = 1. The quadratic formula is x = (-b +/- sqrt(b^2 - 4ac)) / (2a). The discriminant b^2 - 4ac = (-4)^2 - 4(1)(1) = 16 - 4 = 12. So x = (4 +/- sqrt(12)) / 2 = (4 +/- 2sqrt(3)) / 2 = 2 +/- sqrt(3). So the roots are 2 + sqrt(3) and 2 - sqrt(3).

x = (-b +/- sqrt(b^2 - 4ac)) / (2a)

  • x = (-b +/- sqrt(b^2 - 4ac)) / (2a)
  • a=1, b=-4, c=1; discriminant = 12
  • x = (4 +/- 2sqrt(3))/2
  • Roots: 2 + sqrt(3) and 2 - sqrt(3)

Why learn this

It works for every quadratic, even those that do not factorise easily.

💡 Memory trick

x = (-b +/- sqrt(b^2 - 4ac)) / (2a).

MathematicsQuadratic Equationsmedium

What is the discriminant? Find the nature of the roots of x^2 + 4x + 4 = 0.

Reveal answer ↓

What it is

The discriminant D = b^2 - 4ac tells the nature of the roots of a quadratic equation.

Answer

The discriminant of a quadratic equation ax^2 + bx + c = 0 is D = b^2 - 4ac. If D > 0 the roots are real and distinct; if D = 0 the roots are real and equal; and if D < 0 the equation has no real roots. For x^2 + 4x + 4 = 0, a = 1, b = 4, c = 4, so D = 4^2 - 4(1)(4) = 16 - 16 = 0. Since D = 0, the roots are real and equal (both equal to -2).

D = b^2 - 4ac

  • Discriminant D = b^2 - 4ac
  • D > 0: real and distinct roots
  • D = 0: real and equal roots
  • For x^2+4x+4: D = 0, roots equal (-2)

Why learn this

It reveals whether the roots are real and distinct, equal or not real without solving.

💡 Memory trick

D > 0 real and distinct; D = 0 real and equal; D < 0 no real roots.

MathematicsArithmetic Progressionseasy

Find the 15th term of the AP: 3, 7, 11, 15, ...

Reveal answer ↓

What it is

The nth term of an arithmetic progression is a + (n - 1)d, where a is the first term and d the common difference.

Answer

In this AP, the first term a = 3 and the common difference d = 7 - 3 = 4. The nth term is given by an = a + (n - 1)d. For the 15th term, a15 = 3 + (15 - 1) x 4 = 3 + 14 x 4 = 3 + 56 = 59. So the 15th term is 59.

an = a + (n - 1)d

  • an = a + (n - 1)d
  • a = 3, d = 4
  • a15 = 3 + 14 x 4
  • 15th term = 59

Why learn this

It lets us find any term of a sequence without listing all the terms.

💡 Memory trick

an = a + (n - 1)d. Find d by subtracting any term from the next.

MathematicsArithmetic Progressionsmedium

Find the sum of the first 20 terms of the AP: 2, 5, 8, 11, ...

Reveal answer ↓

What it is

The sum of the first n terms of an AP is (n/2)[2a + (n - 1)d].

Answer

Here a = 2 and d = 5 - 2 = 3, and n = 20. The sum is Sn = (n/2)[2a + (n - 1)d] = (20/2)[2 x 2 + (20 - 1) x 3] = 10[4 + 57] = 10 x 61 = 610. So the sum of the first 20 terms is 610.

Sn = (n/2)[2a + (n - 1)d]

  • Sn = (n/2)[2a + (n - 1)d]
  • a = 2, d = 3, n = 20
  • = 10[4 + 57] = 10 x 61
  • Sum = 610

Why learn this

It quickly adds a long list of evenly spaced numbers.

💡 Memory trick

Sn = (n/2)[2a + (n-1)d], or (n/2)(first term + last term).

MathematicsTrianglesmedium

State the criteria for the similarity of two triangles.

Reveal answer ↓

What it is

Two triangles are similar if their corresponding angles are equal and corresponding sides are proportional.

Answer

Two triangles are similar if they have the same shape, that is, their corresponding angles are equal and their corresponding sides are in the same ratio. The criteria for similarity are: AA (or AAA), when two angles of one triangle equal two angles of the other; SSS, when the three pairs of corresponding sides are in the same ratio; and SAS, when one angle equals the corresponding angle and the two sides including these angles are in the same ratio. Similar triangles are written with the symbol for similarity.

