For Class 8, 9 & 10
Master the basics - and everything after gets easier
Concept-first questions with clear model answers in Physics, Chemistry, Maths and Biology, all NCERT-aligned. Start early, build the habit, and walk into your boards, NEET and JEE already ahead.
Interactive lessons
learn by playingDrag, slide and build - watch each concept come alive, then reveal the answer.
200 interactive lessons
Ohm's law
Class 10 Physics
Slide V & R, watch the bulb glow
Open →pH scale
Class 10 Chemistry
Slide across acids and bases
Open →Atomic number and mass number
Class 9 Chemistry
Add protons & neutrons, build shells
Open →Laws of reflection
Class 8 Physics
Change the angle, watch it bounce
Open →Volume of a sphere
Class 9 Maths
Grow the radius, see the volume
Open →Area of a trapezium
Class 8 Maths
Drag the sides, read the area
Open →Power of a lens
Class 10 Physics
Move the object, trace the rays
Open →Food chain and energy flow
Class 10 Biology
Follow the energy as it flows
Open →Speed
Class 8 Physics
Slide distance & time, watch the speed
Open →Density
Class 9 Physics
Pack mass into volume, float or sink
Open →Work done
Class 9 Physics
Push harder or farther, watch work grow
Open →Kinetic energy
Class 9 Physics
Speed it up - energy grows with the square
Open →Power of a lens
Class 10 Physics
Shorten the focal length, boost the power
Open →Mole concept
Class 9 Chemistry
Weigh out grams, count the moles
Open →Avogadro's number
Class 9 Chemistry
Add moles, count the particles
Open →Microscope magnification
Class 8 Biology
Grow the image, read the magnification
Open →Population density
Class 10 Biology
Add individuals, shrink the land, see crowding
Open →Simple interest
Class 8 Maths
Slide money, rate & time, watch interest
Open →Pythagoras theorem
Class 9 Maths
Stretch the two sides, get the hypotenuse
Open →Probability of an event
Class 10 Maths
Change the outcomes, watch the odds
Open →Newton's second law
Class 9 Physics
Push a mass, pick an acceleration
Open →Momentum
Class 9 Physics
Slide mass & velocity, build momentum
Open →Pressure
Class 8 Physics
Shrink the area, feel the pressure rise
Open →Weight
Class 9 Physics
Change the planet's gravity, watch your weight
Open →Refractive index
Class 10 Physics
Slow light in the medium, raise the index
Open →Resistors in series
Class 10 Physics
Add two resistors in a line
Open →Mass percentage of a solution
Class 9 Chemistry
Dissolve solute, read the strength
Open →Concentration of a solution
Class 9 Chemistry
Pack solute into less liquid
Open →Population change
Class 10 Biology
Balance births against deaths
Open →Compound microscope
Class 8 Biology
Combine eyepiece & objective lenses
Open →Area of a circle
Class 8 Maths
Grow the radius, watch the area square
Open →Volume of a cuboid
Class 8 Maths
Stretch length, breadth & height
Open →Electronic configuration and valency
Class 9 Chemistry
Slide the atomic number, build the atom
Open →Homologous series (alkanes)
Class 10 Chemistry
Add carbons, name the compound
Open →Mass number
Class 9 Chemistry
Add protons & neutrons, get the mass number
Open →Power
Class 9 Physics
More work in less time = more power
Open →Potential energy
Class 9 Physics
Lift a mass higher, store energy
Open →Wave speed
Class 9 Physics
Tune frequency & wavelength, set the speed
Open →Electric current
Class 10 Physics
Push charge per second, get the current
Open →Percentage
Class 8 Maths
Compare part to whole as a %
Open →Electron dot structure
Class 9 Chemistry
Draw valence electrons as dots
Open →Acceleration
Class 9 Physics
Speed up over time, find acceleration
Open →Distance, speed and time
Class 8 Physics
Set speed & time, cover the distance
Open →Frequency and time period
Class 9 Physics
Shorten the period, raise the frequency
Open →Heating effect of current
Class 10 Physics
Raise the current, watch heating soar
Open →Area of a triangle
Class 8 Maths
Set base & height, halve the rectangle
Open →Area of a rectangle
Class 8 Maths
Set length & breadth, fill the area
Open →Mean (average)
Class 9 Maths
Share the total equally across items
Open →Discount
Class 8 Maths
Slide price & % off, see the saving
Open →Heart rate
Class 10 Biology
Set heart rate & time, count the beats
Open →Resistors in parallel
Class 10 Physics
Wire two resistors side by side
Open →Electric charge
Class 10 Physics
Flow current over time, collect charge
Open →Electrical energy and units
Class 10 Physics
Run appliances, add up the units
Open →Kelvin temperature scale
Class 9 Chemistry
Slide Celsius, read the Kelvin
Open →Moles from number of particles
Class 9 Chemistry
Divide particles by Avogadro's number
Open →Ten percent law
Class 10 Biology
See 10% of energy reach the next level
Open →Area of a square
Class 8 Maths
Grow the side, square the area
Open →Volume of a cube
Class 8 Maths
Grow the edge, cube the volume
Open →Circumference of a circle
Class 8 Maths
Grow the radius, roll out the rim
Open →Surface area of a cube
Class 9 Maths
Grow the edge, cover six faces
Open →Potential difference
Class 10 Physics
Share work across charge, get volts
Open →Resistance from Ohm's law
Class 10 Physics
Divide voltage by current, get resistance
Open →Echo and SONAR
Class 9 Physics
Time the echo, find the distance
Open →Mass from moles
Class 9 Chemistry
Multiply moles by molar mass
Open →Breathing rate
Class 10 Biology
Set breathing rate & time
Open →Volume of a cylinder
Class 10 Maths
Set radius & height, fill the can
Open →Compound interest
Class 8 Maths
Compound money over years
Open →Profit and loss percentage
Class 8 Maths
Set cost & selling price, see profit %
Open →Perimeter of a rectangle
Class 8 Maths
Set length & breadth, walk the border
Open →Surface area of a sphere
Class 10 Maths
Grow the radius, wrap the ball
Open →Time period
Class 9 Physics
Raise the frequency, shrink the period
Open →Relative velocity
Class 9 Physics
Two objects approach - add their speeds
Open →Average velocity
Class 9 Physics
Average the start and end speeds
Open →Equations of motion (v = u + at)
Class 9 Physics
Accelerate from u for a time t
Open →Kelvin to Celsius
Class 9 Chemistry
Slide Kelvin, read the Celsius
Open →Population growth rate
Class 10 Biology
Balance births vs deaths per population
Open →Perimeter of a square
Class 8 Maths
Grow the side, walk four edges
Open →Perimeter of a triangle
Class 8 Maths
Add the three sides
Open →Area of a parallelogram
Class 8 Maths
Set base & height, slide the shape
Open →Area of a rhombus
Class 8 Maths
Set the two diagonals
Open →Equations of motion (distance)
Class 9 Physics
Start, accelerate, cover ground
Open →Joule's law of heating
Class 10 Physics
Raise current, resistance or time
Open →Electric power (P = VI)
Class 10 Physics
Multiply voltage by current
Open →Average atomic mass of isotopes
Class 9 Chemistry
Mix two isotopes by abundance
Open →Seed germination percentage
Class 9 Biology
Count sprouted seeds out of the total
Open →Volume of a cone
Class 9 Maths
Set radius & height, fill the cone
Open →Surface area of a cylinder
Class 9 Maths
Wrap the side and both ends
Open →Surface area of a cuboid
Class 9 Maths
Cover all six rectangular faces
Open →nth term of an AP
Class 10 Maths
Step from the first term by d
Open →Sum of an AP
Class 10 Maths
Add up the first n terms
Open →Focal length of a mirror
Class 10 Physics
