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For Class 8, 9 & 10

Foundation - a strong base in Physics, Chemistry, Maths & Biology

Concept-first questions with clear model answers across all four subjects, aligned to NCERT. Start early, build the habit, and walk into your board exams, NEET and JEE already ahead.

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SubjectAllPhysics 19Chemistry 19Biology 19Mathematics 27
ChapterAllAcids, Bases and SaltsArithmetic ProgressionsCarbon and its CompoundsChemical Reactions and EquationsCirclesControl and CoordinationCoordinate GeometryElectricityHeredity and EvolutionHow do Organisms ReproduceIntroduction to TrigonometryLife ProcessesLight - Reflection and RefractionMagnetic Effects of Electric CurrentMetals and Non-metalsOur EnvironmentPair of Linear Equations in Two VariablesPolynomialsProbabilityQuadratic EquationsReal NumbersSome Applications of TrigonometryStatisticsSurface Areas and VolumesThe Human Eye and the Colourful WorldTriangles

Showing 1 question for Class 10. Tap a card to reveal the answer.

MathematicsSurface Areas and Volumeseasy

Find the volume of a cone whose base radius is 3 cm and height is 4 cm. (Take pi = 22/7.)

Reveal answer ↓

What it is

A cone's volume is exactly one-third of a cylinder with the same base and height.

Answer

Volume of a cone = (1/3) x pi x r^2 x h = (1/3) x (22/7) x 3^2 x 4 = (1/3) x (22/7) x 36 = (22 x 12) / 7 = 264/7, which is about 37.7 cubic cm.

V(cone) = (1/3) pi r^2 h

  • •V = (1/3) pi r^2 h
  • •= (1/3)(22/7)(9)(4)
  • •= 264/7 = about 37.7 cm^3

Why learn this

It's how we measure ice-cream cones, funnels, heaps of grain and tent capacity.

💡 Memory trick

Cone = 1/3 x pi r^2 h - a cone is a third of its cylinder.