AA, SSS, SAS similarity criteria

  • Corresponding angles equal
  • Corresponding sides proportional
  • Criteria: AA, SSS, SAS
  • Similar = same shape, may differ in size

Why learn this

Similarity is used to find unknown lengths and to prove geometric results.

💡 Memory trick

Similarity rules: AA, SSS (proportional), SAS. Similar triangles have the same shape, not size.

MathematicsTrianglesmedium

State the basic proportionality theorem (Thales theorem).

Reveal answer ↓

What it is

A line drawn parallel to one side of a triangle divides the other two sides in the same ratio.

Answer

The basic proportionality theorem, also called Thales theorem, states that if a line is drawn parallel to one side of a triangle to intersect the other two sides at distinct points, then it divides those two sides in the same ratio. For a triangle ABC with a line DE parallel to BC cutting AB at D and AC at E, this means AD/DB = AE/EC. The converse is also true: if a line divides two sides of a triangle in the same ratio, then it is parallel to the third side.

AD/DB = AE/EC (DE parallel to BC)

  • A line parallel to one side divides the other two proportionally
  • AD/DB = AE/EC
  • Converse is also true
  • Used to prove similarity

Why learn this

It is used to prove similarity and to find lengths of divided sides.

💡 Memory trick

Parallel line inside a triangle splits the two sides proportionally: AD/DB = AE/EC.

MathematicsTrianglesmedium

The two shorter sides of a right triangle are 6 cm and 8 cm. Find the hypotenuse.

Reveal answer ↓

What it is

In a right-angled triangle, the square of the hypotenuse equals the sum of the squares of the other two sides.

Answer

By the Pythagoras theorem, in a right-angled triangle, hypotenuse^2 = base^2 + height^2. Here hypotenuse^2 = 6^2 + 8^2 = 36 + 64 = 100, so the hypotenuse = sqrt(100) = 10 cm. Therefore the hypotenuse is 10 centimetres.

hypotenuse^2 = base^2 + height^2

  • hypotenuse^2 = base^2 + height^2
  • = 6^2 + 8^2 = 36 + 64 = 100
  • hypotenuse = sqrt(100)
  • Hypotenuse = 10 cm

Why learn this

It is used to find distances and lengths in countless real problems.

💡 Memory trick

hypotenuse^2 = base^2 + height^2 (only for a right angle).

MathematicsCoordinate Geometrymedium

Find the distance between the points (1, 2) and (4, 6).

Reveal answer ↓

What it is

The distance between two points is found from the differences of their coordinates using the Pythagoras theorem.

Answer

The distance between two points (x1, y1) and (x2, y2) is given by sqrt((x2 - x1)^2 + (y2 - y1)^2). Here = sqrt((4 - 1)^2 + (6 - 2)^2) = sqrt(3^2 + 4^2) = sqrt(9 + 16) = sqrt(25) = 5. So the distance between the two points is 5 units.

Distance = sqrt((x2 - x1)^2 + (y2 - y1)^2)

  • Distance = sqrt((x2-x1)^2 + (y2-y1)^2)
  • = sqrt(3^2 + 4^2)
  • = sqrt(25)
  • Distance = 5 units

Why learn this

It measures the straight-line distance between any two points on a graph.

💡 Memory trick

Distance = sqrt((x2 - x1)^2 + (y2 - y1)^2).

MathematicsCoordinate Geometryhard

Find the coordinates of the point dividing the line joining (2, 3) and (6, 7) in the ratio 1:1 (the midpoint).

Reveal answer ↓

What it is

The section formula gives the coordinates of a point dividing a line segment in a given ratio.

Answer

The section formula for a point dividing the join of (x1, y1) and (x2, y2) in the ratio m:n is ((m x2 + n x1)/(m + n), (m y2 + n y1)/(m + n)). For the ratio 1:1 this becomes the midpoint formula ((x1 + x2)/2, (y1 + y2)/2). Here midpoint = ((2 + 6)/2, (3 + 7)/2) = (8/2, 10/2) = (4, 5). So the midpoint is (4, 5).

Midpoint = ((x1 + x2)/2, (y1 + y2)/2)

  • Section formula for ratio m:n
  • Midpoint = ((x1+x2)/2, (y1+y2)/2)
  • = ((2+6)/2, (3+7)/2)
  • Midpoint = (4, 5)

Why learn this

It is used to find dividing points and midpoints of segments.