Halve the radius to find the focus
Open →Speed of light in a medium
Class 10 Physics
Raise the index, slow the light
Open →Percentage purity
Class 9 Chemistry
Weigh the pure part of a sample
Open →Slope of a line
Class 10 Maths
Rise over run gives the steepness
Open →Percentage change
Class 8 Maths
Compare a new value to the old
Open →Volume of a hemisphere
Class 9 Maths
Grow the radius of half a ball
Open →Area of a sector
Class 10 Maths
Cut a slice of angle from a circle
Open →Length of an arc
Class 10 Maths
Measure the curved edge of a slice
Open →Slant height of a cone
Class 9 Maths
Combine radius & height for the slant
Open →Unit conversion (km/h to m/s)
Class 9 Physics
Convert km/h into m/s
Open →Equations of motion (v^2 = u^2 + 2as)
Class 9 Physics
Accelerate over a distance, find v
Open →Impulse
Class 9 Physics
Hit harder or longer, change momentum
Open →Wavelength
Class 9 Physics
Speed over frequency gives wavelength
Open →Oscillations
Class 9 Physics
Vibrate at a frequency for a time
Open →Cost of electricity
Class 10 Physics
Units times rate gives the bill
Open →Number of neutrons
Class 9 Chemistry
Take protons away from the mass number
Open →Curved surface area of a cone
Class 9 Maths
Wrap the slanted side of a cone
Open →Total surface area of a cone
Class 9 Maths
Add the base circle to the cone's side
Open →Curved surface area of a hemisphere
Class 9 Maths
Cover the dome of a hemisphere
Open →Diagonal of a square
Class 9 Maths
Cross a square corner to corner
Open →Unit conversion (m/s to km/h)
Class 9 Physics
Convert m/s into km/h
Open →Distance from velocities
Class 9 Physics
From two speeds, find the distance
Open →Diagonal of a rectangle
Class 9 Maths
Cross a rectangle corner to corner
Open →Diagonal of a cuboid
Class 9 Maths
The longest rod that fits in a box
Open →Area by Heron's formula
Class 9 Maths
Area from just the three sides
Open →Interior angle sum of a polygon
Class 8 Maths
Add up a polygon's inside angles
Open →Exterior angle of a regular polygon
Class 8 Maths
Share 360 among a polygon's corners
Open →Number of diagonals of a polygon
Class 8 Maths
Count the diagonals of a polygon
Open →Discriminant
Class 10 Maths
Test how many roots a quadratic has
Open →Sum of roots
Class 10 Maths
Sum of a quadratic's roots
Open →Punnett square (monohybrid cross)
Class 10 Biology
Cross two parents, predict the offspring
Open →Balancing chemical equations
Class 10 Chemistry
Slide coefficients until atoms balance
Open →Writing chemical formulae (valency)
Class 9 Chemistry
Criss-cross valencies into a formula
Open →Current from power
Class 10 Physics
Divide power by voltage for current
Open →Power (P = V^2 / R)
Class 10 Physics
Voltage squared over resistance
Open →Sine ratio
Class 10 Maths
Opposite over hypotenuse
Open →Cosine ratio
Class 10 Maths
Adjacent over hypotenuse
Open →Tangent ratio
Class 10 Maths
Opposite over adjacent
Open →Area of an equilateral triangle
Class 9 Maths
Area of an equilateral triangle
Open →Curved surface area of a cylinder
Class 9 Maths
Wrap only the curved side
Open →Loss percentage
Class 8 Maths
Sell below cost, find the loss %
Open →Amount with simple interest
Class 8 Maths
Principal plus its simple interest
Open →Distance formula
Class 10 Maths
Straight distance between two points
Open →States of matter
Class 9 Chemistry
Heat particles solid → liquid → gas
Open →Parts of a plant cell
Class 8 Biology
Tap a cell part to see its job
Open →Diagonal of a cube
Class 9 Maths
Longest diagonal through a cube
Open →Total surface area of a hemisphere
Class 9 Maths
Dome plus its flat circle
Open →Sum of first n natural numbers
Class 10 Maths
Add 1 + 2 + ... + n instantly
Open →Range of data
Class 9 Maths
Spread from smallest to largest
Open →Class mark
Class 9 Maths
Midpoint of a class interval
Open →Selling price from profit percent
Class 8 Maths
Mark up cost by a profit %
Open →Perimeter of a sector
Class 10 Maths
Two radii plus the curved arc
Open →Circumference from diameter
Class 8 Maths
Circumference straight from diameter
Open →Power (P = F x v)
Class 9 Physics
Force times velocity gives power
Open →Percentage of a number
Class 8 Maths
Find a percentage of a number
Open →Series and parallel circuits
Class 10 Physics
Break a bulb in series vs parallel
Open →Symbols of elements
Class 9 Chemistry
Match each element to its symbol
Open →Free fall (velocity)
Class 9 Physics
Drop from a height, hit this speed
Open →Free fall (time)
Class 9 Physics
How long a drop takes
Open →Free fall (distance)
Class 9 Physics
Distance fallen in a given time
Open →Complement of an event
Class 10 Maths
Chance an event does NOT happen
Open →Product of roots
Class 10 Maths
Product of a quadratic's roots
Open →Exterior angle theorem
Class 9 Maths
Exterior angle = sum of remote interiors
Open →Complementary angles
Class 10 Maths
What adds to 90 degrees
Open →Supplementary angles
Class 9 Maths
What adds to 180 degrees
Open →Perimeter of a semicircle
Class 10 Maths
Curved half plus the diameter
Open →Area of a semicircle
Class 10 Maths
Half the area of a circle
Open →Turning effect (moments)
Class 9 Physics
Balance the see-saw with moments
Open →Reflex arc
Class 10 Biology
Step through a reflex, stimulus to action
Open →Buoyant force (upthrust)
Class 9 Physics
Displace liquid, feel the upthrust
Open →Relative density
Class 9 Physics
Compare a density to water's
Open →Power in lifting a load
Class 9 Physics
Lift a load, faster needs more power
Open →Cosecant ratio
Class 10 Maths
Hypotenuse over opposite
Open →Secant ratio
Class 10 Maths
Hypotenuse over adjacent
Open →Cotangent ratio
Class 10 Maths
Adjacent over opposite
Open →Height from angle of elevation
Class 10 Maths
Height from an angle of elevation
Open →Area of a quadrant
Class 10 Maths
A quarter of a circle's area
Open →Interior angle of a regular polygon
Class 8 Maths
One inside angle of a regular polygon
Open →Sum of first n odd numbers
Class 10 Maths
Add the first n odd numbers
Open →Sum of first n even numbers
Class 10 Maths
Add the first n even numbers
Open →Quadratic formula (a root)
Class 10 Maths
Larger root of a quadratic
Open →LCM from HCF
Class 10 Maths
LCM from the product and HCF
Open →Depreciation
Class 8 Maths
Value drops by a % each year
Open →Cost price from selling price
Class 8 Maths
Work back to the cost price
Open →Downstream speed
Class 8 Maths
Row with the current
Open →Upstream speed
Class 8 Maths
Row against the current
Open →Average speed for a round trip
Class 8 Maths
Average speed there and back
Open →Sales tax / GST
Class 8 Maths
Tax added on a price
Open →Area of a ring (annulus)
Class 10 Maths
Area of a ring between two circles
Open →Edge of a cube from volume
Class 9 Maths
Edge back from the volume
Open →Radius from area
Class 10 Maths
Radius back from a circle's area
Open →Side from area of a square
Class 8 Maths
Side back from a square's area
Open →Height of a triangle from area
Class 9 Maths
Height back from area and base
Open →Rate from simple interest
Class 8 Maths
Rate back from the interest
Open →Time from simple interest
Class 8 Maths
Time back from the interest
Open →Principal from simple interest
Class 8 Maths
Principal back from the interest
Open →Mean proportional
Class 10 Maths
Geometric mean of two numbers
Open →Fourth proportional
Class 8 Maths
Complete the proportion a : b = c : ?
Open →Marked price from selling price
Class 8 Maths
Marked price back from the sale price
Open →Chambers of the human heart
Class 10 Biology
Tap a heart chamber to see its job
Open →Equation of a line (y = mx + c)
Class 9 Maths
Read y off a straight line
Open →Average term of an AP
Class 10 Maths
Average of first and last term
Open →Number of terms in an AP
Class 10 Maths
How many terms in an AP
Open →Midpoint of two points
Class 10 Maths
x-coordinate of a midpoint
Open →Empirical mode
Class 10 Maths
Estimate the mode from mean & median
Open →Length of a shadow
Class 10 Maths
Shadow from height and sun angle
Open →Train crossing a pole
Class 8 Maths
Speed to cross a pole
Open →Time and work
Class 8 Maths
More workers, fewer days
Open →Dividing in a ratio
Class 8 Maths
Split a total in a ratio
Open →Unitary method
Class 8 Maths
Cost of a single item
Open →Your progress — Foundation - Class 8 to 10
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Showing 57 questions in Mathematics for Class 9. Tap a card to reveal the answer.
MathematicsNumber SystemsmediumRationalise the denominator of 1 / sqrt(2).
Reveal answer ↓
What it is
Rationalising clears a surd (root) from the denominator by multiplying top and bottom by it.
Answer
Multiply the numerator and denominator by sqrt(2): (1/sqrt(2)) x (sqrt(2)/sqrt(2)) = sqrt(2) / 2. So 1/sqrt(2) = sqrt(2)/2, which is about 0.707. Rationalising removes the irrational number (surd) from the denominator.
1/sqrt(a) = sqrt(a)/a
- •Multiply top and bottom by sqrt(2)
- •= sqrt(2)/2
- •Removes the surd from the denominator
Why learn this
It makes fractions easier to compute and compare - important in exams and in engineering maths.
💡 Memory trick
Multiply top and bottom by the same surd - the root moves upstairs.
MathematicsPolynomialsmediumUsing the remainder theorem, find the remainder when p(x) = x^3 + 3x^2 + 3x + 1 is divided by (x + 1).
Reveal answer ↓
What it is
The remainder theorem says the remainder of p(x) divided by (x - a) is simply p(a).
Answer
By the remainder theorem, the remainder when p(x) is divided by (x + 1) is p(-1). p(-1) = (-1)^3 + 3(-1)^2 + 3(-1) + 1 = -1 + 3 - 3 + 1 = 0. Since the remainder is 0, (x + 1) is a factor of p(x).
Remainder theorem: remainder = p(a) when dividing by (x - a)
- •Remainder = p(-1)
- •p(-1) = -1 + 3 - 3 + 1 = 0
- •Remainder 0 -> (x + 1) is a factor
Why learn this
It checks factors of big polynomials in one step - a shortcut used all through algebra.
💡 Memory trick
Dividing by (x + 1)? Just plug in x = -1. Set the bracket to zero, then substitute.
MathematicsLinear Equations in Two VariableseasyWhere does the line x + y = 5 meet the x-axis and the y-axis?
Reveal answer ↓
What it is
A straight line meets the axes at its intercepts - put y = 0 for the x-axis, x = 0 for the y-axis.
Answer
On the x-axis, y = 0, so x + 0 = 5 gives x = 5; the line meets the x-axis at (5, 0). On the y-axis, x = 0, so 0 + y = 5 gives y = 5; it meets the y-axis at (0, 5). These two intercept points are enough to draw the straight line.
Intercepts: set y = 0 for x-axis, x = 0 for y-axis
- •x-axis: put y = 0 -> (5, 0)
- •y-axis: put x = 0 -> (0, 5)
- •Two points define the straight line
Why learn this
Two intercepts are the fastest way to draw any line - used in graphs, economics and coding.
💡 Memory trick
Zero the other one: y = 0 gives the x-cut, x = 0 gives the y-cut.
MathematicsHeron's FormulamediumFind the area of a triangle whose sides are 3 cm, 4 cm and 5 cm using Heron's formula.
Reveal answer ↓
What it is
Heron's formula finds a triangle's area from just its three sides, using the semi-perimeter.
Answer
First find the semi-perimeter s = (3 + 4 + 5)/2 = 6 cm. Heron's formula gives Area = sqrt[s(s - a)(s - b)(s - c)] = sqrt[6(6 - 3)(6 - 4)(6 - 5)] = sqrt[6 x 3 x 2 x 1] = sqrt[36] = 6 square cm.
Area = sqrt[s(s-a)(s-b)(s-c)], s = (a+b+c)/2
- •s = (a + b + c)/2 = 6 cm
- •Area = sqrt[s(s-a)(s-b)(s-c)]
- •= sqrt[36] = 6 cm^2
Why learn this
It measures land, plots and any triangle where you cannot easily find the height.
💡 Memory trick
Half the perimeter is 's'; Area = sqrt of s times the three (s - side) gaps.
MathematicsSurface Areas and VolumesmediumFind the volume of a sphere of radius 7 cm. (Take pi = 22/7.)
Reveal answer ↓
What it is
A sphere's volume grows with the cube of its radius: V = (4/3) pi r^3.
V = 4/3 π r³ ≈ 1437.3 cm³
Answer
Volume of a sphere = (4/3) x pi x r^3 = (4/3) x (22/7) x 7^3 = (4/3) x (22/7) x 343 = (4 x 22 x 49)/3 = 4312/3, which is about 1437.3 cubic cm.
V(sphere) = (4/3) pi r^3
- •V = (4/3) pi r^3
- •= (4/3)(22/7)(343)
- •= 4312/3 = about 1437.3 cm^3
Why learn this
It measures balls, planets, bubbles and tanks - anywhere something is round.
💡 Memory trick
Four-thirds pi r-cubed: V = (4/3) pi r^3 - the roundest formula in maths.
MathematicsStatisticseasyFind the mean of the data: 10, 15, 20, 25, 30.
Reveal answer ↓
What it is
The mean (average) is the total of all values divided by how many values there are.
Answer
Mean = (sum of all observations) / (number of observations) = (10 + 15 + 20 + 25 + 30) / 5 = 100 / 5 = 20.
Mean = (sum of observations) / (number of observations)
- •Mean = sum of values / number of values
- •Sum = 100, count = 5
- •Mean = 20
Why learn this
It summarises data in one number - used in marks, cricket averages, economics and science.
💡 Memory trick
Add them all up, divide by how many. Mean = sum / count.
MathematicsTrianglesmediumThe two shorter sides of a right triangle are 3 and 4. Find the hypotenuse. Slide to explore.
Reveal answer ↓
What it is
In a right-angled triangle, the square on the hypotenuse equals the sum of the squares on the other two sides.
Answer
By the Pythagoras theorem, c^2 = a^2 + b^2 = 3^2 + 4^2 = 9 + 16 = 25, so c = sqrt(25) = 5. The hypotenuse is always the longest side and lies opposite the right angle.
c = sqrt(a^2 + b^2)
- •c^2 = a^2 + b^2
- •c is the hypotenuse (longest side)
- •3-4-5 is the classic example
Why learn this
It measures distances we cannot walk in a straight line - used in construction, navigation and graphics.
💡 Memory trick
c^2 = a^2 + b^2. The 3-4-5 triangle is the classic check.
MathematicsStatisticseasyFive values add up to 250. Find their mean. Slide the values to explore.
Reveal answer ↓
What it is
The mean of a set of values is their sum divided by how many values there are.
Answer
Mean = sum of values / number of values = 250 / 5 = 50. The mean is the value each item would have if the total were shared out equally among them.
mean = sum of values / number of values
- •Mean = sum / number of items
- •Also called the average
- •Shares the total equally
Why learn this
It's the everyday 'average' used for marks, scores and data.
💡 Memory trick
Mean = sum / count. Share the total equally.
MathematicsSurface Areas and VolumeseasyFind the surface area of a cube of side 4 units. Slide the side to explore.
Reveal answer ↓
What it is
The surface area of a cube is six times the area of one square face.
Answer
Surface area = 6 x side^2 = 6 x 4^2 = 6 x 16 = 96 square units. A cube has six identical square faces, so we find the area of one face and multiply by six.
S = 6 x side^2
- •Surface area = 6 x side^2
- •A cube has 6 equal faces
- •Unit: square units
Why learn this
It tells how much material wraps or paints a cubic box.
💡 Memory trick
Surface area = 6 x side^2 - six equal faces.
MathematicsSurface Areas and VolumesmediumFind the volume of a cone of radius 3 and height 7 units (pi = 3.14159). Slide to explore.
Reveal answer ↓
What it is
The volume of a cone is one third of pi times the square of the radius times the height.