💡 Memory trick

Point = ((m x2 + n x1)/(m+n), (m y2 + n y1)/(m+n)) for ratio m:n.

MathematicsIntroduction to Trigonometrymedium

Define sin, cos and tan of an acute angle in a right-angled triangle.

Reveal answer ↓

What it is

In a right triangle, the trigonometric ratios sine, cosine and tangent relate an angle to pairs of its sides.

Answer

In a right-angled triangle, for an acute angle A: the sine of A is the ratio of the side opposite to A to the hypotenuse (sin A = opposite/hypotenuse); the cosine of A is the ratio of the side adjacent to A to the hypotenuse (cos A = adjacent/hypotenuse); and the tangent of A is the ratio of the side opposite to A to the side adjacent to A (tan A = opposite/adjacent). Also, tan A = sin A / cos A. The reciprocals are cosec A, sec A and cot A.

sin = opp/hyp ; cos = adj/hyp ; tan = opp/adj

  • sin A = opposite / hypotenuse
  • cos A = adjacent / hypotenuse
  • tan A = opposite / adjacent
  • tan A = sin A / cos A

Why learn this

They connect angles to side lengths and are the basis of all trigonometry.

💡 Memory trick

SOH-CAH-TOA: sin = Opp/Hyp, cos = Adj/Hyp, tan = Opp/Adj.

MathematicsIntroduction to Trigonometrymedium

Evaluate sin 30 + cos 60 and tan 45.

Reveal answer ↓

What it is

The trig ratios of 0, 30, 45, 60 and 90 degrees have fixed standard values.

Answer

Using the standard values: sin 30 = 1/2 and cos 60 = 1/2, so sin 30 + cos 60 = 1/2 + 1/2 = 1. Also tan 45 = 1. So sin 30 + cos 60 = 1 and tan 45 = 1.

sin 30 = 1/2 ; cos 60 = 1/2 ; tan 45 = 1

  • sin 30 = 1/2, cos 60 = 1/2
  • sin 30 + cos 60 = 1
  • tan 45 = 1
  • Learn the standard-angle table

Why learn this

They are used constantly in solving triangles and applications.

💡 Memory trick

sin: 0, 1/2, 1/sqrt2, sqrt3/2, 1 for 0, 30, 45, 60, 90. cos is the reverse.

MathematicsIntroduction to Trigonometrymedium

State the three trigonometric identities. If sin A = 3/5, find cos A.

Reveal answer ↓

What it is

The fundamental trigonometric identity is sin^2 A + cos^2 A = 1.

Answer

The three fundamental trigonometric identities are: sin^2 A + cos^2 A = 1; 1 + tan^2 A = sec^2 A; and 1 + cot^2 A = cosec^2 A. Given sin A = 3/5, use sin^2 A + cos^2 A = 1: cos^2 A = 1 - sin^2 A = 1 - (3/5)^2 = 1 - 9/25 = 16/25. So cos A = sqrt(16/25) = 4/5 (taking the positive value for an acute angle).

sin^2 A + cos^2 A = 1

  • sin^2 A + cos^2 A = 1
  • 1 + tan^2 A = sec^2 A
  • 1 + cot^2 A = cosec^2 A
  • cos A = 4/5 when sin A = 3/5

Why learn this

It lets us find one ratio from another and simplify expressions.

💡 Memory trick

sin^2 + cos^2 = 1 always. The other two: 1 + tan^2 = sec^2 ; 1 + cot^2 = cosec^2.

MathematicsSome Applications of Trigonometrymedium

The angle of elevation of the top of a tower from a point 30 m away is 45 degrees. Find the height of the tower.

Reveal answer ↓

What it is

Trigonometry finds unknown heights and distances using an angle of elevation or depression.

Answer

Let the height of the tower be h. The point is 30 m from the base, and the angle of elevation of the top is 45 degrees. Using tan(angle) = opposite/adjacent = height/distance: tan 45 = h/30. Since tan 45 = 1, we get 1 = h/30, so h = 30 m. Therefore the height of the tower is 30 metres.

tan(angle of elevation) = height / distance

  • tan(angle) = height / distance
  • tan 45 = h/30
  • tan 45 = 1
  • Height h = 30 m

Why learn this

It measures tall or far objects without physically reaching them.

💡 Memory trick

Angle of elevation looks up; use tan(angle) = height / distance.

MathematicsCirclesmedium

What is a tangent to a circle? State the relationship between a tangent and the radius at the point of contact.