Answer
Volume = 1/3 x pi x r^2 x h = 1/3 x 3.14159 x 3^2 x 7 = 1/3 x 3.14159 x 9 x 7 = 65.97 cubic units. A cone holds exactly one third of the cylinder with the same base and height.
V = (1/3) x pi x r^2 x h
- •Volume = 1/3 x pi x r^2 x h
- •One third of the matching cylinder
- •Unit: cubic units
Why learn this
It measures the space in cones, funnels and ice-cream cones.
💡 Memory trick
Volume = 1/3 x pi x r^2 x h - a third of the cylinder.
MathematicsSurface Areas and VolumesmediumFind the total surface area of a cylinder of radius 3 and height 7 units (pi = 3.14159). Slide to explore.
Reveal answer ↓
What it is
The total surface area of a cylinder is the curved side plus its two circular ends.
Answer
Total surface area = 2 pi r (r + h) = 2 x 3.14159 x 3 x (3 + 7) = 2 x 3.14159 x 3 x 10 = 188.5 square units. This is the curved surface 2 pi r h plus the two circular ends 2 pi r^2.
S = 2 pi r (r + h)
- •Total surface = 2 pi r (r + h)
- •Curved side (2 pi r h) + two ends (2 pi r^2)
- •Unit: square units
Why learn this
It's the metal needed to make a closed tin or tank.
💡 Memory trick
Total surface = 2 pi r (r + h).
MathematicsSurface Areas and VolumesmediumFind the surface area of a cuboid 3 x 4 x 5 units. Slide the dimensions to explore.
Reveal answer ↓
What it is
The surface area of a cuboid is twice the sum of the areas of its three different faces.
Answer
Surface area = 2(lb + bh + hl) = 2(3x4 + 4x5 + 5x3) = 2(12 + 20 + 15) = 2 x 47 = 94 square units. A cuboid has three pairs of identical faces, so we add the three distinct faces and double the total.
S = 2(lb + bh + hl)
- •Surface = 2(lb + bh + hl)
- •Three pairs of identical faces
- •Unit: square units
Why learn this
It's the card needed to make a closed rectangular box.
💡 Memory trick
Surface = 2(lb + bh + hl).
MathematicsSurface Areas and VolumesmediumFind the volume of a hemisphere of radius 6 units (pi = 3.14159). Slide to explore.
Reveal answer ↓
What it is
The volume of a hemisphere is two thirds of pi times the cube of the radius.
Answer
Volume = 2/3 x pi x r^3 = 2/3 x 3.14159 x 6^3 = 2/3 x 3.14159 x 216 = 452.39 cubic units. A hemisphere is half a sphere, so its volume is half of 4/3 x pi x r^3, which is 2/3 x pi x r^3.
V = (2/3) x pi x r^3
- •Volume = 2/3 x pi x r^3
- •Half of a full sphere's volume
- •Unit: cubic units
Why learn this
It sizes domes, bowls and half-spherical tanks.
💡 Memory trick
Volume = 2/3 x pi x r^3 - half a sphere.
MathematicsSurface Areas and VolumesmediumA cone has radius 3 and height 4 units. Find its slant height. Slide to explore.
Reveal answer ↓
What it is
The slant height of a cone is found from its radius and vertical height using the Pythagoras theorem.
Answer
Slant height l = sqrt(r^2 + h^2) = sqrt(3^2 + 4^2) = sqrt(9 + 16) = sqrt(25) = 5 units. The radius, the vertical height and the slant height form a right triangle, so Pythagoras gives the slant.
l = sqrt(r^2 + h^2)
- •l = sqrt(r^2 + h^2)
- •From the Pythagoras theorem
- •Used for the curved surface area
Why learn this
It's needed to work out the curved surface area of a cone.
💡 Memory trick
l = sqrt(r^2 + h^2) - the hypotenuse of r and h.
MathematicsSurface Areas and VolumesmediumFind the curved surface area of a cone with radius 3 and slant height 5 units (pi = 3.14159). Slide to explore.
Reveal answer ↓
What it is
The curved surface area of a cone is pi times the radius times the slant height.
Answer
Curved surface area = pi x r x l = 3.14159 x 3 x 5 = 47.12 square units. Note that l is the slant height along the sloping side, not the vertical height of the cone.
CSA = pi x r x l
- •Curved area = pi x r x l
- •l is the slant height
- •Unit: square units
Why learn this
It's the paper needed to make the cone's sloping side, like an ice-cream wrapper.
💡 Memory trick
Curved area = pi x r x l (l is the slant height).
MathematicsSurface Areas and VolumesmediumFind the total surface area of a cone with radius 3 and slant height 5 units (pi = 3.14159). Slide to explore.
Reveal answer ↓
What it is
The total surface area of a cone is its curved surface plus its circular base.
Answer
Total surface area = pi x r x (l + r) = 3.14159 x 3 x (5 + 3) = 3.14159 x 3 x 8 = 75.40 square units. This is the curved surface (pi x r x l) plus the base circle (pi x r^2).
TSA = pi x r x (l + r)
- •Total area = pi x r x (l + r)
- •Curved surface + base circle
- •Unit: square units
Why learn this
It's the material to make a closed cone, like a party hat with a base.
💡 Memory trick
Total area = pi x r x (l + r).
MathematicsSurface Areas and VolumeseasyFind the curved surface area of a hemisphere of radius 6 units (pi = 3.14159). Slide to explore.
Reveal answer ↓
What it is
The curved surface area of a hemisphere is two pi times the square of the radius.
Answer
Curved surface area = 2 x pi x r^2 = 2 x 3.14159 x 6^2 = 2 x 3.14159 x 36 = 226.19 square units. A full sphere has surface 4 x pi x r^2, so the curved part of a hemisphere is exactly half of that.
CSA = 2 x pi x r^2
- •Curved area = 2 x pi x r^2
- •Half a sphere's surface (4 pi r^2)
- •Unit: square units
Why learn this
It's the dome surface of bowls, domes and half-spheres.
💡 Memory trick
Curved area = 2 x pi x r^2 - half a sphere's surface.
MathematicsMensurationeasyFind the diagonal of a square of side 10 units. Slide the side to explore.
Reveal answer ↓
What it is
The diagonal of a square is its side length times the square root of two.
Answer
Diagonal = side x sqrt(2) = 10 x 1.414 = 14.14 units. This comes from the Pythagoras theorem on the two equal sides of the square: diagonal^2 = side^2 + side^2 = 2 x side^2.
diagonal = side x sqrt(2)
- •Diagonal = side x sqrt(2)
- •sqrt(2) is about 1.414
- •From Pythagoras on two equal sides
Why learn this
It's the straight-line distance across a square tile or field.
💡 Memory trick
Diagonal = side x sqrt(2), about side x 1.414.
MathematicsMensurationeasyFind the diagonal of a rectangle 3 by 4 units. Slide the sides to explore.
Reveal answer ↓
What it is
The diagonal of a rectangle is the square root of the sum of the squares of its length and breadth.
Answer
Diagonal = sqrt(l^2 + b^2) = sqrt(3^2 + 4^2) = sqrt(9 + 16) = sqrt(25) = 5 units. The length, breadth and diagonal form a right triangle, so the Pythagoras theorem gives the diagonal.
diagonal = sqrt(l^2 + b^2)
- •Diagonal = sqrt(l^2 + b^2)
- •From the Pythagoras theorem
- •3-4-5 is the classic case
Why learn this
It's the straight distance across a rectangular screen, room or field.
💡 Memory trick
Diagonal = sqrt(l^2 + b^2) - Pythagoras on the two sides.
MathematicsSurface Areas and VolumesmediumFind the longest diagonal of a cuboid 3 x 4 x 12 units. Slide the dimensions to explore.
Reveal answer ↓
What it is
The longest diagonal of a cuboid is the square root of the sum of the squares of its three dimensions.
Answer
Space diagonal = sqrt(l^2 + b^2 + h^2) = sqrt(3^2 + 4^2 + 12^2) = sqrt(9 + 16 + 144) = sqrt(169) = 13 units. It extends the Pythagoras theorem into three dimensions.
diagonal = sqrt(l^2 + b^2 + h^2)
- •Diagonal = sqrt(l^2 + b^2 + h^2)
- •Pythagoras in 3D
- •Longest rod that fits inside
Why learn this
It's the longest straight rod or stick that can fit inside a box.
💡 Memory trick
Diagonal = sqrt(l^2 + b^2 + h^2).
MathematicsHeron's FormulamediumFind the area of a triangle with sides 3, 4 and 5 units using Heron's formula. Slide to explore.
Reveal answer ↓
What it is
Heron's formula gives the area of a triangle from the lengths of its three sides.
Answer
First the semi-perimeter s = (a+b+c)/2 = (3+4+5)/2 = 6. Then area = sqrt(s(s-a)(s-b)(s-c)) = sqrt(6 x 3 x 2 x 1) = sqrt(36) = 6 square units. (This is a right triangle, so 1/2 x 3 x 4 = 6 agrees.)
area = sqrt(s(s-a)(s-b)(s-c))
- •s = (a + b + c) / 2
- •Area = sqrt(s(s-a)(s-b)(s-c))
- •Uses only the three sides
Why learn this
It works even when the height is not known, using only the sides.
💡 Memory trick
s = (a+b+c)/2, then area = sqrt(s(s-a)(s-b)(s-c)).
MathematicsHeron's FormulamediumFind the area of an equilateral triangle of side 6 units. Slide the side to explore.
Reveal answer ↓
What it is
The area of an equilateral triangle is root three over four times the square of its side.
Answer
Area = (sqrt(3) / 4) x side^2 = (1.732 / 4) x 6^2 = 0.433 x 36 = 15.59 square units. This is a special case of Heron's formula when all three sides are equal.
A = (sqrt(3) / 4) x side^2
- •Area = (sqrt(3) / 4) x side^2
- •About 0.433 x side^2
- •Special case of Heron's formula
Why learn this
It's a quick formula for the most symmetric triangle.
💡 Memory trick
Area = (sqrt(3) / 4) x side^2, about 0.433 x side^2.
MathematicsSurface Areas and VolumeseasyFind the curved surface area of a cylinder with radius 3 and height 7 units (pi = 3.14159). Slide to explore.
Reveal answer ↓
What it is
The curved surface area of a cylinder is two pi times the radius times the height.
Answer
Curved surface area = 2 x pi x r x h = 2 x 3.14159 x 3 x 7 = 131.95 square units. It is the rectangle you would get by unrolling the curved side, with width equal to the circumference and height equal to the cylinder's height.
CSA = 2 x pi x r x h
- •Curved area = 2 x pi x r x h
- •The unrolled side is a rectangle
- •Excludes the two circular ends
Why learn this
It's the label that wraps around a tin, without the top and bottom.
💡 Memory trick
Curved area = 2 x pi x r x h.
MathematicsSurface Areas and VolumesmediumFind the longest diagonal of a cube of side 5 units. Slide the side to explore.
Reveal answer ↓
What it is
The longest diagonal of a cube is its side length times the square root of three.
Answer
Space diagonal = side x sqrt(3) = 5 x 1.732 = 8.66 units. It comes from applying Pythagoras twice - once across a face, then through the solid - giving sqrt(side^2 + side^2 + side^2) = side x sqrt(3).
diagonal = side x sqrt(3)
- •Diagonal = side x sqrt(3)
- •About side x 1.732
- •Pythagoras in three dimensions
Why learn this
It's the longest straight rod that fits inside a cubical box.
💡 Memory trick
Diagonal = side x sqrt(3), about side x 1.732.
MathematicsSurface Areas and VolumesmediumFind the total surface area of a solid hemisphere of radius 6 units (pi = 3.14159). Slide to explore.
Reveal answer ↓
What it is
The total surface area of a solid hemisphere is three pi times the square of the radius.
Answer
Total surface area = 3 x pi x r^2 = 3 x 3.14159 x 6^2 = 3 x 3.14159 x 36 = 339.29 square units. It is the curved dome (2 pi r^2) plus the flat circular base (pi r^2), which together make 3 pi r^2.
TSA = 3 x pi x r^2
- •Total = 3 x pi x r^2
- •Curved 2 pi r^2 + base pi r^2
- •Unit: square units
Why learn this
It's the full surface of a solid dome, including its flat base.
💡 Memory trick
Total = 3 x pi x r^2 (curved 2 pi r^2 + base pi r^2).
MathematicsStatisticseasyA data set has a highest value of 80 and a lowest of 20. Find the range. Slide to explore.
Reveal answer ↓
What it is
The range of a set of data is the difference between its highest and lowest values.
Answer
Range = highest value - lowest value = 80 - 20 = 60. A larger range means the data is more spread out; a small range means the values are close together.
range = highest value - lowest value
- •Range = highest - lowest
- •Simplest measure of spread
- •Larger range -> more spread out
Why learn this
It's the quickest way to describe how spread out data is.
💡 Memory trick
Range = highest - lowest.
MathematicsStatisticseasyFind the class mark of the interval 10 to 20. Slide the limits to explore.
Reveal answer ↓
What it is
The class mark is the midpoint of a class interval, the average of its lower and upper limits.
Answer
Class mark = (lower limit + upper limit) / 2 = (10 + 20) / 2 = 15. It is the midpoint of the interval and stands in for every value in that class when we calculate a grouped mean.
class mark = (lower + upper) / 2
- •Class mark = (lower + upper) / 2
- •Midpoint of the interval
- •Used for grouped-data mean
Why learn this
It represents a whole interval when finding the mean of grouped data.
💡 Memory trick
Class mark = (lower + upper) / 2.
MathematicsTriangleseasyTwo interior angles of a triangle are 60 and 70 degrees. Find the exterior angle at the third vertex. Slide to explore.
Reveal answer ↓
What it is
An exterior angle of a triangle equals the sum of the two interior angles opposite to it.
Answer
Exterior angle = angle 1 + angle 2 = 60 + 70 = 130 degrees. This works because the exterior angle and the third interior angle sit on a straight line (180 degrees), and the three interior angles also add to 180 degrees.
exterior angle = interior angle 1 + interior angle 2
- •Exterior angle = sum of two remote interior angles
- •Equals 180 minus the adjacent interior angle
- •Follows from the angle sum of a triangle
Why learn this
It's a quick way to find an unknown angle without using the full 180 degree rule.
💡 Memory trick
Exterior angle = sum of the two remote interior angles.
MathematicsLines and AngleseasyWhat is the supplement of a 60 degree angle? Slide the angle to explore.
Reveal answer ↓
What it is
Two angles are supplementary when they add up to 180 degrees.
Answer
Supplement = 180 - angle = 180 - 60 = 120 degrees. Supplementary angles add to a straight angle (180 degrees), so the angles on one side of a straight line always sum to 180.
supplement = 180 - angle
- •Supplement = 180 - angle
- •The two add to 180 degrees
- •Angles on a straight line are supplementary
Why learn this
Angles on a straight line are supplementary, a fact used throughout geometry.
💡 Memory trick
Supplement = 180 - angle.
MathematicsSurface Areas and VolumesmediumA cube has a volume of 64 cubic units. Find its edge. Slide the volume to explore.
Reveal answer ↓
What it is
The edge of a cube is the cube root of its volume.
Answer
Edge = cube root of volume = cube root of 64 = 4 units, because 4 x 4 x 4 = 64. It simply reverses the volume formula V = side^3.
side = cube root of volume
- •Edge = cube root of volume
- •Reverses V = side^3
- •Volume 64 -> edge 4
Why learn this
It reverses the volume formula to find the side.
💡 Memory trick
Since V = side^3, side = cube root of V.
MathematicsMensurationeasyA triangle has an area of 40 square units and a base of 10. Find its height. Slide to explore.
Reveal answer ↓
What it is
The height of a triangle is twice its area divided by the base.
Answer
Height = 2 x area / base = 2 x 40 / 10 = 80 / 10 = 8 units. This is the area formula area = 1/2 x base x height rearranged to make the height the subject.
height = 2 x area / base
- •Height = 2 x area / base
- •Reverses area = 1/2 x base x height
- •Area 40, base 10 -> height 8
Why learn this
It reverses the area formula to find a missing height.