Reveal answer ↓

What it is

A tangent to a circle touches it at exactly one point and is perpendicular to the radius at that point.

Answer

A tangent to a circle is a straight line that touches the circle at exactly one point, called the point of contact. A key theorem states that the tangent at any point of a circle is perpendicular to the radius drawn to the point of contact; that is, the radius and the tangent make a right angle (90 degrees) at the point of contact. A line that cuts the circle at two points is called a secant, not a tangent.

Radius is perpendicular to the tangent at the point of contact

  • Tangent touches the circle at one point
  • Point of contact
  • Tangent is perpendicular to the radius there
  • A secant cuts the circle at two points

Why learn this

It is the key property used in all tangent-related problems.

💡 Memory trick

Radius meets tangent at 90 degrees at the point of contact.

MathematicsCirclesmedium

How many tangents can be drawn from an external point to a circle, and what is special about them?

Reveal answer ↓

What it is

The lengths of the two tangents drawn from an external point to a circle are equal.

Answer

From a point lying outside a circle, exactly two tangents can be drawn to the circle. A key theorem states that the lengths of these two tangents drawn from an external point to a circle are equal. From a point on the circle, only one tangent can be drawn, and from a point inside the circle, no tangent can be drawn. These equal-tangent lengths are used in many geometry proofs and constructions.

Tangents from an external point are equal in length

  • Two tangents from an external point
  • The two tangent lengths are equal
  • One tangent from a point on the circle
  • No tangent from a point inside

Why learn this

It is used to find tangent lengths and to prove results about circles.

💡 Memory trick

From one outside point, the two tangents to a circle are always equal in length.

MathematicsAreas Related to Circlesmedium

Find the area of a sector of a circle of radius 7 cm with a central angle of 90 degrees. (Take pi = 22/7.)

Reveal answer ↓

What it is

The area of a sector of a circle is a fraction of the whole circle's area, proportional to its central angle.

Answer

The area of a sector = (central angle / 360) x pi r^2 = (90/360) x (22/7) x 7^2 = (1/4) x (22/7) x 49 = (1/4) x 22 x 7 = (1/4) x 154 = 38.5 cm^2. So the area of the sector is 38.5 square centimetres.

Area of sector = (angle/360) x pi r^2

  • Area of sector = (angle/360) x pi r^2
  • = (90/360) x (22/7) x 49
  • = (1/4) x 154
  • Area = 38.5 cm^2

Why learn this

It is used to find areas of pie slices, fan shapes and portions of circular fields.

💡 Memory trick

Area of sector = (angle/360) x pi r^2.

MathematicsStatisticsmedium

The class marks and frequencies of a data set are: (10, 2), (20, 3), (30, 5). Find the mean.

Reveal answer ↓

What it is

The mean of grouped data is found using the class marks and their frequencies.

Answer

For grouped data, the mean = sum of (frequency x class mark) / sum of frequencies. Compute the products: 2 x 10 = 20, 3 x 20 = 60, 5 x 30 = 150. Sum of products = 20 + 60 + 150 = 230. Sum of frequencies = 2 + 3 + 5 = 10. Mean = 230 / 10 = 23. So the mean of the data is 23.

Mean = sum(fi xi) / sum(fi)

  • Mean = sum(f x x) / sum(f)
  • Products: 20, 60, 150; sum = 230
  • Total frequency = 10
  • Mean = 230/10 = 23

Why learn this

It gives a single average value that represents grouped data.

💡 Memory trick

Mean = sum of (frequency x class mark) / sum of frequencies.

MathematicsProbabilityeasy

A die is rolled once. Find the probability of getting an even number.

Reveal answer ↓

What it is

Theoretical probability of an event is the number of favourable outcomes divided by the total number of equally likely outcomes.

Answer

When a die is rolled, the total number of equally likely outcomes is 6 (the numbers 1 to 6). The even numbers are 2, 4 and 6, so the number of favourable outcomes is 3. Therefore the probability of getting an even number = favourable outcomes / total outcomes = 3/6 = 1/2. So the probability is 1/2.

P(E) = number of favourable outcomes / total number of outcomes

  • P(E) = favourable / total outcomes
  • Total outcomes = 6
  • Even numbers: 2, 4, 6 (3 outcomes)
  • P(even) = 3/6 = 1/2

Why learn this

It predicts the chance of an event in games and experiments.

💡 Memory trick

P(E) = favourable outcomes / total outcomes, always between 0 and 1.

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