💡 Memory trick
From area = 1/2 x base x height, height = 2 x area / base.
MathematicsLinear Equations in Two VariablesmediumFor the line y = 2x + 1, find y when x = 3. Slide m, x and c to explore.
Reveal answer ↓
What it is
A straight line is described by y = mx + c, where m is the slope and c is the y-intercept.
Answer
y = m x + c = 2 x 3 + 1 = 6 + 1 = 7. The slope m tells how steeply y changes with x, and c is where the line crosses the y-axis (its value when x = 0).
y = m x + c
- •y = m x + c
- •m is the slope, c the y-intercept
- •c is the value of y when x = 0
Why learn this
It's the workhorse equation for graphs, rates and trends.
💡 Memory trick
y = mx + c: slope times x, plus the intercept.
MathematicsNumber SystemsmediumDifferentiate between rational and irrational numbers with an example each.
Reveal answer ↓
What it is
A rational number can be written as p/q with integers p and q (q not 0); an irrational number cannot.
Answer
A rational number is a number that can be expressed in the form p/q, where p and q are integers and q is not zero; its decimal expansion is either terminating or non-terminating but recurring, for example 3/4 = 0.75 or 1/3 = 0.333... An irrational number cannot be written as p/q, and its decimal expansion is non-terminating and non-recurring, for example sqrt(2) = 1.41421... or pi.
Rational number = p/q, q not equal to 0
- •Rational: p/q form, q not 0
- •Rational decimals terminate or recur
- •Irrational: cannot be written as p/q
- •Irrational decimals are non-terminating, non-recurring (sqrt 2, pi)
Why learn this
Together they make up the real numbers used on the number line.
💡 Memory trick
Rational = ratio p/q (terminating or repeating decimal). Irrational = non-terminating, non-repeating.
MathematicsNumber SystemsmediumRationalise the denominator of 1 / sqrt(3).
Reveal answer ↓
What it is
Rationalising removes a surd from the denominator by multiplying by a suitable factor.
Answer
To rationalise 1/sqrt(3), multiply both the numerator and the denominator by sqrt(3): (1 x sqrt(3)) / (sqrt(3) x sqrt(3)) = sqrt(3) / 3. So 1/sqrt(3) = sqrt(3)/3, which now has a rational denominator.
1/sqrt(a) = sqrt(a)/a
- •Multiply numerator and denominator by the surd
- •sqrt(3) x sqrt(3) = 3
- •1/sqrt(3) = sqrt(3)/3
- •Use the conjugate for a + sqrt(b) type denominators
Why learn this
It simplifies expressions and makes them easier to compute.
💡 Memory trick
Multiply top and bottom by the surd (or its conjugate) to clear the root below.
MathematicsNumber SystemsmediumSimplify 2^(1/2) x 2^(1/2) and (8)^(2/3).
Reveal answer ↓
What it is
The laws of exponents also apply to rational powers (roots) of positive real numbers.
Answer
Using a^m x a^n = a^(m+n): 2^(1/2) x 2^(1/2) = 2^(1/2 + 1/2) = 2^1 = 2. For (8)^(2/3), write 8 = 2^3, so (2^3)^(2/3) = 2^(3 x 2/3) = 2^2 = 4. So the answers are 2 and 4.
a^m x a^n = a^(m+n) ; (a^m)^n = a^(mn)
- •a^m x a^n = a^(m+n)
- •a^(1/n) = nth root of a
- •2^(1/2) x 2^(1/2) = 2
- •(8)^(2/3) = 4
Why learn this
They let us simplify expressions involving powers and roots.
💡 Memory trick
a^(1/n) means the nth root of a. Multiply powers -> add; divide -> subtract.
MathematicsPolynomialseasyDefine the degree of a polynomial. Name the polynomials of degree 1, 2 and 3.
Reveal answer ↓
What it is
The degree of a polynomial is the highest power of the variable; polynomials are named by their degree.
Answer
The degree of a polynomial is the highest power of the variable present in it. A polynomial of degree 1, such as 2x + 3, is called a linear polynomial; a polynomial of degree 2, such as x^2 + 5x + 6, is called a quadratic polynomial; and a polynomial of degree 3, such as x^3 - 2x + 1, is called a cubic polynomial. A constant like 7 has degree 0.
Degree = highest power of the variable
- •Degree = highest power of the variable
- •Degree 1: linear
- •Degree 2: quadratic
- •Degree 3: cubic
Why learn this
Knowing the type helps decide how to factorise and solve.
💡 Memory trick
Degree 1 = linear, 2 = quadratic, 3 = cubic.
MathematicsPolynomialsmediumFind the remainder when p(x) = x^3 + 3x^2 + 3x + 1 is divided by (x + 1).
Reveal answer ↓
What it is
When a polynomial p(x) is divided by (x - a), the remainder is p(a).
Answer
By the remainder theorem, the remainder when p(x) is divided by (x - a) is p(a). Here the divisor is (x + 1) = (x - (-1)), so a = -1. Substitute: p(-1) = (-1)^3 + 3(-1)^2 + 3(-1) + 1 = -1 + 3 - 3 + 1 = 0. So the remainder is 0, which means (x + 1) is a factor.
Remainder of p(x) / (x - a) = p(a)
- •Remainder theorem: remainder = p(a)
- •Divisor (x + 1) means a = -1
- •p(-1) = -1 + 3 - 3 + 1 = 0
- •Remainder 0 means (x + 1) is a factor
Why learn this
It finds the remainder without doing long division.
💡 Memory trick
Remainder on dividing by (x - a) is just p(a) - substitute a into the polynomial.
MathematicsPolynomialsmediumState the factor theorem. Is (x - 2) a factor of p(x) = x^2 - 5x + 6?
Reveal answer ↓
What it is
(x - a) is a factor of a polynomial p(x) if and only if p(a) = 0.
Answer
The factor theorem states that (x - a) is a factor of a polynomial p(x) if and only if p(a) = 0. To test (x - 2), substitute a = 2: p(2) = 2^2 - 5(2) + 6 = 4 - 10 + 6 = 0. Since p(2) = 0, (x - 2) is a factor of x^2 - 5x + 6.
(x - a) is a factor of p(x) if p(a) = 0
- •(x - a) is a factor if p(a) = 0
- •Test x - 2: put a = 2
- •p(2) = 4 - 10 + 6 = 0
- •So (x - 2) is a factor
Why learn this
It quickly tests whether a given linear expression divides a polynomial exactly.
💡 Memory trick
If p(a) = 0, then (x - a) is a factor - a is a zero of the polynomial.
MathematicsPolynomialsmediumExpand (x + 2y + 3z)^2 using a standard identity.
Reveal answer ↓
What it is
The identity (a + b + c)^2 = a^2 + b^2 + c^2 + 2ab + 2bc + 2ca expands the square of a trinomial.
Answer
Using (a + b + c)^2 = a^2 + b^2 + c^2 + 2ab + 2bc + 2ca with a = x, b = 2y and c = 3z: = x^2 + (2y)^2 + (3z)^2 + 2(x)(2y) + 2(2y)(3z) + 2(3z)(x) = x^2 + 4y^2 + 9z^2 + 4xy + 12yz + 6zx.
(a + b + c)^2 = a^2 + b^2 + c^2 + 2ab + 2bc + 2ca
- •(a+b+c)^2 = a^2+b^2+c^2+2ab+2bc+2ca
- •Square each term
- •Add twice each pair product
- •Answer: x^2 + 4y^2 + 9z^2 + 4xy + 12yz + 6zx
Why learn this
It speeds up expansion and appears in many algebra questions.
💡 Memory trick
Square each term, then add twice each pair product (ab, bc, ca).
MathematicsCoordinate GeometryeasyIn which quadrant do the points (3, -4) and (-2, 5) lie?
Reveal answer ↓
What it is
The Cartesian plane is formed by two perpendicular axes and is divided into four quadrants.
Answer
On the Cartesian plane, the x-axis and y-axis meet at the origin and divide the plane into four quadrants. In a point (x, y): the first quadrant has both coordinates positive, the second has x negative and y positive, the third has both negative, and the fourth has x positive and y negative. The point (3, -4) has x positive and y negative, so it lies in the fourth quadrant. The point (-2, 5) has x negative and y positive, so it lies in the second quadrant.
A point is written as (x, y)
- •Two perpendicular axes meet at the origin
- •Quadrant signs: I(+,+), II(-,+), III(-,-), IV(+,-)
- •(3, -4) is in quadrant IV
- •(-2, 5) is in quadrant II
Why learn this
It lets us locate any point using an ordered pair of coordinates.
💡 Memory trick
Signs by quadrant: I (+,+), II (-,+), III (-,-), IV (+,-), going anticlockwise.
MathematicsLinear Equations in Two VariablesmediumHow many solutions does a linear equation in two variables have? Find two solutions of x + y = 5.
Reveal answer ↓
What it is
A linear equation in two variables has infinitely many solutions, which lie on a straight line when graphed.
Answer
A linear equation in two variables of the form ax + by + c = 0 has infinitely many solutions, and all of them lie on a straight line when plotted on a graph. For x + y = 5, we can choose values of x and find y: if x = 0, then y = 5, giving (0, 5); if x = 2, then y = 3, giving (2, 3). So (0, 5) and (2, 3) are two of its infinitely many solutions.
ax + by + c = 0
- •Form ax + by + c = 0
- •Infinitely many solutions
- •Graph is a straight line
- •Solutions of x + y = 5: (0,5), (2,3), ...
Why learn this
It models relationships between two quantities, such as cost and number of items.
💡 Memory trick
Pick any x, solve for y - each pair (x, y) is one point on the line.
MathematicsLines and AngleseasyDefine a linear pair and vertically opposite angles.
Reveal answer ↓
What it is
When lines meet, they form angle pairs such as linear pairs (sum 180) and vertically opposite angles (equal).
Answer
A linear pair is a pair of adjacent angles formed when two lines intersect (or a ray stands on a line) such that their non-common arms form a straight line; the sum of a linear pair is 180 degrees. Vertically opposite angles are the pairs of opposite angles formed when two lines intersect; vertically opposite angles are always equal. For example, if two lines cross and one angle is 70 degrees, the angle opposite it is also 70 degrees, and its linear pair is 110 degrees.
Linear pair sum = 180 degrees
- •Linear pair: adjacent angles summing to 180 degrees
- •Vertically opposite angles are equal
- •Formed when two lines intersect
- •Used to find unknown angles
Why learn this
These relationships let us find unknown angles in figures.
💡 Memory trick
Linear pair sums to 180 degrees; vertically opposite angles are equal.
MathematicsLines and AnglesmediumState the angle relationships when a transversal cuts two parallel lines.
Reveal answer ↓
What it is
A transversal cutting two parallel lines makes equal corresponding angles, equal alternate angles and co-interior angles that sum to 180.
Answer
When a transversal intersects two parallel lines, the following angle relationships hold: corresponding angles are equal; alternate interior angles are equal; alternate exterior angles are equal; and co-interior (allied or same-side interior) angles are supplementary, that is, they add up to 180 degrees. These properties can be used both to find unknown angles and to prove that two lines are parallel.
Co-interior angles sum = 180 degrees
- •Corresponding angles are equal
- •Alternate interior angles are equal
- •Co-interior angles sum to 180 degrees
- •Used to prove lines are parallel
Why learn this
These angle rules are used to prove lines parallel and to find angles.
💡 Memory trick
Corresponding equal, Alternate equal, Co-interior sum to 180 (C-shape adds to 180).
MathematicsTriangleseasyTwo interior angles of a triangle are 50 and 60 degrees. Find the third angle and the exterior angle at the third vertex.
Reveal answer ↓
What it is
The interior angles of a triangle sum to 180 degrees, and an exterior angle equals the sum of the two opposite interior angles.
Answer
By the angle sum property, the three interior angles add to 180 degrees, so the third angle = 180 - (50 + 60) = 180 - 110 = 70 degrees. By the exterior angle property, the exterior angle at the third vertex equals the sum of the two opposite interior angles = 50 + 60 = 110 degrees (which is also 180 - 70).
Angle sum = 180 degrees ; exterior angle = sum of two opposite interior angles
- •Interior angles of a triangle sum to 180 degrees
- •Third angle = 180 - 110 = 70 degrees
- •Exterior angle = sum of opposite interior angles
- •Exterior angle = 50 + 60 = 110 degrees
Why learn this
These are the most-used rules for finding angles in triangles.
💡 Memory trick
Exterior angle = sum of the two remote (opposite) interior angles.
MathematicsTrianglesmediumState the criteria for the congruence of two triangles.
Reveal answer ↓
What it is
Two triangles are congruent if they satisfy SSS, SAS, ASA, AAS or RHS.
Answer
Two triangles are congruent (equal in all respects) if any one of the following holds: SSS, when the three sides of one equal the three sides of the other; SAS, when two sides and the included angle are equal; ASA, when two angles and the included side are equal; AAS, when two angles and a non-included side are equal; and RHS, when in two right triangles the hypotenuse and one side are equal. Note that there is no SSA/ASS congruence rule.
Congruence: SSS, SAS, ASA, AAS, RHS
- •SSS: three sides equal
- •SAS: two sides and included angle
- •ASA / AAS: two angles and a side
- •RHS: right angle, hypotenuse and one side
Why learn this
Congruence lets us prove sides and angles equal in geometry.
💡 Memory trick
SSS, SAS, ASA, AAS, RHS - note there is NO ASS/SSA rule.
MathematicsTrianglesmediumState the two key properties of an isosceles triangle.
Reveal answer ↓
What it is
In an isosceles triangle the angles opposite the equal sides are equal, and vice versa.
Answer
An isosceles triangle has two sides equal. Its key properties are: the angles opposite the two equal sides are equal (the base angles are equal); and conversely, if two angles of a triangle are equal, then the sides opposite them are equal, so the triangle is isosceles. Also, the perpendicular drawn from the vertex angle to the base bisects the base and the vertex angle.
Angles opposite equal sides are equal
- •Two sides are equal
- •Angles opposite equal sides are equal
- •Equal angles imply equal opposite sides
- •Vertex perpendicular bisects the base
Why learn this
It is a frequently used result in geometry proofs and angle problems.
💡 Memory trick
Equal sides -> equal base angles (and the reverse is also true).
MathematicsQuadrilateralsmediumState any three properties of a parallelogram.
Reveal answer ↓
What it is
In a parallelogram opposite sides and opposite angles are equal, and the diagonals bisect each other.
Answer
Three properties of a parallelogram are: opposite sides are equal and parallel; opposite angles are equal; and the diagonals bisect each other. A further property is that each diagonal divides the parallelogram into two congruent triangles, and any pair of adjacent angles is supplementary (sums to 180 degrees).
Diagonals of a parallelogram bisect each other
- •Opposite sides equal and parallel
- •Opposite angles equal
- •Diagonals bisect each other
- •A diagonal makes two congruent triangles
Why learn this
These properties are used to prove figures are parallelograms and to solve problems.
💡 Memory trick
Opposite sides equal, opposite angles equal, diagonals bisect each other.
MathematicsQuadrilateralsmediumState the midpoint theorem. If the third side of a triangle is 10 cm, how long is the segment joining the midpoints of the other two sides?
Reveal answer ↓
What it is
The line segment joining the midpoints of two sides of a triangle is parallel to the third side and half its length.
Answer
The midpoint theorem states that the line segment joining the midpoints of any two sides of a triangle is parallel to the third side and is equal to half of it. If the third side is 10 cm, then the segment joining the midpoints of the other two sides is parallel to it and its length is 10 / 2 = 5 cm.
Midsegment = (1/2) x third side
- •Joins midpoints of two sides
- •Parallel to the third side
- •Length = half of the third side
- •Half of 10 cm = 5 cm
Why learn this
It is used to prove parallelism and to find lengths in triangles.
💡 Memory trick
Join two midpoints -> the segment is parallel to and half the third side.
MathematicsCirclesmediumState two properties relating the centre of a circle to its chords.
Reveal answer ↓
What it is
The perpendicular from the centre of a circle to a chord bisects the chord, and equal chords are equidistant from the centre.
Answer
Two important chord properties are: the perpendicular drawn from the centre of a circle to a chord bisects the chord (and conversely, the line from the centre to the midpoint of a chord is perpendicular to it); and equal chords of a circle are equidistant from the centre (and chords that are equidistant from the centre are equal). These follow from the fact that all radii of a circle are equal.
Perpendicular from centre bisects the chord
- •Perpendicular from centre bisects a chord
- •Line from centre to a chord's midpoint is perpendicular
- •Equal chords are equidistant from the centre
- •Equidistant chords are equal
Why learn this
These chord properties are used to find lengths and prove results in circles.
💡 Memory trick
Perpendicular from the centre cuts a chord in half; equal chords are equally far from the centre.
MathematicsCircleshardState the angle-at-centre theorem and the property of a cyclic quadrilateral.
Reveal answer ↓
What it is
The angle at the centre is twice the angle at the circumference on the same arc, and opposite angles of a cyclic quadrilateral sum to 180 degrees.
Answer
The angle subtended by an arc at the centre of a circle is double the angle subtended by the same arc at any point on the remaining part of the circumference. A consequence is that angles in the same segment are equal, and the angle in a semicircle is a right angle. In a cyclic quadrilateral (one whose four vertices lie on a circle), the sum of each pair of opposite angles is 180 degrees, that is, the opposite angles are supplementary.
Angle at centre = 2 x angle at circumference
- •Angle at centre = 2 x angle at circumference (same arc)
- •Angles in the same segment are equal
- •Angle in a semicircle = 90 degrees
- •Cyclic quadrilateral: opposite angles sum to 180 degrees
Why learn this
These theorems solve a large number of circle geometry problems.
💡 Memory trick
Centre angle = 2 x circumference angle; cyclic quadrilateral opposite angles = 180.
MathematicsHeron's FormulamediumFind the area of a triangle whose sides are 3 cm, 4 cm and 5 cm using Heron's formula.
Reveal answer ↓
What it is
Heron's formula finds the area of a triangle from the lengths of its three sides.
Answer
First find the semi-perimeter s = (a + b + c)/2 = (3 + 4 + 5)/2 = 12/2 = 6 cm. Then area = sqrt(s(s - a)(s - b)(s - c)) = sqrt(6(6 - 3)(6 - 4)(6 - 5)) = sqrt(6 x 3 x 2 x 1) = sqrt(36) = 6 cm^2. So the area of the triangle is 6 square centimetres.
Area = sqrt(s(s-a)(s-b)(s-c)), s = (a+b+c)/2
- •s = (a + b + c)/2 = 6
- •Area = sqrt(s(s-a)(s-b)(s-c))
- •sqrt(6 x 3 x 2 x 1) = sqrt(36)
- •Area = 6 cm^2
Why learn this
It works even when the height of the triangle is not known.
💡 Memory trick
Find s = (a+b+c)/2, then area = sqrt(s(s-a)(s-b)(s-c)).
MathematicsSurface Areas and VolumesmediumFind the volume of a cone of radius 3 cm and height 7 cm. (Take pi = 22/7.)
Reveal answer ↓
What it is
A cone has curved surface area pi r l and volume (1/3) pi r^2 h.
Answer
Volume of a cone = (1/3) pi r^2 h = (1/3) x (22/7) x 3^2 x 7 = (1/3) x (22/7) x 9 x 7 = (1/3) x 22 x 9 = (1/3) x 198 = 66 cm^3. So the volume of the cone is 66 cubic centimetres.
Volume of cone = (1/3) pi r^2 h ; CSA = pi r l
- •Volume of cone = (1/3) pi r^2 h
- •= (1/3)(22/7)(9)(7)
- •= 66 cm^3
- •Slant height l = sqrt(r^2 + h^2)
Why learn this
It is used for ice-cream cones, funnels and conical tents.
💡 Memory trick
Cone volume is one-third of a cylinder of the same base and height.
MathematicsSurface Areas and VolumesmediumFind the surface area of a sphere of radius 7 cm. (Take pi = 22/7.)
Reveal answer ↓
What it is
A sphere has surface area 4 pi r^2 and volume (4/3) pi r^3.
Answer
Surface area of a sphere = 4 pi r^2 = 4 x (22/7) x 7^2 = 4 x (22/7) x 49 = 4 x 22 x 7 = 616 cm^2. So the surface area of the sphere is 616 square centimetres.
Surface area = 4 pi r^2 ; Volume = (4/3) pi r^3
- •Surface area of sphere = 4 pi r^2
- •= 4 x (22/7) x 49
- •= 616 cm^2
- •Volume of sphere = (4/3) pi r^3
Why learn this
It is used for balls, globes and bubbles.
💡 Memory trick
Sphere surface = 4 pi r^2; volume = (4/3) pi r^3.
MathematicsSurface Areas and VolumesmediumFind the total surface area of a closed cylinder of radius 7 cm and height 10 cm. (Take pi = 22/7.)
Reveal answer ↓
What it is
A cylinder has curved surface area 2 pi r h and total surface area 2 pi r (r + h).
Answer
Total surface area of a closed cylinder = 2 pi r (r + h) = 2 x (22/7) x 7 x (7 + 10) = 2 x 22 x 17 = 748 cm^2. So the total surface area of the cylinder is 748 square centimetres.
TSA of cylinder = 2 pi r (r + h)
- •CSA = 2 pi r h
- •TSA = 2 pi r (r + h)
- •= 2 x (22/7) x 7 x 17
- •TSA = 748 cm^2
Why learn this
It is used for pipes, tanks, tins and pillars.
💡 Memory trick
TSA of a closed cylinder = 2 pi r (h + r) (curved surface plus two circles).
MathematicsStatisticseasyFind the mean of the data: 10, 12, 14, 16, 18.
Reveal answer ↓
What it is
The mean (average) is the sum of all observations divided by the number of observations.
Answer
The mean is the sum of all observations divided by the number of observations. Sum = 10 + 12 + 14 + 16 + 18 = 70. Number of observations = 5. Mean = 70 / 5 = 14. So the mean of the data is 14.
Mean = (sum of observations) / (number of observations)
- •Mean = sum / number of observations
- •Sum = 70
- •Number = 5
- •Mean = 14
Why learn this
It is the most common way to represent a set of data by a single value.
💡 Memory trick
Mean = sum of values / number of values.
MathematicsStatisticsmediumFind the median and mode of the data: 4, 6, 6, 8, 10.
Reveal answer ↓
What it is
The median is the middle value of ordered data; the mode is the most frequently occurring value.
Answer
The data is already arranged in ascending order: 4, 6, 6, 8, 10. There are 5 observations (odd number), so the median is the middle (3rd) value, which is 6. The mode is the value that occurs most often; here 6 occurs twice while all others occur once, so the mode is 6. Thus both the median and the mode are 6.
Median = middle value (for odd n) ; Mode = most frequent value
- •Arrange data in order first
- •Median = middle value (odd count)
- •Median = 6
- •Mode = most frequent value = 6
Why learn this
The median resists extreme values and the mode shows the most common item.
💡 Memory trick
Median = MIDdle of sorted data; Mode = MOST frequent value.
MathematicsProbabilityeasyA coin is tossed 100 times and a head appears 60 times. Find the empirical probability of getting a head.
Reveal answer ↓
What it is
Empirical (experimental) probability is the ratio of the number of times an event happens to the total number of trials.
Answer
Empirical probability of an event = (number of times the event occurs) / (total number of trials). Here a head appeared 60 times out of 100 tosses, so P(head) = 60/100 = 0.6. The probability of any event lies between 0 and 1, and the probabilities of all outcomes add up to 1.
P(E) = number of favourable trials / total trials
- •P(event) = favourable outcomes / total trials
- •P(head) = 60/100
- •= 0.6
- •Probability lies between 0 and 1
Why learn this
It estimates chances from real observed data, like coin tosses.
💡 Memory trick
P(event) = favourable outcomes / total trials, a value between 0 and 1.
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